
Electric Motor Control
10th Edition
ISBN: 9781305177611
Author: Herman
Publisher: Cengage
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Textbook Question
Chapter 21, Problem 12SQ
Convert the control circuit only, Figure 21–11, from the wiring diagram to an elementary diagram. Include the limit switches (RLS, FLS) as operating in the control circuit.
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-E1 + VR1 + VR4 – E2 + VR3 = 0 -------> Loop 1 (a)
R1(I1) + R4(I1 – I2) + R3(I1) = E1 + E2 ------> Loop 1 (b)
R1(I1) + R4(I1) - R4(I2) + R3(I1) = E1 + E2 ------> Loop 1 (c)
(R1 + R3 + R4) (I1) - R4(I2) = E1 + E2 ------> Loop 1 (d)
Now that we have loop 1 equation will procced on finding the equation of I2 current loop. However, a reminder that because we are going in a clockwise direction, it goes against the direction of the current. As such we will get an equation for the matrix that will be:
E2 – VR4 – VR2 + E3 = 0 ------> Loop 2 (a)
-R4(I2 – I1) -R2(I2) = -E2 – E3 ------> Loop 2 (b)
-R4(I2) + R4(I1) - R2(I2) = -E2 – E3 -----> Loop 2 (c)
R4(I1) – (R4 + R2)(I2) = -E2 – E3 -----> Loop 2 (d)
These two equations will be implemented to the matrix formula I = inv(A) * b
R11 R12
(R1 + R3 + R4)
-R4
-R4
R4 + R2
10.2 For each of the following groups of sources, determineif the three sources constitute a balanced source, and if it is,determine if it has a positive or negative phase sequence.(a) va(t) = 169.7cos(377t +15◦) Vvb(t) = 169.7cos(377t −105◦) Vvc(t) = 169.7sin(377t −135◦) V(b) va(t) = 311cos(wt −12◦) Vvb(t) = 311cos(wt +108◦) Vvc(t) = 311cos(wt +228◦) V(c) V1 = 140 −140◦ VV2 = 114 −20◦ VV3 = 124 100◦ V
Apply single-phase equivalency to determine the linecurrents in the Y-D network shown in Fig. P10.13. The loadimpedances are Zab = Zbc = Zca = (25+ j5) W
Chapter 21 Solutions
Electric Motor Control
Ch. 21 - How is a change in the direction of rotation of a...Ch. 21 - Prob. 2SQCh. 21 - If a reversing control circuit contains...Ch. 21 - How is auxiliary contact interlocking achieved on...Ch. 21 - After the forward coil has been energized, is the...Ch. 21 - If a mechanical interlock is the only means of...Ch. 21 - If pilot lights are to indicate which coil is...Ch. 21 - What is the sequence of the operations if the...Ch. 21 - In place of the push buttons in Figure 214, draw a...Ch. 21 - From the elementary drawing in Figure 2110,...
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- 10.8 In the network of Fig. P10.8, Za = Zb = Zc = (25+ j5) W.Determine the line currents.arrow_forwardUsing D flip-flops, design a synchronous counter. The counter counts in the sequence 1,3,5,7, 1,7,5,3,1,3,5,7,.... when its enable input x is equal to 1; otherwise, the counter count 0. Present state Next state x=0 Next state x=1 Output SO 52 S1 1 S1 54 53 3 52 53 S2 56 51 0 $5 5 54 S4 53 0 55 58 57 7 56 56 55 0 57 S10 59 1 58 58 S7 0 59 S12 S11 7 $10 $10 59 0 $11 $14 $13 5 $12 S12 $11 0 513 $15 SO 3 S14 $14 S13 0 $15 515 SO 0 Explain how to get the table step by step with drawing the state diagram and finding the Karnaugh map.arrow_forwardFor the oscillator resonance circuit shown in Fig. (5), derive the oscillation frequency Feedback and open-loop gains. L₁ 5 mH (a) ell +10 V R₁ ww R3 S C2 HH 1 με 1000 pF 100 pF R₂ 1 με RA H (b) +9 V R4 CA 470 pF C₁ R3 HH 1 με R₁ ww L₁ 000 1.5 mH R₂ ww Hi 1 μF L2 m 10 mHarrow_forward
- Expert handwritten solution onlyarrow_forwardB. For the oscillator circuit shown in frequency, feedback and open-loop gains. +10 V name the circuit, derive and find the oscillation P.Av +9 V -000 4₁ 5 mH w R₁ C₂ HH 1 με w 100 pF R₂ T R CA www. 470 pF w ww www 1000 pF HH 1μF C₁ HH 1μF Ra ww HI 4₁ 000 1.5 mH H 4 AF 000 10 mHarrow_forwardI want to check if the current that I have from using the mesh analysis is correct? I1 = 0.214mA I2 = -0.429mAarrow_forward
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- A) Calculate the efficiency of the test transformer at the resistive loads (X-25%, 50%, 75%, 100%, 125% full load). B) From part (A) draw the plot (efficiency Vs power output) of the transformer. C) Discuss the plot of part (B).arrow_forwarda- Determine fH; and Ho b- Find fg and fr. c- Sketch the frequency response for the high-frequency region using a Bode plot and determine the cutoff frequency. Ans: 277.89 KHz; 2.73 MHz; 895.56 KHz; 107.47 MHz. 14V Cw=5pF Cwo-8pF Coc-12 pF 5.6kQ Ch. 40. pF C-8pF 68kQ 0.47µF Vo 0.82 kQ V₁ B=120 0.47µF www 3.3kQ 10kQ 1.2kQ =20µF Narrow_forwardUsing D flip-flops, design a synchronous counter. The counter counts in the sequence 1,3,5,7, 1,7,5,3,1,3,5,7,.... when its enable input x is equal to 1; otherwise, the counter. This counter is for individual settings only need the state diagram and need the state table to use 16 states from So to S15.arrow_forward
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