
Concept explainers
(a)
Interpretation:
The complete balanced equation for the given incomplete reaction has to be written.
Concept Introduction:
Balanced Chemical equation:
A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass.
(a)

Answer to Problem 21.94QP
Explanation of Solution
To Write: The complete balanced equation for the given incomplete reaction.
Lithium bicarbonate undergoes decomposition while heating and gives lithium carbonate, water and carbon dioxide.
The balanced equation is given as follows,
Lithium carbonate has two lithium atoms. Thus, lithium bicarbonate on reactants side gets coefficient two and other compounds does not need any coefficient. Now in both sides the elements are balanced.
(b)
Interpretation:
The complete balanced equation for the given incomplete reaction has to be written.
Concept Introduction:
Balanced Chemical equation:
A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass.
(b)

Answer to Problem 21.94QP
Explanation of Solution
To Write: The complete balanced equation for the given incomplete reaction.
Sodium sulfate reacts with barium chloride to form sodium chloride and barium sulfate solution.
The balanced equation is given as follows,
There are two sodium, one barium, one sulfur, two chlorine and four oxygen atoms on reactant side. Product side has one barium, one sulfur, one sodium, one chlorine and four oxygen. Only sodium chloride gets coefficient two and balances the equation. Now in both sides the elements are balanced.
(c)
Interpretation:
The complete balanced equation for the given incomplete reaction has to be written.
Concept Introduction:
Balanced Chemical equation:
A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass.
(c)

Answer to Problem 21.94QP
Explanation of Solution
To Write: The complete balanced equation for the given incomplete reaction.
Potassium carbonate reacts with calcium hydroxide to form calcium carbonate precipitate.
The balanced equation is given as follows,
Potassium hydroxide gets coefficient two because potassium carbonate has two potassium atoms. Now in both sides the elements are balanced.
(d)
Interpretation:
The complete balanced equation for the given incomplete reaction has to be written.
Concept Introduction:
Balanced Chemical equation:
A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass.
(d)

Answer to Problem 21.94QP
Explanation of Solution
To Write: The complete balanced equation for the given incomplete reaction.
Lithium reacts with hydrochloric acid which gives lithium chloride and hydrogen gas.
The balanced equation is given as follows,
Hydrogen chloride, lithium chloride and lithium gets coefficient two due to two hydrogen atoms in hydrogen gas. Now in both sides the elements are balanced.
(e)
Interpretation:
The complete balanced equation for the given incomplete reaction has to be written.
Concept Introduction:
Balanced Chemical equation:
A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass.
(e)

Answer to Problem 21.94QP
Explanation of Solution
To Write: The complete balanced equation for the given incomplete reaction.
Sodium reacts with zirconium chloride which gives sodium chloride and zirconium.
The balanced equation is given as follows,
Zirconium chloride has four chloride atoms which gives rise to coefficient four for sodium chloride and sodium. Now in both sides the elements are balanced.
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Chapter 21 Solutions
Student Solutions Manual for Ebbing/Gammon's General Chemistry
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- 2. (3 pts) Consider the unit cell for the spinel compound, CrFe204. How many total particles are in the unit cell? Also, show how the number of particles and their positions are consistent with the CrFe204 stoichiometry - this may or may not be reflected by the particle colors in the diagram. (HINT: In the diagram, the blue particle is in an interior position while each red particle is either in a corner or face position.)arrow_forwardFrom the following potentials, calculate the activity of Cl- in saturated KCl. E0 (calomel electrode)= 0.268 V E (calomel electrode, saturated KCl)= 0.241 Varrow_forwardCalculate the voltage of each of the following cells. a) Fe(s)/Fe2+ (1.55 x 10-2 M)//Cu2+ (6.55 x 10-3 M)/Cu(s) b) Pt, H2 (0.255 bar)/HCl (4.55 x 10-4 M), AgCl (sat'd)/Ag Fe2+ +2e- = Fe E0= -0.44 V Cu2+ + 2e- = Cu E0= 0.337 V Ag+ + e- = Ag E0= 0.799 V AgCl(s) + e- = Ag(s) + Cl- E0= 0.222 V 2H+ + 2e- = H2 E0= 0.000 Varrow_forward
- A solution contains 0.097 M Ce3+, 1.55x10-3 M Ce4+, 1.55x10-3 M Mn2+, 0.097 M MnO4-, and 1.00 M HClO4 (F= 9.649 x 104 C/mol). a) Write a balanced net reaction that can occur between species in this solution. b) Calculate deltaG0 and K for the reaction. c) Calculate E and deltaG for the conditions given. Ce4+ + e- = Ce3+ E0= 1.70 V MnO4- + 8H+ + 5e- = Mn2+ + 4H2O E0= 1.507 Varrow_forward1. Provide a step-by-step mechanism for formation of ALL STEREOISOMERS in the following reaction. Na HCO3 (Sodium bicarbonate, baking soda) is not soluble in CH2Cl2. The powder is a weak base used to neutralize strong acid (pKa < 0) produced by the reaction. Redraw the product to show the configuration(s) that form at C-2 and C-4. Br2 OH CH2Cl2 Na* HCO3 Br HO OH + Na Br +arrow_forward2. Specify the solvent and reagent(s) required to carry out each of the following FGI. If two reagent sets must be used for the FGI, specify the solvent and reagent(s) for each reagent set. If a reaction cannot be carried out with reagents (sets) class, write NP (not possible) in the solvent box for reagent set #1. Use the letter abbreviation for each solvent; use a number abbreviation for reagent(s). Solvents: CH2Cl2 (A); H₂O (B); Reagents: HBr (1); R₂BH (6); H2SO4 (2); CH3OH (C); Br₂ (3); CH3CO₂H (D) NaHCO3 (4); Hg(OAc)2 (5); H₂O2/HO (7); NaBH4 (8) Reagent Set #1 Reagent Set #2 FGI + enant OH Solvent Reagent(s) Solvent Reagent(s)arrow_forward
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