Applied Physics (11th Edition)
11th Edition
ISBN: 9780134159386
Author: Dale Ewen, Neill Schurter, Erik Gundersen
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 2, Problem 1RP
Solve F = ma for (a) m and (b) a.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Find the amplitude, wavelength, period, and the speed of the wave.
A long solenoid of length 6.70 × 10-2 m and cross-sectional area 5.0 × 10-5 m² contains
6500 turns per meter of length. Determine the emf induced in the solenoid when the
current in the solenoid changes from 0 to 1.5 A during the time interval from 0 to 0.20 s.
Number
Units
A coat hanger of mass m = 0.255 kg oscillates on a peg as a physical pendulum as shown in the figure below. The distance from the pivot to the center of mass of the coat hanger is d = 18.0 cm and the period of the motion is T = 1.37 s. Find the moment of inertia of the coat hanger about the pivot.
Chapter 2 Solutions
Applied Physics (11th Edition)
Ch. 2.1 - =stforSCh. 2.1 - a=tforVCh. 2.1 - w = mg for mCh. 2.1 - F = ma for aCh. 2.1 - E = IR for RCh. 2.1 - V = lwh for wCh. 2.1 - Ep = mgh for gCh. 2.1 - Ep = mgh for hCh. 2.1 - 2 = 2gh for hCh. 2.1 - XL = 2 f L for f
Ch. 2.1 - P=WtforWCh. 2.1 - p=FAforFCh. 2.1 - P=WtforiCh. 2.1 - p=FAforACh. 2.1 - Ek=12m2formCh. 2.1 - Ek=12m2Ch. 2.1 - W = Fs for SCh. 2.1 - f = i + at for aCh. 2.1 - V = E Ir for lCh. 2.1 - 2 = 1 + at for tCh. 2.1 - R=2PforPCh. 2.1 - R=kLd2forLCh. 2.1 - Prob. 23PCh. 2.1 - XC=12fCforfCh. 2.1 - R=LAforLCh. 2.1 - RT = R1 + R2 + R3 + R4 for R3Ch. 2.1 - Q1 = P(Q2 Q1) for Q2Ch. 2.1 - ISIP=NPNSforIPCh. 2.1 - VPVS=NPNSforNSCh. 2.1 - Prob. 31PCh. 2.1 - Prob. 32PCh. 2.1 - Prob. 33PCh. 2.1 - Ft=m(V2V1)forV1Ch. 2.1 - Q=I2RtJforRCh. 2.1 - x=xi+it+12at2forX1Ch. 2.1 - A = r2 for r, Where r is a radiusCh. 2.1 - V = r2h for r, Where r is a radiusCh. 2.1 - R=kLd2 for d, where d is a diameterCh. 2.1 - V=13r2h for r, where r is a radiusCh. 2.1 - Solve each formula for the quantity given. 41....Ch. 2.1 - Solve each formula for the quantity given. 42....Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.3 - Find the volume of the box in Fig. 2.3. Figure 2.3Ch. 2.3 - Find the volume of a cylinder whose height is 7.50...Ch. 2.3 - Find the volume of a cone whose height is 9.30 cm...Ch. 2.3 - Find the volume of the cylinder. Figure 2.6Ch. 2.3 - Find the cross-sectional area of the cylinder....Ch. 2.3 - Find the lateral surface area of the cylinder....Ch. 2.3 - Find the total volume of the building shown in...Ch. 2.3 - Find the cross-sectional area of the concrete...Ch. 2.3 - Find the volume of a rectangular storage facility...Ch. 2.3 - Find the cross-sectional area of a piston head...Ch. 2.3 - Find the area of a right triangle that has legs of...Ch. 2.3 - Find the length of the hypotenuse of the right...Ch. 2.3 - Find the cross-sectional area of a pipe with outer...Ch. 2.3 - Find the volume of a spherical water tank with...Ch. 2.3 - The area of a rectangular parking lot is 900m2. If...Ch. 2.3 - The volume of a rectangular crate is 192 ft3. If...Ch. 2.3 - Find the volume of a brake cylinder whose diameter...Ch. 2.3 - Find the volume of a tractor engine cylinder whose...Ch. 2.3 - A cylindrical silo has a circumference of 29.5 m....Ch. 2.3 - If the silo in Problem 19 has a capacity of...Ch. 2.3 - A wheel 30.0 cm in diameter moving along level...Ch. 2.3 - The side of the silo in Problems 19 and 20 needs...Ch. 2.3 - You are asked to design a cylindrical water tank...Ch. 2.3 - If the height of the water tank in Problem 23 were...Ch. 2.3 - A ceiling is 12.0 ft by 15.0 ft. How many...Ch. 2.3 - Find the cross-sectional area of the dovetail...Ch. 2.3 - Find tile volume of the storage bin shown in Fig....Ch. 2.3 - The maximum cross-sectional area of a spherical...Ch. 2.3 - How many cubic yards of concrete are needed to...Ch. 2.3 - What length of sidewalk 4.00 in. thick and 4.00 ft...Ch. 2.3 - Find the volume of each figure.Ch. 2.3 - Inside diameter: 20.0 cm Outside diameter: 50.0 cmCh. 2 - A formula is a. the amount of each value needed....Ch. 2 - Subscripts are a. the same as exponents. b. used...Ch. 2 - A working equation a. is derived from the basic...Ch. 2 - Cite two examples in industry in which formulas...Ch. 2 - How are subscripts used in measurement?Ch. 2 - Why is reading the problem carefully the most...Ch. 2 - How can making a sketch help in problem solving?Ch. 2 - What do we call the relationship between data that...Ch. 2 - How is a working equation different from a basic...Ch. 2 - How can analysis of the units in a problem assist...Ch. 2 - How can making an estimate of your answer assist...Ch. 2 - Solve F = ma for (a) m and (b) a.Ch. 2 - Solve =2ghforh.Ch. 2 - Solve s=12(f+i)tforf.Ch. 2 - Prob. 4RPCh. 2 - Given P = a + b + c, with P = 36 ft, a = 12 ft,...Ch. 2 - Given A=(a+b2)h, with A=210m2, b = 16.0 m, and h =...Ch. 2 - Given A = r2, if A. = 15.0 m2, find r.Ch. 2 - Given A=12bh, if b = 12.2 cm and h = 20.0 cm, what...Ch. 2 - A cone has a volume of 314 cm3 and radius of 5.00...Ch. 2 - A right triangle has a side of 41.2 mm and a side...Ch. 2 - Given a cylinder with a radius of 7 .20 cm and a...Ch. 2 - A rectangle has a perimeter of 40.0 cm. One side...Ch. 2 - The formula for the volume of a cylinder is V =...Ch. 2 - The formula for the area of a triangle is A=12bh....Ch. 2 - Find the volume of the lead sleeve with the cored...Ch. 2 - A rectangular plot of land measure 40.0 m by...Ch. 2 - You run a landscaping business and know that you...Ch. 2 - A room that measures 10.0 ft wide, 32.0 ft long,...Ch. 2 - Instead of using a solid iron beam, structural...Ch. 2 - A shipping specialist at a craft store needs to...Ch. 2 - A crane needs to lift a spool of fine steel cable...
Additional Science Textbook Solutions
Find more solutions based on key concepts
Contrast the fertility of an allotetraploid with an autotriploid and an autotetraploid.
Concepts of Genetics (12th Edition)
You have isolated (1) a streptomycin-resistant mutant (strR) of Chlamydomonas that maps to the chloroplast geno...
Genetic Analysis: An Integrated Approach (3rd Edition)
Modified True/False 6. __________ Halophiles inhabit extremely saline habitats, such as the Great Salt Lake.
Microbiology with Diseases by Body System (5th Edition)
An obese 55-year-old woman consults her physician about minor chest pains during exercise. Explain the physicia...
Biology: Life on Earth with Physiology (11th Edition)
You microscopically examine scrapings from a case of Acan-thamoeba keratitis. You expect to see a. nothing. b. ...
Microbiology: An Introduction
What are four functions of connective tissue?
Anatomy & Physiology (6th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Review Conceptual Example 3 and the drawing as an aid in solving this problem. A conducting rod slides down between two frictionless vertical copper tracks at a constant speed of 3.9 m/s perpendicular to a 0.49-T magnetic field. The resistance of th rod and tracks is negligible. The rod maintains electrical contact with the tracks at all times and has a length of 1.4 m. A 1.1-Q resistor is attached between the tops of the tracks. (a) What is the mass of the rod? (b) Find the change in the gravitational potentia energy that occurs in a time of 0.26 s. (c) Find the electrical energy dissipated in the resistor in 0.26 s.arrow_forwardA camera lens used for taking close-up photographs has a focal length of 21.5 mm. The farthest it can be placed from the film is 34.0 mm. (a) What is the closest object (in mm) that can be photographed? 58.5 mm (b) What is the magnification of this closest object? 0.581 × ×arrow_forwardGiven two particles with Q = 4.40-µC charges as shown in the figure below and a particle with charge q = 1.40 ✕ 10−18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = ∞.) Three positively charged particles lie along the x-axis of the x y coordinate plane.Charge q is at the origin.Charge Q is at (0.800 m, 0).Another charge Q is at (−0.800 m, 0).(a)What is the net force (in N) exerted by the two 4.40-µC charges on the charge q? (Enter the magnitude.) N(b)What is the electric field (in N/C) at the origin due to the two 4.40-µC particles? (Enter the magnitude.) N/C(c)What is the electrical potential (in kV) at the origin due to the two 4.40-µC particles? kV(d)What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 4.40-µC particles?arrow_forward
- (a) Where does an object need to be placed relative to a microscope in cm from the objective lens for its 0.500 cm focal length objective to produce a magnification of -25? (Give your answer to at least three decimal places.) 0.42 × cm (b) Where should the 5.00 cm focal length eyepiece be placed in cm behind the objective lens to produce a further fourfold (4.00) magnification? 15 × cmarrow_forwardIn a LASIK vision correction, the power of a patient's eye is increased by 3.10 D. Assuming this produces normal close vision, what was the patient's near point in m before the procedure? (The power for normal close vision is 54.0 D, and the lens-to-retina distance is 2.00 cm.) 0.98 x marrow_forwardDon't use ai to answer I will report you answerarrow_forward
- A shopper standing 2.00 m from a convex security mirror sees his image with a magnification of 0.200. (Explicitly show on paper how you follow the steps in the Problem-Solving Strategy for mirrors found on page 1020. Your instructor may ask you to turn in this work.) (a) Where is his image (in m)? (Use the correct sign.) -0.4 m in front of the mirror ▾ (b) What is the focal length (in m) of the mirror? -0.5 m (c) What is its radius of curvature (in m)? -1.0 marrow_forwardAn amoeba is 0.309 cm away from the 0.304 cm focal length objective lens of a microscope.arrow_forwardTwo resistors of resistances R1 and R2, with R2>R1, are connected to a voltage source with voltage V0. When the resistors are connected in series, the current is Is. When the resistors are connected in parallel, the current Ip from the source is equal to 10Is. Let r be the ratio R1/R2. Find r. I know you have to find the equations for V for both situations and relate them, I'm just struggling to do so. Please explain all steps, thank you.arrow_forward
- Bheem and Ram, jump off either side of a bridge while holding opposite ends of a rope and swing back and forth under the bridge to save a child while avoiding a fire. Looking at the swing of just Bheem, we can approximate him as a simple pendulum with a period of motion of 5.59 s. How long is the pendulum ? When Bheem swings, he goes a full distance, from side to side, of 10.2 m. What is his maximum velocity? What is his maximum acceleration?arrow_forwardThe position of a 0.300 kg object attached to a spring is described by x=0.271 m ⋅ cos(0.512π⋅rad/s ⋅t) (Assume t is in seconds.) Find the amplitude of the motion. Find the spring constant. Find the position of the object at t = 0.324 s. Find the object's velocity at t = 0.324 s.arrow_forwardMin Min is hanging from her spring-arms off the edge of the level. Due to the spring like nature of her arms she is bouncing up and down in simple harmonic motion with a maximum displacement from equilibrium of 0.118 m. The spring constant of Min-Min’s arms is 9560. N/m and she has a mass of 87.5 kg. What is the period at which she oscillates? Find her maximum speed. Find her speed when she is located 5.00 cm from her equilibrium position.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice University
College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Introduction to Vectors and Their Operations; Author: Professor Dave Explains;https://www.youtube.com/watch?v=KBSCMTYaH1s;License: Standard YouTube License, CC-BY