Applied Physics (11th Edition)
11th Edition
ISBN: 9780134159386
Author: Dale Ewen, Neill Schurter, Erik Gundersen
Publisher: PEARSON
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Chapter 2.1, Problem 1P
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A dielectric-filled parallel-plate capacitor has plate area A = 20.0 ccm2 , plate separaton d = 10.0 mm and dielectric constant k = 4.00. The capacitor is connected to a battery that creates a constant voltage V = 12.5 V . Throughout the problem, use ϵ0 = 8.85×10−12 C2/N⋅m2 . Find the energy U1 of the dielectric-filled capacitor. The dielectric plate is now slowly pulled out of the capacitor, which remains connected to the battery. Find the energy U2 of the capacitor at the moment when the capacitor is half-filled with the dielectric. The capacitor is now disconnected from the battery, and the dielectric plate is slowly removed the rest of the way out of the capacitor. Find the new energy of the capacitor, U3. In the process of removing the remaining portion of the dielectric from the disconnected capacitor, how much work W is done by the external agent acting on the dielectric?
In (Figure 1) C1 = 6.00 μF, C2 = 6.00 μF, C3 = 12.0 μF, and C4 = 3.00 μF. The capacitor network is connected to an applied potential difference Vab. After the charges on the capacitors have reached their final values, the voltage across C3 is 40.0 V. What is the voltage across C4? What is the voltage Vab applied to the network? Please explain everything in steps.
I need help with these questions again. A step by step working out with diagrams that explains more clearly
Chapter 2 Solutions
Applied Physics (11th Edition)
Ch. 2.1 - =stforSCh. 2.1 - a=tforVCh. 2.1 - w = mg for mCh. 2.1 - F = ma for aCh. 2.1 - E = IR for RCh. 2.1 - V = lwh for wCh. 2.1 - Ep = mgh for gCh. 2.1 - Ep = mgh for hCh. 2.1 - 2 = 2gh for hCh. 2.1 - XL = 2 f L for f
Ch. 2.1 - P=WtforWCh. 2.1 - p=FAforFCh. 2.1 - P=WtforiCh. 2.1 - p=FAforACh. 2.1 - Ek=12m2formCh. 2.1 - Ek=12m2Ch. 2.1 - W = Fs for SCh. 2.1 - f = i + at for aCh. 2.1 - V = E Ir for lCh. 2.1 - 2 = 1 + at for tCh. 2.1 - R=2PforPCh. 2.1 - R=kLd2forLCh. 2.1 - Prob. 23PCh. 2.1 - XC=12fCforfCh. 2.1 - R=LAforLCh. 2.1 - RT = R1 + R2 + R3 + R4 for R3Ch. 2.1 - Q1 = P(Q2 Q1) for Q2Ch. 2.1 - ISIP=NPNSforIPCh. 2.1 - VPVS=NPNSforNSCh. 2.1 - Prob. 31PCh. 2.1 - Prob. 32PCh. 2.1 - Prob. 33PCh. 2.1 - Ft=m(V2V1)forV1Ch. 2.1 - Q=I2RtJforRCh. 2.1 - x=xi+it+12at2forX1Ch. 2.1 - A = r2 for r, Where r is a radiusCh. 2.1 - V = r2h for r, Where r is a radiusCh. 2.1 - R=kLd2 for d, where d is a diameterCh. 2.1 - V=13r2h for r, where r is a radiusCh. 2.1 - Solve each formula for the quantity given. 41....Ch. 2.1 - Solve each formula for the quantity given. 42....Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.3 - Find the volume of the box in Fig. 2.3. Figure 2.3Ch. 2.3 - Find the volume of a cylinder whose height is 7.50...Ch. 2.3 - Find the volume of a cone whose height is 9.30 cm...Ch. 2.3 - Find the volume of the cylinder. Figure 2.6Ch. 2.3 - Find the cross-sectional area of the cylinder....Ch. 2.3 - Find the lateral surface area of the cylinder....Ch. 2.3 - Find the total volume of the building shown in...Ch. 2.3 - Find the cross-sectional area of the concrete...Ch. 2.3 - Find the volume of a rectangular storage facility...Ch. 2.3 - Find the cross-sectional area of a piston head...Ch. 2.3 - Find the area of a right triangle that has legs of...Ch. 2.3 - Find the length of the hypotenuse of the right...Ch. 2.3 - Find the cross-sectional area of a pipe with outer...Ch. 2.3 - Find the volume of a spherical water tank with...Ch. 2.3 - The area of a rectangular parking lot is 900m2. If...Ch. 2.3 - The volume of a rectangular crate is 192 ft3. If...Ch. 2.3 - Find the volume of a brake cylinder whose diameter...Ch. 2.3 - Find the volume of a tractor engine cylinder whose...Ch. 2.3 - A cylindrical silo has a circumference of 29.5 m....Ch. 2.3 - If the silo in Problem 19 has a capacity of...Ch. 2.3 - A wheel 30.0 cm in diameter moving along level...Ch. 2.3 - The side of the silo in Problems 19 and 20 needs...Ch. 2.3 - You are asked to design a cylindrical water tank...Ch. 2.3 - If the height of the water tank in Problem 23 were...Ch. 2.3 - A ceiling is 12.0 ft by 15.0 ft. How many...Ch. 2.3 - Find the cross-sectional area of the dovetail...Ch. 2.3 - Find tile volume of the storage bin shown in Fig....Ch. 2.3 - The maximum cross-sectional area of a spherical...Ch. 2.3 - How many cubic yards of concrete are needed to...Ch. 2.3 - What length of sidewalk 4.00 in. thick and 4.00 ft...Ch. 2.3 - Find the volume of each figure.Ch. 2.3 - Inside diameter: 20.0 cm Outside diameter: 50.0 cmCh. 2 - A formula is a. the amount of each value needed....Ch. 2 - Subscripts are a. the same as exponents. b. used...Ch. 2 - A working equation a. is derived from the basic...Ch. 2 - Cite two examples in industry in which formulas...Ch. 2 - How are subscripts used in measurement?Ch. 2 - Why is reading the problem carefully the most...Ch. 2 - How can making a sketch help in problem solving?Ch. 2 - What do we call the relationship between data that...Ch. 2 - How is a working equation different from a basic...Ch. 2 - How can analysis of the units in a problem assist...Ch. 2 - How can making an estimate of your answer assist...Ch. 2 - Solve F = ma for (a) m and (b) a.Ch. 2 - Solve =2ghforh.Ch. 2 - Solve s=12(f+i)tforf.Ch. 2 - Prob. 4RPCh. 2 - Given P = a + b + c, with P = 36 ft, a = 12 ft,...Ch. 2 - Given A=(a+b2)h, with A=210m2, b = 16.0 m, and h =...Ch. 2 - Given A = r2, if A. = 15.0 m2, find r.Ch. 2 - Given A=12bh, if b = 12.2 cm and h = 20.0 cm, what...Ch. 2 - A cone has a volume of 314 cm3 and radius of 5.00...Ch. 2 - A right triangle has a side of 41.2 mm and a side...Ch. 2 - Given a cylinder with a radius of 7 .20 cm and a...Ch. 2 - A rectangle has a perimeter of 40.0 cm. One side...Ch. 2 - The formula for the volume of a cylinder is V =...Ch. 2 - The formula for the area of a triangle is A=12bh....Ch. 2 - Find the volume of the lead sleeve with the cored...Ch. 2 - A rectangular plot of land measure 40.0 m by...Ch. 2 - You run a landscaping business and know that you...Ch. 2 - A room that measures 10.0 ft wide, 32.0 ft long,...Ch. 2 - Instead of using a solid iron beam, structural...Ch. 2 - A shipping specialist at a craft store needs to...Ch. 2 - A crane needs to lift a spool of fine steel cable...
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