Chapter 2, Problem 50R

To determine

To Find:Acceleration of the satellite’s.

Answer to Problem 50R

The acceleration of the satellite is $83.34{\text{m/s}}^{\text{2}}$

Explanation of Solution

Given:

Initial speed of the satellites is $5000\text{m/s}$

After $1\min$ the speed of the satellites is $10000\text{m/s}$

Formula:

Acceleration of an object is given by

  $\text{a}\text{=}\frac{d}{t^2}$

Here, $\text{a}$ is acceleration, $d$ is distance and $t$ is time.

Calculation:

Distance travel by the satellite per minute is

  $\begin{array}{l}=10000\text{m/s}\text{-}\text{5000}\text{m/s}\\ =5000\text{m/s}\end{array}$

Therefore acceleration of the satellite is

  $\begin{array}{l}=\frac{\text{5000}\text{m/s}}{\text{1}\text{min}}\\ \text{=}\frac{\text{5000}\text{m/s}}{\text{60}\text{s}}\\ =83.34\text{m/s}\end{array}$

Conclusion:

Hence, the acceleration of the satellite is $83.34{\text{m/s}}^{\text{2}}$