Electric Motor Control
10th Edition
ISBN: 9781305177611
Author: Herman
Publisher: Cengage
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Chapter 21, Problem 5SQ
After the forward coil has been energized, is the auxiliary forward interlocking contact open or closed?
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10.2 For each of the following groups of sources, determineif the three sources constitute a balanced source, and if it is,determine if it has a positive or negative phase sequence.(a) va(t) = 169.7cos(377t +15◦) Vvb(t) = 169.7cos(377t −105◦) Vvc(t) = 169.7sin(377t −135◦) V(b) va(t) = 311cos(wt −12◦) Vvb(t) = 311cos(wt +108◦) Vvc(t) = 311cos(wt +228◦) V(c) V1 = 140 −140◦ VV2 = 114 −20◦ VV3 = 124 100◦ V
Apply single-phase equivalency to determine the linecurrents in the Y-D network shown in Fig. P10.13. The loadimpedances are Zab = Zbc = Zca = (25+ j5) W
10.8 In the network of Fig. P10.8, Za = Zb = Zc = (25+ j5) W.Determine the line currents.
Chapter 21 Solutions
Electric Motor Control
Ch. 21 - How is a change in the direction of rotation of a...Ch. 21 - Prob. 2SQCh. 21 - If a reversing control circuit contains...Ch. 21 - How is auxiliary contact interlocking achieved on...Ch. 21 - After the forward coil has been energized, is the...Ch. 21 - If a mechanical interlock is the only means of...Ch. 21 - If pilot lights are to indicate which coil is...Ch. 21 - What is the sequence of the operations if the...Ch. 21 - In place of the push buttons in Figure 214, draw a...Ch. 21 - From the elementary drawing in Figure 2110,...
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- Using D flip-flops, design a synchronous counter. The counter counts in the sequence 1,3,5,7, 1,7,5,3,1,3,5,7,.... when its enable input x is equal to 1; otherwise, the counter count 0. Present state Next state x=0 Next state x=1 Output SO 52 S1 1 S1 54 53 3 52 53 S2 56 51 0 $5 5 54 S4 53 0 55 58 57 7 56 56 55 0 57 S10 59 1 58 58 S7 0 59 S12 S11 7 $10 $10 59 0 $11 $14 $13 5 $12 S12 $11 0 513 $15 SO 3 S14 $14 S13 0 $15 515 SO 0 Explain how to get the table step by step with drawing the state diagram and finding the Karnaugh map.arrow_forwardFor the oscillator resonance circuit shown in Fig. (5), derive the oscillation frequency Feedback and open-loop gains. L₁ 5 mH (a) ell +10 V R₁ ww R3 S C2 HH 1 με 1000 pF 100 pF R₂ 1 με RA H (b) +9 V R4 CA 470 pF C₁ R3 HH 1 με R₁ ww L₁ 000 1.5 mH R₂ ww Hi 1 μF L2 m 10 mHarrow_forwardExpert handwritten solution onlyarrow_forward
- B. For the oscillator circuit shown in frequency, feedback and open-loop gains. +10 V name the circuit, derive and find the oscillation P.Av +9 V -000 4₁ 5 mH w R₁ C₂ HH 1 με w 100 pF R₂ T R CA www. 470 pF w ww www 1000 pF HH 1μF C₁ HH 1μF Ra ww HI 4₁ 000 1.5 mH H 4 AF 000 10 mHarrow_forwardI want to check if the current that I have from using the mesh analysis is correct? I1 = 0.214mA I2 = -0.429mAarrow_forwardI want to find the current by using mesh analysis pleasearrow_forward
- I want to find the current by using mesh analysis pleasearrow_forwardR₁ W +10 V R3 +9 V C₂ R₁ CA C₁ 470 pF HH 1000 pF HH 1 με C4 1 μF 1 uF C₁ R₂ R4 100 pF Find Open-loop Jain L₁ 5 mH (a) Av=S,B={" H R₁₂ ✓ ww (b) R₁ L₁ 000 1.5 mH R₂ H 1 uF 12 10 mHarrow_forwardA) Calculate the efficiency of the test transformer at the resistive loads (X-25%, 50%, 75%, 100%, 125% full load). B) From part (A) draw the plot (efficiency Vs power output) of the transformer. C) Discuss the plot of part (B).arrow_forward
- a- Determine fH; and Ho b- Find fg and fr. c- Sketch the frequency response for the high-frequency region using a Bode plot and determine the cutoff frequency. Ans: 277.89 KHz; 2.73 MHz; 895.56 KHz; 107.47 MHz. 14V Cw=5pF Cwo-8pF Coc-12 pF 5.6kQ Ch. 40. pF C-8pF 68kQ 0.47µF Vo 0.82 kQ V₁ B=120 0.47µF www 3.3kQ 10kQ 1.2kQ =20µF Narrow_forwardUsing D flip-flops, design a synchronous counter. The counter counts in the sequence 1,3,5,7, 1,7,5,3,1,3,5,7,.... when its enable input x is equal to 1; otherwise, the counter. This counter is for individual settings only need the state diagram and need the state table to use 16 states from So to S15.arrow_forward: A sequential network has one input (X) and two outputs (Z1 and Z2). An output Z1 Z2 = 10 occurs every time the input sequence 1011 is completed. An output Z1 Z2 = 01 occurs every time the input sequence 0101 is completed. Otherwise Z1 Z2 = 0 Find Moore state diagram with minimum number of states: a) When overlap is allowed. b) When overlap is not allowed. I need a step by step printable solution that uses sequences on the same drawing.arrow_forward
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