OWLv2 for Ebbing/Gammon's General Chemistry, 11th Edition, [Instant Access], 1 term (6 months)
OWLv2 for Ebbing/Gammon's General Chemistry, 11th Edition, [Instant Access], 1 term (6 months)
11th Edition
ISBN: 9781305673939
Author: Darrell Ebbing; Steven D. Gammon
Publisher: Cengage Learning US
Question
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Chapter 21, Problem 21.125QP

(a)

Interpretation Introduction

Interpretation:

The given equation has to be written complete and balanced

Concept Introduction:

Balanced Chemical equation:

A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass.

To Write: The given equation complete and balanced.

(a)

Expert Solution
Check Mark

Answer to Problem 21.125QP

The complete and balanced equation of the given equation is:

CO2(g) + Ba(OH)2(aq) BaCO3(s) + H2O(l)

Explanation of Solution

Given Equation:

CO2(g) + Ba(OH)2(aq)

Complete Equation:

A complete equation will have same present on both sides of the equation.

The above equation can be completed by writing as follows,

CO2(g) + Ba(OH)2(aq) BaCO3(s) + H2O(l)

Balancing the equation:

A balanced equation will have same elements and same number of atoms of each side of the reaction.

List the atoms of the equation in a table and check for the equal number of atoms present on either side of the reaction.

Reactant side Atom Product side
1 C 1
4 O 4
1 Ba 1
2 H 2

The number of atoms on both sides of the reaction are same. Therefore, the above equation is a balanced one.

Hence, the complete and balanced form of the given equation is written as:

  CO2(g) + Ba(OH)2(aq) BaCO3(s) + H2O(l)

Conclusion

The complete and balanced equation of the given equation is written as:

CO2(g) + Ba(OH)2(aq) BaCO3(s) + H2O(l)

(b)

Interpretation Introduction

Interpretation:

The given equation has to be written complete and balanced

Concept Introduction:

Balanced Chemical equation:

A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass.

To Write: The given equation complete and balanced.

(b)

Expert Solution
Check Mark

Answer to Problem 21.125QP

The complete and balanced equation of the given equation is:

MgCO3(s) + 2HBr(aq) CO2(g) + H2O(l) + MgBr2(aq)

Explanation of Solution

Given Equation:

MgCO3(s) + HBr(aq) 

Complete equation:

A complete equation will have same present on both sides of the equation.

The above equation can be completed by writing as follows,

MgCO3(s) + HBr(aq) CO2(g) + H2O(l) + MgBr2(aq)

Balancing the equation:

A balanced equation will have same elements and same number of atoms of each side of the reaction.

MgCO3(s) + HBr(aq) CO2(g) + H2O(l) + MgBr2(aq)

List the atoms of the equation in a table and check for the equal number of atoms present on either side of the reaction.

Reactant side Atom Product side
1 C 1
3 O 3
1 Mg 1
1 H 2
1 Br 2

Multiply HBr on the reactant side by two and balance the equation again.

MgCO3(s) + 2HBr(aq) CO2(g) + H2O(l) + MgBr2(aq)

Again, list the atoms of the equation in a table and check for the equal number of atoms present on either side of the reaction.

Reactant side Atom Product side
1 C 1
3 O 3
1 Mg 1
2 H 2
2 Br 2

The number of atoms on both sides of the reaction are same. Therefore, the above equation is a balanced one.

Hence, the complete and balanced form of the given equation is written as:

  MgCO3(s) + 2HBr(aq) CO2(g) + H2O(l) + MgBr2(aq)

Conclusion

The complete and balanced equation of the given equation is written as:

MgCO3(s) + 2HBr(aq) CO2(g) + H2O(l) + MgBr2(aq)

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Chapter 21 Solutions

OWLv2 for Ebbing/Gammon's General Chemistry, 11th Edition, [Instant Access], 1 term (6 months)

Ch. 21 - Prob. 21.9QPCh. 21 - Prob. 21.10QPCh. 21 - Prob. 21.11QPCh. 21 - Prob. 21.12QPCh. 21 - Prob. 21.13QPCh. 21 - Prob. 21.14QPCh. 21 - Prob. 21.15QPCh. 21 - Prob. 21.16QPCh. 21 - Prob. 21.17QPCh. 21 - Prob. 21.18QPCh. 21 - Prob. 21.19QPCh. 21 - Prob. 21.20QPCh. 21 - Prob. 21.21QPCh. 21 - Prob. 21.22QPCh. 21 - Prob. 21.23QPCh. 21 - Prob. 21.24QPCh. 21 - Prob. 21.25QPCh. 21 - Prob. 21.26QPCh. 21 - Prob. 21.27QPCh. 21 - Prob. 21.28QPCh. 21 - Prob. 21.29QPCh. 21 - Prob. 21.30QPCh. 21 - Prob. 21.31QPCh. 21 - Prob. 21.32QPCh. 21 - Prob. 21.33QPCh. 21 - Prob. 21.34QPCh. 21 - Prob. 21.35QPCh. 21 - Prob. 21.36QPCh. 21 - Prob. 21.37QPCh. 21 - Prob. 21.38QPCh. 21 - Prob. 21.39QPCh. 21 - Prob. 21.40QPCh. 21 - Prob. 21.41QPCh. 21 - Describe the steps in the Ostwald process for the...Ch. 21 - Prob. 21.43QPCh. 21 - Prob. 21.44QPCh. 21 - Prob. 21.45QPCh. 21 - Prob. 21.46QPCh. 21 - Prob. 21.47QPCh. 21 - Prob. 21.48QPCh. 21 - What is the most important commercial means of...Ch. 21 - Prob. 21.50QPCh. 21 - Prob. 21.51QPCh. 21 - Prob. 21.52QPCh. 21 - Prob. 21.53QPCh. 21 - Prob. 21.54QPCh. 21 - Prob. 21.55QPCh. 21 - Prob. 21.56QPCh. 21 - Prob. 21.57QPCh. 21 - Prob. 21.58QPCh. 21 - Prob. 21.59QPCh. 21 - Prob. 21.60QPCh. 21 - Prob. 21.61QPCh. 21 - A test tube contains a solution of one of the...Ch. 21 - Prob. 21.63QPCh. 21 - Prob. 21.64QPCh. 21 - Prob. 21.65QPCh. 21 - Prob. 21.66QPCh. 21 - Prob. 21.67QPCh. 21 - Prob. 21.68QPCh. 21 - Prob. 21.69QPCh. 21 - Prob. 21.70QPCh. 21 - Prob. 21.71QPCh. 21 - Prob. 21.72QPCh. 21 - Prob. 21.73QPCh. 21 - Prob. 21.74QPCh. 21 - Prob. 21.75QPCh. 21 - Prob. 21.76QPCh. 21 - Prob. 21.77QPCh. 21 - Prob. 21.78QPCh. 21 - Prob. 21.79QPCh. 21 - Prob. 21.80QPCh. 21 - Prob. 21.81QPCh. 21 - Prob. 21.82QPCh. 21 - Prob. 21.83QPCh. 21 - Prob. 21.84QPCh. 21 - Prob. 21.85QPCh. 21 - Prob. 21.86QPCh. 21 - Sketch a diagram showing the formation of energy...Ch. 21 - Sketch a diagram showing the formation of energy...Ch. 21 - Prob. 21.89QPCh. 21 - Prob. 21.90QPCh. 21 - Prob. 21.91QPCh. 21 - Prob. 21.92QPCh. 21 - Prob. 21.93QPCh. 21 - Prob. 21.94QPCh. 21 - Francium was discovered as a minor decay product...Ch. 21 - Prob. 21.96QPCh. 21 - Prob. 21.97QPCh. 21 - Prob. 21.98QPCh. 21 - Prob. 21.99QPCh. 21 - Prob. 21.100QPCh. 21 - Prob. 21.101QPCh. 21 - Prob. 21.102QPCh. 21 - Prob. 21.103QPCh. 21 - Prob. 21.104QPCh. 21 - Prob. 21.105QPCh. 21 - Prob. 21.106QPCh. 21 - Prob. 21.107QPCh. 21 - Prob. 21.108QPCh. 21 - Prob. 21.109QPCh. 21 - Prob. 21.110QPCh. 21 - Prob. 21.111QPCh. 21 - Prob. 21.112QPCh. 21 - Prob. 21.113QPCh. 21 - Prob. 21.114QPCh. 21 - Prob. 21.115QPCh. 21 - Prob. 21.116QPCh. 21 - Prob. 21.117QPCh. 21 - Prob. 21.118QPCh. 21 - Prob. 21.119QPCh. 21 - Prob. 21.120QPCh. 21 - Prob. 21.121QPCh. 21 - Prob. 21.122QPCh. 21 - Prob. 21.123QPCh. 21 - Prob. 21.124QPCh. 21 - Prob. 21.125QPCh. 21 - Prob. 21.126QPCh. 21 - Prob. 21.127QPCh. 21 - Prob. 21.128QPCh. 21 - Prob. 21.129QPCh. 21 - Prob. 21.130QPCh. 21 - Prob. 21.131QPCh. 21 - Prob. 21.132QPCh. 21 - Prob. 21.133QPCh. 21 - Prob. 21.134QPCh. 21 - Prob. 21.135QPCh. 21 - Prob. 21.136QPCh. 21 - Prob. 21.137QPCh. 21 - Prob. 21.138QPCh. 21 - Prob. 21.139QPCh. 21 - Prob. 21.140QPCh. 21 - Prob. 21.141QPCh. 21 - Prob. 21.142QPCh. 21 - Prob. 21.143QPCh. 21 - Phosphorous acid, H3PO3, is oxidized to phosphoric...Ch. 21 - Prob. 21.145QPCh. 21 - Prob. 21.146QPCh. 21 - Prob. 21.147QPCh. 21 - Prob. 21.148QPCh. 21 - What are the oxidation numbers of sulfur in each...Ch. 21 - What are the oxidation numbers of sulfur in each...Ch. 21 - Prob. 21.151QPCh. 21 - Prob. 21.152QPCh. 21 - Prob. 21.153QPCh. 21 - Prob. 21.154QPCh. 21 - Prob. 21.155QPCh. 21 - Prob. 21.156QPCh. 21 - Chlorine can be prepared by oxidizing chloride ion...Ch. 21 - Prob. 21.158QPCh. 21 - Prob. 21.159QPCh. 21 - Prob. 21.160QPCh. 21 - Prob. 21.161QPCh. 21 - Prob. 21.162QPCh. 21 - Prob. 21.163QPCh. 21 - Prob. 21.164QPCh. 21 - Prob. 21.165QPCh. 21 - Prob. 21.166QPCh. 21 - Prob. 21.167QPCh. 21 - Xenon trioxide, XeO3, is reduced to xenon in...Ch. 21 - Prob. 21.169QPCh. 21 - Prob. 21.170QPCh. 21 - Prob. 21.171QPCh. 21 - Prob. 21.172QPCh. 21 - Prob. 21.173QPCh. 21 - Prob. 21.174QPCh. 21 - Prob. 21.175QPCh. 21 - Prob. 21.176QPCh. 21 - Prob. 21.177QPCh. 21 - Prob. 21.178QPCh. 21 - Prob. 21.179QPCh. 21 - Prob. 21.180QPCh. 21 - Prob. 21.181QPCh. 21 - Prob. 21.182QPCh. 21 - Prob. 21.183QPCh. 21 - Prob. 21.184QPCh. 21 - Prob. 21.185QPCh. 21 - Prob. 21.186QPCh. 21 - Prob. 21.187QPCh. 21 - Sodium perchlorate, NaClO4, is produced by...Ch. 21 - The amount of sodium hypochlorite in a bleach...Ch. 21 - Prob. 21.190QPCh. 21 - Prob. 21.191QPCh. 21 - Prob. 21.192QPCh. 21 - Prob. 21.193QPCh. 21 - Prob. 21.194QPCh. 21 - Prob. 21.195QPCh. 21 - Prob. 21.196QPCh. 21 - Prob. 21.197QPCh. 21 - Prob. 21.198QPCh. 21 - Prob. 21.199QPCh. 21 - Prob. 21.200QPCh. 21 - Prob. 21.201QPCh. 21 - Prob. 21.202QPCh. 21 - Prob. 21.203QPCh. 21 - Prob. 21.204QP
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