Chapter 21, Problem 37QAP

Iodine can be prepared by allowing an aqueous solution of hydrogen iodide to react with manganese dioxide, MnO₂. The reaction is
$2{\text{I}}^{-}\left(aq\right)+4{\text{H}}^{+}\left(aq\right)+{\text{MnO}}_2\left(s\right)\to {\text{Mn}}^{2+}\left(aq\right)+2{\text{H}}_2\text{O}+{\text{I}}_2\left(s\right)$
If an excess of hydrogen iodide is added to 0.200 g of MnO₂, how many grams of iodine are obtained, assuming 100% yield?