Chapter 21, Problem 21.48AP

Interpretation Introduction

Interpretation:

Whether hydrolysis of fructose $\text{6-phosphate}$ favorable for phosphorylating $ADP$ if it is or not the reasons should be explained and what would make the reaction favorable should be identified.

Concept Introduction:

Exergonic: The reaction is considered as exergonic if energy released since the reactants loses its energy making the free energy more negative hence making it spontaneous reaction.

Endergonic: The reaction is considered as endergonic if it needs more energy means that activation energy is much higher making the reaction non spontaneous.

Favorable Reaction: They release free energy which in turn used to do work. The products will have lower energy than reactants of the reaction shows that stable products are obtained hence the value of $\text{ΔG}$ will be negative.

The tendency for reaction proceed toward product side before reaching equilibrium will increases as more amount of free energy released.

Hydrolysis: The reaction in which chemical compound is breakdown in presence of water is termed as hydrolysis. Here water serves as one reactant.

Phosphorylation: It involves transfer of phosphate group from inorganic/organic phosphate to another chemical compound.