Chapter 2.1, Problem 18E

(a)

To determine

To find: Complete the table given below for $f\left(x\right)=\sin \left(\frac{1}{x}\right)$ and also estimate the value of $\underset{x\to 0}{\lim }f\left(x\right)$ :

$x$	$-0.1$	$-0.01$	$-0.001$	$-0.0001$
$f\left(x\right)$	$?$	$?$	$?$	$?$

Answer to Problem 18E

The value of the $\underset{x\to 0}{\lim }f\left(x\right)$ doesn’t exist and the complete table is given below:

$x$	$-0.1$	$-0.01$	$-0.001$	$-0.0001$
$f\left(x\right)$	$0.5440$	$0.5063$	$-0.8268$	$0.3056$

Explanation of Solution

Given information:

The function is $f\left(x\right)=\sin \left(\frac{1}{x}\right)$ .

Calculation:

Substitute $-0.1$ for $x$ in the given function.

  $\begin{array}{c}f\left(x\right)=\sin \left(\frac{1}{x}\right)\\ f\left(-0.1\right)=\sin \left(-\frac{1}{0.1}\right)\\ f\left(-0.1\right)=\sin \left(-10\right)\end{array}$

To find the value of $\sin \left(-10\right)$ with the help of calculator press “ON” button and enter the keystrokes as given below:

  $\boxed{\text{SIN}}\boxed{(-)}\boxed{10}\boxed{)}$

The value of $\sin \left(-10\right)$ using a calculator is approximately $0.5440$ .

So, the value of $f\left(x\right)$ at $x=-0.1$ is $0.5440$ .

Substitute $-0.01$ for $x$ in the given function.

  $\begin{array}{c}f\left(x\right)=\sin \left(\frac{1}{x}\right)\\ f\left(-0.01\right)=\sin \left(-\frac{1}{0.01}\right)\\ f\left(-0.01\right)=\sin \left(-100\right)\end{array}$

To find the value of $\sin \left(-100\right)$ with the help of calculator press “ON” button and enter the keystrokes as given below:

  $\boxed{\text{SIN}}\boxed{(-)}\boxed{100}\boxed{)}$

The value of $\sin \left(-100\right)$ using a calculator is approximately $0.5063$ .

So, the value of $f\left(x\right)$ at $x=-0.01$ is $0.5063$ .

Substitute $-0.001$ for $x$ in the given function.

  $\begin{array}{c}f\left(x\right)=x\sin \left(\frac{1}{x}\right)\\ f\left(-0.001\right)=\sin \left(-\frac{1}{0.001}\right)\\ f\left(-0.001\right)=\sin \left(-1000\right)\end{array}$

To find the value of $\sin \left(-1000\right)$ with the help of calculator press “ON” button and enter the keystrokes as given below:

  $\boxed{\text{SIN}}\boxed{(-)}\boxed{1000}\boxed{)}$

The value of $\sin \left(-1000\right)$ using a calculator is approximately $-0.8268$ .

So, the value of $f\left(x\right)$ at $x=-0.001$ is $-0.8268$ .

Substitute $-0.0001$ for $x$ in the given function.

  $\begin{array}{c}f\left(x\right)=x\sin \left(\frac{1}{x}\right)\\ f\left(-0.0001\right)=\sin \left(-\frac{1}{0.0001}\right)\\ f\left(-0.0001\right)=\sin \left(-10000\right)\end{array}$

To find the value of $\sin \left(-10000\right)$ with the help of calculator press “ON” button and enter the keystrokes as given below:

  $\boxed{\text{SIN}}\boxed{(-)}\boxed{10000}\boxed{)}$

The value of $\sin \left(-10000\right)$ using a calculator is approximately $0.3056$ .

So, the value of $f\left(x\right)$ at $x=-0.0001$ is $0.3056$ .

Therefore, the complete table is given by:

$x$	$-0.1$	$-0.01$	$-0.001$	$-0.0001$
$f\left(x\right)$	$0.5440$	$0.5063$	$-0.8268$	$0.3056$

The value of the function is not possible to find when $x$ tends to $0$ as the values of function are oscillates with decrease in $x$ .

Therefore, The value of the $\underset{x\to 0}{\lim }f\left(x\right)$ doesn’t exist.

(b)

To determine

To find: Complete the table given below for $f\left(x\right)=\sin \left(\frac{1}{x}\right)$ and also estimate the value of $\underset{x\to 0}{\lim }f\left(x\right)$ :

$x$	$0.1$	$0.01$	$0.001$	$0.0001$
$f\left(x\right)$	$?$	$?$	$?$	$?$

Answer to Problem 18E

The value of the $\underset{x\to 0}{\lim }f\left(x\right)$ doesn’t exist and the complete table is given below:

$x$	$0.1$	$0.01$	$0.001$	$0.0001$
$f\left(x\right)$	$-0.5440$	$-0.5063$	$0.8268$	$-0.3056$

Explanation of Solution

Given information:

The function is $f\left(x\right)=\sin \left(\frac{1}{x}\right)$ .

Calculation:

Substitute $0.1$ for $x$ in the given function.

  $\begin{array}{c}f\left(x\right)=\sin \left(\frac{1}{x}\right)\\ f\left(0.1\right)=\sin \left(\frac{1}{0.1}\right)\\ f\left(0.1\right)=\sin \left(10\right)\end{array}$

To find the value of $\sin \left(10\right)$ with the help of calculator press “ON” button and enter the keystrokes as given below:

  $\boxed{\text{SIN}}\boxed{10}\boxed{)}$

The value of $\sin \left(10\right)$ using a calculator is approximately $-0.5440$ .

So, the value of $f\left(x\right)$ at $x=0.1$ is $-0.5440$ .

Substitute $0.01$ for $x$ in the given function.

  $\begin{array}{c}f\left(x\right)=\sin \left(\frac{1}{x}\right)\\ f\left(0.01\right)=\sin \left(\frac{1}{0.01}\right)\\ f\left(0.01\right)=\sin \left(100\right)\end{array}$

To find the value of $\sin \left(100\right)$ with the help of calculator press “ON” button and enter the keystrokes as given below:

  $\boxed{\text{SIN}}\boxed{100}\boxed{)}$

The value of $\sin \left(100\right)$ using a calculator is approximately $-0.5063$ .

So, the value of $f\left(x\right)$ at $x=0.01$ is $-0.5063$ .

Substitute $0.001$ for $x$ in the given function.

  $\begin{array}{c}f\left(x\right)=x\sin \left(\frac{1}{x}\right)\\ f\left(0.001\right)=\sin \left(\frac{1}{0.001}\right)\\ f\left(0.001\right)=\sin \left(1000\right)\end{array}$

To find the value of $\sin \left(1000\right)$ with the help of calculator press “ON” button and enter the keystrokes as given below:

  $\boxed{\text{SIN}}\boxed{1000}\boxed{)}$

The value of $\sin \left(1000\right)$ using a calculator is approximately $0.8268$ .

So, the value of $f\left(x\right)$ at $x=0.001$ is $0.8268$ .

Substitute $0.0001$ for $x$ in the given function.

  $\begin{array}{c}f\left(x\right)=x\sin \left(\frac{1}{x}\right)\\ f\left(0.0001\right)=\sin \left(\frac{1}{0.0001}\right)\\ f\left(0.0001\right)=\sin \left(10000\right)\end{array}$

To find the value of $\sin \left(10000\right)$ with the help of calculator press “ON” button and enter the keystrokes as given below:

  $\boxed{\text{SIN}}\boxed{10000}\boxed{)}$

The value of $\sin \left(10000\right)$ using a calculator is approximately $-0.3056$ .

So, the value of $f\left(x\right)$ at $x=0.0001$ is $-0.3056$ .

Therefore, the complete table is given by:

$x$	$0.1$	$0.01$	$0.001$	$0.0001$
$f\left(x\right)$	$-0.5440$	$-0.5063$	$0.8268$	$-0.3056$

The value of the function is not possible to find when $x$ tends to $0$ as the values of function are oscillates with decrease in $x$ .

Therefore, The value of the $\underset{x\to 0}{\lim }f\left(x\right)$ doesn’t exist.