EBK ORGANIC CHEMISTRY-PRINT COMPANION (
EBK ORGANIC CHEMISTRY-PRINT COMPANION (
4th Edition
ISBN: 9781119776741
Author: Klein
Publisher: WILEY CONS
Question
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Chapter 21, Problem 84PP

(a)

Interpretation Introduction

Interpretation:

Michael donor and Michael acceptor need to be identified for the given set of compounds.

Concept introduction:

When a active methylene is deprotonated to form a carbanion (Michael donor) which acts as a nucleophile for 1,4-conjugate addition to α,β -unsaturated compound (Michael acceptor) is known as Michael addition reaction.  Michael reaction is thermodynamically controlled.  A general scheme is shown below,

EBK ORGANIC CHEMISTRY-PRINT COMPANION (, Chapter 21, Problem 84PP , additional homework tip  1

Please remember that 1,5-difunctionalization is the hallmark of Michael addition reaction.

To Find : To find the Michael donor and Michael acceptor for the given compound.

(b)

Interpretation Introduction

Interpretation:

Michael donor and Michael acceptor need to be identified for the given set of compounds.

Concept introduction:

When a active methylene is deprotonated to form a carbanion (Michael donor) which acts as a nucleophile for 1,4-conjugate addition to α,β -unsaturated compound (Michael acceptor) is known as Michael addition reaction.  Michael reaction is thermodynamically controlled.  A general scheme is shown below,

EBK ORGANIC CHEMISTRY-PRINT COMPANION (, Chapter 21, Problem 84PP , additional homework tip  2

Please remember that 1,5-difunctionalization is the hallmark of Michael addition reaction.

To Find : To find the Michael donor and Michael acceptor for the given compound.

(c)

Interpretation Introduction

Interpretation:

Michael donor and Michael acceptor need to be identified for the given set of compounds.

Concept introduction:

When a active methylene is deprotonated to form a carbanion (Michael donor) which acts as a nucleophile for 1,4-conjugate addition to α,β -unsaturated compound (Michael acceptor) is known as Michael addition reaction.  Michael reaction is thermodynamically controlled.  A general scheme is shown below,

EBK ORGANIC CHEMISTRY-PRINT COMPANION (, Chapter 21, Problem 84PP , additional homework tip  3

Please remember that 1,5-difunctionalization is the hallmark of Michael addition reaction.

To Find : To find the Michael donor and Michael acceptor for the given compound.

(d)

Interpretation Introduction

Interpretation:

Michael donor and Michael acceptor need to be identified for the given set of compounds.

Concept introduction:

When a active methylene is deprotonated to form a carbanion (Michael donor) which acts as a nucleophile for 1,4-conjugate addition to α,β -unsaturated compound (Michael acceptor) is known as Michael addition reaction.  Michael reaction is thermodynamically controlled.  A general scheme is shown below,

EBK ORGANIC CHEMISTRY-PRINT COMPANION (, Chapter 21, Problem 84PP , additional homework tip  4

To Find : To find the Michael donor and Michael acceptor for the given compound.

(e)

Interpretation Introduction

Interpretation:

Michael donor and Michael acceptor need to be identified for the given set of compounds.

Concept introduction:

When a active methylene is deprotonated to form a carbanion (Michael donor) which acts as a nucleophile for 1,4-conjugate addition to α,β -unsaturated compound (Michael acceptor) is known as Michael addition reaction.  Michael reaction is thermodynamically controlled.  A general scheme is shown below,

EBK ORGANIC CHEMISTRY-PRINT COMPANION (, Chapter 21, Problem 84PP , additional homework tip  5

Please remember that 1,5-difunctionalization is the hallmark of Michael addition reaction.

To Find : To find the Michael donor and Michael acceptor for the given compound.

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Chapter 21 Solutions

EBK ORGANIC CHEMISTRY-PRINT COMPANION (

Ch. 21.2 - Prob. 10CCCh. 21.2 - Prob. 11CCCh. 21.2 - Prob. 12CCCh. 21.2 - Prob. 13CCCh. 21.3 - Prob. 2LTSCh. 21.3 - Prob. 14PTSCh. 21.3 - Prob. 15PTSCh. 21.3 - Prob. 3LTSCh. 21.3 - Prob. 4LTSCh. 21.3 - Prob. 19PTSCh. 21.3 - Prob. 21CCCh. 21.3 - Prob. 22CCCh. 21.3 - Prob. 23CCCh. 21.4 - Prob. 24CCCh. 21.4 - Prob. 25CCCh. 21.4 - Prob. 26CCCh. 21.4 - Prob. 27CCCh. 21.4 - Prob. 28CCCh. 21.5 - Prob. 29CCCh. 21.5 - Prob. 30CCCh. 21.5 - Prob. 5LTSCh. 21.5 - Prob. 31PTSCh. 21.5 - Prob. 6LTSCh. 21.5 - Prob. 33PTSCh. 21.5 - Prob. 34ATSCh. 21.6 - Prob. 35CCCh. 21.6 - Prob. 36CCCh. 21.6 - Prob. 37CCCh. 21.6 - Prob. 7LTSCh. 21.6 - Prob. 38PTSCh. 21.7 - Prob. 8LTSCh. 21.7 - Prob. 42PTSCh. 21.7 - Prob. 43PTSCh. 21 - Prob. 47PPCh. 21 - Prob. 48PPCh. 21 - Prob. 49PPCh. 21 - Prob. 50PPCh. 21 - Prob. 51PPCh. 21 - Prob. 52PPCh. 21 - Prob. 53PPCh. 21 - Prob. 54PPCh. 21 - Prob. 55PPCh. 21 - Prob. 56PPCh. 21 - Prob. 57PPCh. 21 - Prob. 58PPCh. 21 - Prob. 59PPCh. 21 - Prob. 60PPCh. 21 - Prob. 61PPCh. 21 - Prob. 62PPCh. 21 - Prob. 63PPCh. 21 - Prob. 64PPCh. 21 - Prob. 65PPCh. 21 - Prob. 66PPCh. 21 - Prob. 67PPCh. 21 - Prob. 68PPCh. 21 - Prob. 69PPCh. 21 - Prob. 70PPCh. 21 - Prob. 71PPCh. 21 - Prob. 72PPCh. 21 - Prob. 73PPCh. 21 - Prob. 74PPCh. 21 - Prob. 75PPCh. 21 - Prob. 76PPCh. 21 - Prob. 77PPCh. 21 - Prob. 78PPCh. 21 - Prob. 79PPCh. 21 - Prob. 80PPCh. 21 - Prob. 81PPCh. 21 - Prob. 82PPCh. 21 - Prob. 83PPCh. 21 - Prob. 84PPCh. 21 - Prob. 85PPCh. 21 - Prob. 86PPCh. 21 - Prob. 87PPCh. 21 - Prob. 88PPCh. 21 - Prob. 97IPCh. 21 - Prob. 98IPCh. 21 - Prob. 99IPCh. 21 - Prob. 100IPCh. 21 - Prob. 101IPCh. 21 - Prob. 107IPCh. 21 - Prob. 108IPCh. 21 - Prob. 109IP
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