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Concept explainers
Interpretation: The properties and the uses for the chlorofluorocarbon (CFC) should be identified.
Concept Introduction:
Atmosphere: The atmosphere is defined as air that is layer of gases which surrounds the earth due to gravity of earth.
The earth atmosphere consists of layers such as thermosphere, mesosphere, stratosphere and troposphere depending on the temperature and its composition.
Stratosphere:
It is found below the mesosphere layer in which the concentration of ozone and other gases are high. The increasing temperature for this layer with respect to increasing height is due to the presence of high concentration of ozone and other gases in it.
The increased temperature is due to the response of UV radiation from sun and hence ozone is formed due to this reaction and the use of ozone is that it prevents the UV radiation from the sun which is actually harmful.
Troposphere:
The layer is below stratosphere layer and it is closest to the earth surface. It is wholly composed of major air that is 80% of the total mass and almost all the water vapor.
It is the thinnest place which is responsible for all weather conditions since it contains almost all amounts of water vapor with it.
To determine: The properties and the uses of given gas.
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Chapter 21 Solutions
GEN COMBO CHEMISTRY: ATOMS FIRST; ALEKS 360 2S ACCESS CARD CHEMISTRY:ATOMS FIRST
- Shown below are five NMR spectra for five different C6H10O2 compounds. For each spectrum, draw the structure of the compound, and assign the spectrum by labeling H's in your structure (or in a second drawing of the structure) with the chemical shifts of the corresponding signals (which can be estimated to nearest 0.1 ppm). IR information is also provided. As a reminder, a peak near 1700 cm-1 is consistent with the presence of a carbonyl (C=O), and a peak near 3300 cm-1 is consistent with the presence of an O–H. Extra information: For C6H10O2 , there must be either 2 double bonds, or 1 triple bond, or two rings to account for the unsaturation. There is no two rings for this problem. A strong band was observed in the IR at 1717 cm-1arrow_forwardPredict the major products of the organic reaction below. : ☐ + Х ك OH 1. NaH 2. CH₂Br Click and drag to start drawing a structure.arrow_forwardNG NC 15Show all the steps you would use to synthesize the following products shown below using benzene and any organic reagent 4 carbons or less as your starting material in addition to any inorganic reagents that you have learned. NO 2 NC SO3H NO2 OHarrow_forward
- Please draw a stepwise mechanism for this reaction.arrow_forwardPlease show full mechanism for this equation, all arrows and resonance. I would like to see the mechanisms for para, ortho, and meta positions! Thank youarrow_forward1 Please provide an efficient synthesis of the product below from the starting material. Use the starting material as the ONLY source of carbon atoms. Show the synthesis of each compound that would be used in the overall synthesis of the product. [This synthesis uses alkyne and alcohol chemistry.]arrow_forward
- 10- 4000 20 20 30- %Reflectance 60 50- 09 60- 40- Date: Thu Feb 06 17:30:02 2025 (GMT-05:0(UnknownP Scans: 8 Resolution: 2.000 70 70 88 80 3500 3000 2500 90 100 00 Wavenumbers (cm-1) 2000 1500 2983.10 2359.13 1602.52 1584.22 1451.19 1391.87 1367.07 1314.37 1174.34 1070.13 1027.33 1714.16 1269.47 1000 1106.08 1001.14 937.02 873.60 850.20 780.22 686.91 674.38 643.09 617.98 02/06/25 16:38:20arrow_forwardd. Draw arrow-pushing mechanism for an enzymatic retro-aldol reaction of the following hexose. Use B: and/or HA as needed. OH OH سية HO OH OHarrow_forward4. Calculate the wavelength of a photon needed to excite a transition between neighbouring energy levels of a harmonic oscillator of effective mass equal to that of an oxygen atom and with a force constant of 544 N m¹.arrow_forward
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