Chapter 2.1, Problem 2QR

To determine

Tofind: The value of $f\left(2\right)$ for $f\left(x\right)=\frac{4x^2-5}{x^3+4}$ .

Answer to Problem 2QR

The value of $f\left(2\right)$ for $f\left(x\right)=\frac{4x^2-5}{x^3+4}$ is $\frac{11}{12}$ .

Explanation of Solution

Given information:

The function is $f\left(x\right)=\frac{4x^2-5}{x^3+4}$ .

Calculation:

Substitute $2$ for $x$ in the given function.

  $\begin{array}{c}f\left(2\right)=\frac{4\times 2^2-5}{2^3+4}\\ f\left(2\right)=\frac{16-5}{8+4}\\ f\left(2\right)=\frac{11}{12}\end{array}$

Therefore, the value of $f\left(2\right)$ for $f\left(x\right)=\frac{4x^2-5}{x^3+4}$ is $\frac{11}{12}$ .