Determining the value of variables “first” and “last” in function “reverse_array”: From the given question, an array of odd length “cnt = 2k + 1”. Assume k = 0, 1, 2 Case 1: When “k = 0”, then “cnt = 2 (0) + 1 = 0 + 1 = 1”. Then call the function “reverse_array” with “cnt = 1”. first last = cnt - 1 first < = last inplace_swap(&a[first], &a[last]) first = 0 last = 1 - 1 = 0 0 < = 0 inplace_swap(&a[0], &a[0]) Here the both values are equal so value of middle element “a[0]” is “0”. Therefore, “first = 0” and “last = 0”. That is same as the value of “k”. Case 2: When “k = 1”, then cnt = 2 (1) + 1 = 2 + 1 = 3. Then call the function “reverse_array” with “cnt = 3”...

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Answer 1

Expert Solution & Answer

Chapter 2.1, Problem 2.11PP

A.

Explanation of Solution

Determining the value of variables “first” and “last” in function “reverse_array”:

From the given question, an array of odd length “cnt = 2k + 1”. Assume k = 0, 1, 2

Case 1:

When “k = 0”, then “cnt = 2 (0) + 1 = 0 + 1 = 1”.

Then call the function “reverse_array” with “cnt = 1”.

first last = cnt - 1 first < = last inplace_swap(&a[first], &a[last])
first = 0 last = 1 - 1 = 0 0 < = 0
inplace_swap(&a[0], &a[0])

Here the both values are equal so value of middle element “a[0]” is “0”.

Therefore, “first = 0” and “last = 0”. That is same as the value of “k”.

Case 2:

When “k = 1”, then cnt = 2 (1) + 1 = 2 + 1 = 3.

Then call the function “reverse_array” with “cnt = 3”...

B.

Explanation of Solution

Setting the array element is “0” in the function “inplace_swap”:

In the “inplace_swap” function, the arguments “x” and “y” point to the same location.

Once user compute “x ^ y”, then the user get the result of “0”. Because of, value of “a ^ a” is “0” for any “a” in the “inplace_swap” function.

It is based on the property of “^”.

Calling “inplace_swap” function to the reverse array, the value of middle element becomes “0” for odd array length.

Example:

When the array elements are “1, 2, 3, 4 and 5”, then the reverse array is “5, 4, 0, 2, 1”.

Call the function “reverse_array” with array “a” 1, 2, 3, 4 and 5 and “cnt = 3”.

Initially array “a” is

a[0] a[1] a[2] a[3] a[4]
1 2 3 4 5

Steps to find the reverse array...

C.

Explanation of Solution

Modification to the code for “reverse_array” function:

Replace the test condition of “first <=...

Expert Solution & Answer

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Check out a sample textbook solution

See solution

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Answer 2

Expert Solution & Answer

Chapter 2.1, Problem 2.11PP

A.

Explanation of Solution

Determining the value of variables “first” and “last” in function “reverse_array”:

From the given question, an array of odd length “cnt = 2k + 1”. Assume k = 0, 1, 2

Case 1:

When “k = 0”, then “cnt = 2 (0) + 1 = 0 + 1 = 1”.

Then call the function “reverse_array” with “cnt = 1”.

first last = cnt - 1 first < = last inplace_swap(&a[first], &a[last])
first = 0 last = 1 - 1 = 0 0 < = 0
inplace_swap(&a[0], &a[0])

Here the both values are equal so value of middle element “a[0]” is “0”.

Therefore, “first = 0” and “last = 0”. That is same as the value of “k”.

Case 2:

When “k = 1”, then cnt = 2 (1) + 1 = 2 + 1 = 3.

Then call the function “reverse_array” with “cnt = 3”...

B.

Explanation of Solution

Setting the array element is “0” in the function “inplace_swap”:

In the “inplace_swap” function, the arguments “x” and “y” point to the same location.

Once user compute “x ^ y”, then the user get the result of “0”. Because of, value of “a ^ a” is “0” for any “a” in the “inplace_swap” function.

It is based on the property of “^”.

Calling “inplace_swap” function to the reverse array, the value of middle element becomes “0” for odd array length.

Example:

When the array elements are “1, 2, 3, 4 and 5”, then the reverse array is “5, 4, 0, 2, 1”.

Call the function “reverse_array” with array “a” 1, 2, 3, 4 and 5 and “cnt = 3”.

Initially array “a” is

a[0] a[1] a[2] a[3] a[4]
1 2 3 4 5

Steps to find the reverse array...

C.

Explanation of Solution

Modification to the code for “reverse_array” function:

Replace the test condition of “first <=...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Expert Solution & Answer

Chapter 2.1, Problem 2.11PP

A.

Explanation of Solution

Determining the value of variables “first” and “last” in function “reverse_array”:

From the given question, an array of odd length “cnt = 2k + 1”. Assume k = 0, 1, 2

Case 1:

When “k = 0”, then “cnt = 2 (0) + 1 = 0 + 1 = 1”.

Then call the function “reverse_array” with “cnt = 1”.

first last = cnt - 1 first < = last inplace_swap(&a[first], &a[last])
first = 0 last = 1 - 1 = 0 0 < = 0
inplace_swap(&a[0], &a[0])

Here the both values are equal so value of middle element “a[0]” is “0”.

Therefore, “first = 0” and “last = 0”. That is same as the value of “k”.

Case 2:

When “k = 1”, then cnt = 2 (1) + 1 = 2 + 1 = 3.

Then call the function “reverse_array” with “cnt = 3”...

B.

Explanation of Solution

Setting the array element is “0” in the function “inplace_swap”:

In the “inplace_swap” function, the arguments “x” and “y” point to the same location.

Once user compute “x ^ y”, then the user get the result of “0”. Because of, value of “a ^ a” is “0” for any “a” in the “inplace_swap” function.

It is based on the property of “^”.

Calling “inplace_swap” function to the reverse array, the value of middle element becomes “0” for odd array length.

Example:

When the array elements are “1, 2, 3, 4 and 5”, then the reverse array is “5, 4, 0, 2, 1”.

Call the function “reverse_array” with array “a” 1, 2, 3, 4 and 5 and “cnt = 3”.

Initially array “a” is

a[0] a[1] a[2] a[3] a[4]
1 2 3 4 5

Steps to find the reverse array...

C.

Explanation of Solution

Modification to the code for “reverse_array” function:

Replace the test condition of “first <=...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Expert Solution & Answer

Chapter 2.1, Problem 2.11PP

A.

Explanation of Solution

Determining the value of variables “first” and “last” in function “reverse_array”:

From the given question, an array of odd length “cnt = 2k + 1”. Assume k = 0, 1, 2

Case 1:

When “k = 0”, then “cnt = 2 (0) + 1 = 0 + 1 = 1”.

Then call the function “reverse_array” with “cnt = 1”.

first last = cnt - 1 first < = last inplace_swap(&a[first], &a[last])
first = 0 last = 1 - 1 = 0 0 < = 0
inplace_swap(&a[0], &a[0])

Here the both values are equal so value of middle element “a[0]” is “0”.

Therefore, “first = 0” and “last = 0”. That is same as the value of “k”.

Case 2:

When “k = 1”, then cnt = 2 (1) + 1 = 2 + 1 = 3.

Then call the function “reverse_array” with “cnt = 3”...

B.

Explanation of Solution

Setting the array element is “0” in the function “inplace_swap”:

In the “inplace_swap” function, the arguments “x” and “y” point to the same location.

Once user compute “x ^ y”, then the user get the result of “0”. Because of, value of “a ^ a” is “0” for any “a” in the “inplace_swap” function.

It is based on the property of “^”.

Calling “inplace_swap” function to the reverse array, the value of middle element becomes “0” for odd array length.

Example:

When the array elements are “1, 2, 3, 4 and 5”, then the reverse array is “5, 4, 0, 2, 1”.

Call the function “reverse_array” with array “a” 1, 2, 3, 4 and 5 and “cnt = 3”.

Initially array “a” is

a[0] a[1] a[2] a[3] a[4]
1 2 3 4 5

Steps to find the reverse array...

C.

Explanation of Solution

Modification to the code for “reverse_array” function:

Replace the test condition of “first <=...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 2.1, Problem 2.11PP

A.

Explanation of Solution

Determining the value of variables “first” and “last” in function “reverse_array”:

From the given question, an array of odd length “cnt = 2k + 1”. Assume k = 0, 1, 2

Case 1:

When “k = 0”, then “cnt = 2 (0) + 1 = 0 + 1 = 1”.

Then call the function “reverse_array” with “cnt = 1”.

first last = cnt - 1 first < = last inplace_swap(&a[first], &a[last])
first = 0 last = 1 - 1 = 0 0 < = 0
inplace_swap(&a[0], &a[0])

Here the both values are equal so value of middle element “a[0]” is “0”.

Therefore, “first = 0” and “last = 0”. That is same as the value of “k”.

Case 2:

When “k = 1”, then cnt = 2 (1) + 1 = 2 + 1 = 3.

Then call the function “reverse_array” with “cnt = 3”...

B.

Explanation of Solution

Setting the array element is “0” in the function “inplace_swap”:

In the “inplace_swap” function, the arguments “x” and “y” point to the same location.

Once user compute “x ^ y”, then the user get the result of “0”. Because of, value of “a ^ a” is “0” for any “a” in the “inplace_swap” function.

It is based on the property of “^”.

Calling “inplace_swap” function to the reverse array, the value of middle element becomes “0” for odd array length.

Example:

When the array elements are “1, 2, 3, 4 and 5”, then the reverse array is “5, 4, 0, 2, 1”.

Call the function “reverse_array” with array “a” 1, 2, 3, 4 and 5 and “cnt = 3”.

Initially array “a” is

a[0] a[1] a[2] a[3] a[4]
1 2 3 4 5

Steps to find the reverse array...

C.

Explanation of Solution

Modification to the code for “reverse_array” function:

Replace the test condition of “first <=...

Answer 8

Chapter 2.1, Problem 2.11PP

A.

Explanation of Solution

Determining the value of variables “first” and “last” in function “reverse_array”:

From the given question, an array of odd length “cnt = 2k + 1”. Assume k = 0, 1, 2

Case 1:

When “k = 0”, then “cnt = 2 (0) + 1 = 0 + 1 = 1”.

Then call the function “reverse_array” with “cnt = 1”.

first last = cnt - 1 first < = last inplace_swap(&a[first], &a[last])
first = 0 last = 1 - 1 = 0 0 < = 0
inplace_swap(&a[0], &a[0])

Here the both values are equal so value of middle element “a[0]” is “0”.

Therefore, “first = 0” and “last = 0”. That is same as the value of “k”.

Case 2:

When “k = 1”, then cnt = 2 (1) + 1 = 2 + 1 = 3.

Then call the function “reverse_array” with “cnt = 3”...

Answer 9

Chapter 2.1, Problem 2.11PP

A.

Explanation of Solution

Determining the value of variables “first” and “last” in function “reverse_array”:

From the given question, an array of odd length “cnt = 2k + 1”. Assume k = 0, 1, 2

Case 1:

When “k = 0”, then “cnt = 2 (0) + 1 = 0 + 1 = 1”.

Then call the function “reverse_array” with “cnt = 1”.

first last = cnt - 1 first < = last inplace_swap(&a[first], &a[last])
first = 0 last = 1 - 1 = 0 0 < = 0
inplace_swap(&a[0], &a[0])

Here the both values are equal so value of middle element “a[0]” is “0”.

Therefore, “first = 0” and “last = 0”. That is same as the value of “k”.

Case 2:

When “k = 1”, then cnt = 2 (1) + 1 = 2 + 1 = 3.

Then call the function “reverse_array” with “cnt = 3”...

Answer 10

B.

Explanation of Solution

Setting the array element is “0” in the function “inplace_swap”:

In the “inplace_swap” function, the arguments “x” and “y” point to the same location.

Once user compute “x ^ y”, then the user get the result of “0”. Because of, value of “a ^ a” is “0” for any “a” in the “inplace_swap” function.

It is based on the property of “^”.

Calling “inplace_swap” function to the reverse array, the value of middle element becomes “0” for odd array length.

Example:

When the array elements are “1, 2, 3, 4 and 5”, then the reverse array is “5, 4, 0, 2, 1”.

Call the function “reverse_array” with array “a” 1, 2, 3, 4 and 5 and “cnt = 3”.

Initially array “a” is

a[0] a[1] a[2] a[3] a[4]
1 2 3 4 5

Steps to find the reverse array...

Answer 11

B.

Explanation of Solution

Setting the array element is “0” in the function “inplace_swap”:

In the “inplace_swap” function, the arguments “x” and “y” point to the same location.

Once user compute “x ^ y”, then the user get the result of “0”. Because of, value of “a ^ a” is “0” for any “a” in the “inplace_swap” function.

It is based on the property of “^”.

Calling “inplace_swap” function to the reverse array, the value of middle element becomes “0” for odd array length.

Example:

When the array elements are “1, 2, 3, 4 and 5”, then the reverse array is “5, 4, 0, 2, 1”.

Call the function “reverse_array” with array “a” 1, 2, 3, 4 and 5 and “cnt = 3”.

Initially array “a” is

a[0] a[1] a[2] a[3] a[4]
1 2 3 4 5

Steps to find the reverse array...

Answer 12

C.

Explanation of Solution

Modification to the code for “reverse_array” function:

Replace the test condition of “first <=...

Answer 13

C.

Explanation of Solution

Modification to the code for “reverse_array” function:

Replace the test condition of “first <=...

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

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Check out a sample textbook solution

See solution

Answer 17

Ch. 2.1 - Practice Problem 2.1 (solution page 143) Perform...Ch. 2.1 - Prob. 2.2PP Ch. 2.1 - Prob. 2.3PP Ch. 2.1 - Practice Problem 2.4 (solution page 144) Without...Ch. 2.1 - Prob. 2.5PP Ch. 2.1 - Prob. 2.6PP Ch. 2.1 - Prob. 2.7PP Ch. 2.1 - Prob. 2.8PP Ch. 2.1 - Practice Problem 2.9 solution page 146 Computers...Ch. 2.1 - Prob. 2.10PP

Solution Summary: The author explains how to determine the value of variables "first" and "last" in function "reverse_array".

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Explanation of Solution

Explanation of Solution

Modification to the code for “reverse_array” function:

Replace the test condition of “first <=...

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Chapter 2 Solutions

Solution Summary: The author explains how to determine the value of variables "first" and "last" in function "reverse_array".

Concept explainers

Explanation of Solution

Explanation of Solution

Explanation of Solution

Modification to the code for “reverse_array” function: Replace the test condition of “first <=...

Want to see the full answer?

Chapter 2 Solutions

Modification to the code for “reverse_array” function:

Replace the test condition of “first <=...