(a)
Interpretation:
To calculate the mass of
Concept introduction:
Ammonium perchlorate upon decomposition gives
The total number of moles of the substance is equal to the mass of the substance divided by the molecular weight of that substance.
The limiting reagent in the
(a)
Answer to Problem 76GQ
The mass of water molecule is produced upon decomposition of ammonium perchlorate is
The mass of oxygen molecule is produced upon decomposition of ammonium perchlorate is
Explanation of Solution
The mass of
Given:
The mass of ammonium perchlorate is
The balanced chemical equation of decomposition of ammonium perchlorate is written as,
The number of moles
From equation (1), two moles of ammonium perchlorate produced four moles of water molecules. Therefore, the number of moles
The mass
Therefore, the mass of water molecule is produced upon decomposition of ammonium perchlorate is
From equation (1), two moles of ammonium perchlorate produced one mole of the oxygen molecule. Therefore, the number of moles
The mass
Therefore, the mass of oxygen molecule is produced upon decomposition of ammonium perchlorate is
(b)
Interpretation:
To calculate the mass of aluminium which is required to use up all of the oxygen to form
Concept introduction:
Ammonium perchlorate upon decomposition gives
The total number of moles of the substance is equal to the mass of the substance divided by the molecular weight of that substance.
The limiting reagent in the chemical reaction is the substance that is totally consumed when the chemical reaction is complete. The amount of product formed is limited by the limiting reagent.
(b)
Answer to Problem 76GQ
The mass of aluminium powder which is required to use up all of the oxygen to form
Explanation of Solution
The mass of aluminium which is required to use up all of the oxygen to form
Given:
The number of moles of oxygen molecule calculated in sub-part (a) is
The balanced chemical equation of the reaction of aluminium with oxygen molecule is written as,
Since the entire oxygen molecule is used to react with the aluminium powder to produce
From equation (2), four moles of aluminium reacted with three moles of the oxygen molecule. Therefore, the number of moles
The mass
Therefore, the mass of aluminium powder which is required to use up all of the oxygen to form
(c)
Interpretation:
To calculate the mass of
Concept introduction:
Ammonium perchlorate upon decomposition gives
The total number of moles of the substance is equal to the mass of the substance divided by the molecular weight of that substance.
The limiting reagent in the chemical reaction is the substance that is totally consumed when the chemical reaction is complete. The amount of product formed is limited by the limiting reagent.
(c)
Answer to Problem 76GQ
The mass of
Explanation of Solution
The mass of
Given:
The mass of aluminium powder which is required to use up all of the oxygen to form
The balanced chemical equation of the reaction of aluminium with oxygen molecule is written as,
Four moles of aluminium produced two moles of
The mass
Therefore, the mass of
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Chapter 21 Solutions
Chemistry & Chemical Reactivity
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