
A.
Explanation of Solution
“C” Expression for “K = 17”:
The C expression to perform the multiplications for “K = 17” is shown below
Expression: (x << 4) + x
A complete program has been developed to perform the multiplication with “K = 17” is shown below:
//Header file
#include <stdio.h>
#include <assert.h>
//Function definition for part A that is K = 17
int partA(int x)
{
//Returns the value by using "(x << 4) + x"
return (x << 4) + x;
}
//Main function
int main(int argc, char* argv[])
{
//Assign the value for "x"
int xValue = 0x12345678;
/* Call function "partA" with checking value using assert function */
assert(partA(xValue) == 17 * xValue);
return 0;
}
The given code is used to multiply integer variable “x” by constant factor “K = 17”...
B.
Explanation of Solution
“C” Expression for “K = -7”:
The C expression to perform the multiplications for “K = -7” is shown below
Expression: x - (x << 3)
Program:
A complete program has been developed to perform the multiplication with “K = -7” is shown below:
//Header file
#include <stdio.h>
#include <assert.h>
//Function definition for part B that is K = -7
int partB(int x)
{
//Returns the value by using "x - (x << 3);"
return x - (x << 3);
}
//Main function
int main(int argc, char* argv[])
{
//Assign the value for "x"
int xValue = 0x12345678;
/* Call function "partB" with checking value using assert function */
assert(partB(xValue) == -7 * xValue);
return 0;
}
The given code is used to multiply integer variable “x” by constant factor “K = -7”...
C.
Explanation of Solution
“C” Expression for “K = 60”:
The C expression to perform the multiplications for “K = 60” is shown below
Expression: (x << 6) - (x << 2)
Program:
A complete program has been developed to perform the multiplication with “K = 60” is shown below:
//Header file
#include <stdio.h>
#include <assert.h>
//Function definition for part C that is K = 60
int partC(int x)
{
//Returns the value by using "(x << 6) - (x << 2)"
return (x << 6) - (x << 2);
}
//Main function
int main(int argc, char* argv[])
{
//Assign the value for "x"
int xValue = 0x12345678;
/* Call function "partC" with checking value using assert function */
assert(partC(xValue) == 60 * xValue);
return 0;
}
The given code is used to multiply integer variable “x” by constant factor “K = 60”...
D.
Explanation of Solution
“C” Expression for “K = -112”:
The C expression to perform the multiplications for “K = -112” is shown below
Expression: (x << 4) - (x << 7)
Program:
A complete program has been developed to perform the multiplication with “K = -112” is shown below:
//Header file
#include <stdio.h>
#include <assert.h>
//Function definition for part D that is K = -112
int partD(int x)
{
//Returns the value by using "(x << 4) - (x << 7)"
return (x << 4) - (x << 7);
}
//Main function
int main(int argc, char* argv[])
{
//Assign the value for "x"
int xValue = 0x12345678;
/* Call function "partD" with checking value using assert function */
assert(partD(xValue) == -112 * xValue);
return 0;
}
The given code is used to multiply integer variable “x” by constant factor “K = -112”...

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