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Concept explainers
Interpretation: The wavelength required to break the bond between oxygen and hydrogen atom with given minimum energy requires for breaking the bond should be determined.
Concept Introduction:
Energy: The energy is conversed property since it can neither be created nor be destroyed but can be transformed. The energy of the photon is obtained by using the following relation
Wavelength: The distance between the two continuous maximum displacements present in wave or the two continuous minimum displacements present in a wave exhibited by the photons is called wavelength. The wavelength of the photon is inversely proportional to its frequency. The relationship between them is given by the following formula,
Frequency: It denotes the number of waves passes in given amount of time.
Atmosphere: The atmosphere is defined as air that is layer of gases which surrounds the earth due to gravity of earth.
The earth atmosphere consists of layers such as thermosphere, mesosphere, stratosphere and troposphere depending on the temperature and its composition.
Stratosphere:
It is found below the mesosphere layer in which the concentration of ozone and other gases are high. The increasing temperature for this layer with respect to increasing height is due to the presence of high concentration of ozone and other gases in it.
The increased temperature is due to the response of UV radiation from sun and hence ozone is formed due to this reaction and the use of ozone is that it prevents the UV radiation from the sun which is actually harmful.
Troposphere:
The layer is below stratosphere layer and it is closest to the earth surface. It is wholly composed of major air that is 80% of the total mass and almost all the water vapor.
It is the thinnest place which is responsible for all weather conditions since it contains almost all amounts of water vapor with it.
To determine: The wavelength required to decompose the given bond and the stability of that species in the given atmospheric layers.
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Chapter 21 Solutions
GEN COMBO CHEMISTRY: ATOMS FIRST; ALEKS 360 2S ACCESS CARD CHEMISTRY:ATOMS FIRST
- Question 7 (10 points) Identify the carboxylic acid present in each of the following items and draw their structures: Food Vinegar Oranges Yogurt Sour Milk Pickles Acid Structure Paragraph ✓ BI UAE 0118 + v Task: 1. Identify the carboxylic acid 2. Provide Name 3. Draw structure 4. Take a picture of your table and insert Add a File Record Audio Record Video 11.arrow_forwardCheck the box under each structure in the table that is an enantiomer of the molecule shown below. If none of them are, check the none of the above box under the table. Molecule 1 Molecule 2 IZ IN Molecule 4 Molecule 5 ZI none of the above ☐ Molecule 3 Х IN www Molecule 6 NH Garrow_forwardHighlight each chiral center in the following molecule. If there are none, then check the box under the drawing area. There are no chiral centers. Cl Cl Highlightarrow_forward
- A student proposes the following two-step synthesis of an ether from an alcohol A: 1. strong base A 2. R Is the student's proposed synthesis likely to work? If you said the proposed synthesis would work, enter the chemical formula or common abbreviation for an appropriate strong base to use in Step 1: If you said the synthesis would work, draw the structure of an alcohol A, and the structure of the additional reagent R needed in Step 2, in the drawing area below. If there's more than one reasonable choice for a good reaction yield, you can draw any of them. ☐ Click and drag to start drawing a structure. Yes No ロ→ロ 0|0 G Х D : ☐ பarrow_forwardटे Predict the major products of this organic reaction. Be sure to use wedge and dash bonds when necessary, for example to distinguish between different major products. ☐ ☐ : ☐ + NaOH HO 2 Click and drag to start drawing a structure.arrow_forwardShown below are five NMR spectra for five different C6H10O2 compounds. For each spectrum, draw the structure of the compound, and assign the spectrum by labeling H's in your structure (or in a second drawing of the structure) with the chemical shifts of the corresponding signals (which can be estimated to nearest 0.1 ppm). IR information is also provided. As a reminder, a peak near 1700 cm-1 is consistent with the presence of a carbonyl (C=O), and a peak near 3300 cm-1 is consistent with the presence of an O–H. Extra information: For C6H10O2 , there must be either 2 double bonds, or 1 triple bond, or two rings to account for the unsaturation. There is no two rings for this problem. A strong band was observed in the IR at 1717 cm-1arrow_forward
- Predict the major products of the organic reaction below. : ☐ + Х ك OH 1. NaH 2. CH₂Br Click and drag to start drawing a structure.arrow_forwardNG NC 15Show all the steps you would use to synthesize the following products shown below using benzene and any organic reagent 4 carbons or less as your starting material in addition to any inorganic reagents that you have learned. NO 2 NC SO3H NO2 OHarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
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