Chapter 2.1, Problem 1QR

To determine

Tofind: The value of $f\left(2\right)$ for $f\left(x\right)=2x^3-5x^2+4$ .

Answer to Problem 1QR

The value of $f\left(2\right)$ for $f\left(x\right)=2x^3-5x^2+4$ is $0$ .

Explanation of Solution

Given information:

The function is $f\left(x\right)=2x^3-5x^2+4$ .

Calculation:

Substitute $2$ for $x$ in the given function.

  $\begin{array}{c}f\left(x\right)=2x^3-5x^2+4\\ f\left(2\right)=2\times 2^3-5\times 2^2+4\\ f\left(2\right)=16-20+4\\ f\left(2\right)=0\end{array}$

Therefore, the value of $f\left(2\right)$ for $f\left(x\right)=2x^3-5x^2+4$ is $0$ .