
A.
Explanation of Solution
For “C” expression “
- The given “C” expression does not always produce “1”.
- When the value of “x” is “INT_MIN”, the given expression producing the result of “0”.
A complete program has been developed for the above expression when producing result “0” is shown below.
#include <stdio.h>
#include <assert.h>
#include <limits.h>
#include <stdlib.h>
//Function definition for part A
int partA(int x, int y)
{
//Returns the value
return (x < y) == (-x > -y);
}
//Main function
int main(int argc, char* argv[])
{
/* Call function "partA" with checking value using
B.
Explanation of Solution
For “C” expression “
The given “C” expression is always producing the result as “1”. The mathematical principle for given expression shown below:
C.
Explanation of Solution
For “C” expression “
The given “C” expression is always producing the result as “1”. The mathematical principle for given expression shown below:
Program:
A complete program has been developed for the above expression when producing result “1” is shown below
D.
Explanation of Solution
For “C” expression “
The given “C” expression is always producing the result as “1”. The mathematical principle for given expression shown below:
Program:
A complete program has been developed for the above expression when producing result “1” is shown below.
//Header file
#include <stdio.h>
#include <assert.h>
#include <limits.h>
#include <stdlib
E.
Explanation of Solution
For “C” expression “
The given “C” expression is always producing the result as “1”. The mathematical principle for given expression shown below:
For proving

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Chapter 2 Solutions
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