To calculate the average O − F bond enthalpy in OF 2 molecule. Concept introduction: The bond dissociation energy is the energy required to break one mole of the gas (in a gaseous state) to give the separate atoms in a gaseous state. The bond dissociation energy is the energy of a single bond while bond energy is the average of the all bond dissociation energies. For the diatomic molecule bond dissociation energy is equal to the bond energy of the molecule. The change of enthalpy to form one mole of a substance from its constituent elements when all the substances in the standard form is known as standard enthalpy of formation. The standard enthalpy of formation ( Δ f H ∘ ) in terms of standard bond dissociation enthalpy ( B ∘ ) is written as, Δ f H ∘ = ∑ B ∘ products − ∑ B ∘ reactants (1)
To calculate the average O − F bond enthalpy in OF 2 molecule. Concept introduction: The bond dissociation energy is the energy required to break one mole of the gas (in a gaseous state) to give the separate atoms in a gaseous state. The bond dissociation energy is the energy of a single bond while bond energy is the average of the all bond dissociation energies. For the diatomic molecule bond dissociation energy is equal to the bond energy of the molecule. The change of enthalpy to form one mole of a substance from its constituent elements when all the substances in the standard form is known as standard enthalpy of formation. The standard enthalpy of formation ( Δ f H ∘ ) in terms of standard bond dissociation enthalpy ( B ∘ ) is written as, Δ f H ∘ = ∑ B ∘ products − ∑ B ∘ reactants (1)
Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.
Chapter 21, Problem 79GQ
Interpretation Introduction
Interpretation:
To calculate the average O−F bond enthalpy in OF2 molecule.
Concept introduction:
The bond dissociation energy is the energy required to break one mole of the gas (in a gaseous state) to give the separate atoms in a gaseous state. The bond dissociation energy is the energy of a single bond while bond energy is the average of the all bond dissociation energies. For the diatomic molecule bond dissociation energy is equal to the bond energy of the molecule.
The change of enthalpy to form one mole of a substance from its constituent elements when all the substances in the standard form is known as standard enthalpy of formation.
The standard enthalpy of formation (ΔfH∘) in terms of standard bond dissociation enthalpy (B∘) is written as,
Given: N2(g) + 3H2(g)2NH3(g)
AG° = 53.8 kJ at 700K. Calculate AG for the above reaction at 700K if the reaction mixture consists of 20.0 atm of N2(g),
30.0 atm of H2(g), and 0.500 atm of NH3(g).
A) -26.9 kJ
B) 31.1 kJ
C) -15.6 kJ
D) 26.9 kJ
E) -25.5 kJ
Explain the structure of the phosphomolybdate anion [PMo12O40]3-.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell