Chapter 2.1, Problem 1PP

To determine

The speed of the elevator.

Answer to Problem 1PP

The required speed of the elevator is $\boxed{s=6\text{m/s}}$ .

Explanation of Solution

Given:

The distance between the first floor to the 60^th floor is $d=210\text{m}$ .

Time taken by the passenger to travel from first floor to the 60^th floor is $t=35\text{s}$ .

Formula used:

The expression of average speed is

  $s=\frac{d}{t}$.............(1)

Here, $d$ and $t$ are distance and time respectively.

Calculation:

Substitute $210\text{m}$ for $d$ and $35\text{s}$ for $t$ in equation (1)

  $\begin{array}{l}s=\frac{210\text{m}}{35\text{s}}\\ \boxed{s=6\text{m/s}}\end{array}$

Conclusion:

Hence, the required speed of the elevator is $\boxed{s=6\text{m/s}}$ .