Chapter 21, Problem 21.79QP

(a)

Interpretation Introduction

Interpretation:

Energy released when $\text{U-238}$ isotope decays to $\text{Th-234}$ have to be determined.

Concept Introduction:

$Energy,\Delta E=\left(\Delta m\right)c^2$, where $\text{Δm}$ is the mass defect and $c$ is the speed of light.

$\text{Δm}\text{=mass}\text{of}\text{product-}\text{mass}\text{of}\text{reactant}$

(b)

Interpretation Introduction

Interpretation:

Out of $\text{Th-234}$ and $\alpha$ particle, the one which moves faster has to be identified.

Concept Introduction:

$Energy,\Delta E=\left(\Delta m\right)c^2$, where $\text{Δm}$ is the mass defect and $c$ is the speed of light.

$\text{Δm}\text{=mass}\text{of}\text{product-}\text{mass}\text{of}\text{reactant}$

Lighter particle will move faster at a greater speed than heavier particles.