Applied Physics (11th Edition)
11th Edition
ISBN: 9780134159386
Author: Dale Ewen, Neill Schurter, Erik Gundersen
Publisher: PEARSON
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Chapter 2.1, Problem 25P
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Question: For a liquid with typical values
a = 10-3K-¹
K = 10-4 bar-1
V=50 cm³ mol-1,
Cp 200 J mol-1K-1,
calculate the following quantities at 300 K and 1 bar for one mole of gas:
1. () P
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2. (9) T
3. (V) T
4. (1) P
5. (9) T
6. Cv
7. (OF)T
A,B,C AND D
A bungee jumper plans to bungee jump from a bridge 64.0 m above the ground. He plans to use a uniform elastic cord, tied to a harness around his body, to stop his fall at a point 6.00 m above the water. Model his body as a particle and the cord as having negligible mass and obeying
Hooke's law. In a preliminary test he finds that when hanging at rest from a 5.00 m length of the cord, his body weight stretches it by 1.55 m. He will drop from rest at the point where the top end of a longer section of the cord is attached to the bridge.
(a) What length of cord should he use?
Use subscripts 1 and 2 respectively to represent the 5.00 m test length and the actual jump length. Use Hooke's law F = KAL and the fact that the change in length AL for a given force is proportional the length L (AL = CL), to determine the force constant for the test case and for the
jump case. Use conservation of mechanical energy to determine the length of the rope. m
(b) What maximum acceleration will he…
Chapter 2 Solutions
Applied Physics (11th Edition)
Ch. 2.1 - =stforSCh. 2.1 - a=tforVCh. 2.1 - w = mg for mCh. 2.1 - F = ma for aCh. 2.1 - E = IR for RCh. 2.1 - V = lwh for wCh. 2.1 - Ep = mgh for gCh. 2.1 - Ep = mgh for hCh. 2.1 - 2 = 2gh for hCh. 2.1 - XL = 2 f L for f
Ch. 2.1 - P=WtforWCh. 2.1 - p=FAforFCh. 2.1 - P=WtforiCh. 2.1 - p=FAforACh. 2.1 - Ek=12m2formCh. 2.1 - Ek=12m2Ch. 2.1 - W = Fs for SCh. 2.1 - f = i + at for aCh. 2.1 - V = E Ir for lCh. 2.1 - 2 = 1 + at for tCh. 2.1 - R=2PforPCh. 2.1 - R=kLd2forLCh. 2.1 - Prob. 23PCh. 2.1 - XC=12fCforfCh. 2.1 - R=LAforLCh. 2.1 - RT = R1 + R2 + R3 + R4 for R3Ch. 2.1 - Q1 = P(Q2 Q1) for Q2Ch. 2.1 - ISIP=NPNSforIPCh. 2.1 - VPVS=NPNSforNSCh. 2.1 - Prob. 31PCh. 2.1 - Prob. 32PCh. 2.1 - Prob. 33PCh. 2.1 - Ft=m(V2V1)forV1Ch. 2.1 - Q=I2RtJforRCh. 2.1 - x=xi+it+12at2forX1Ch. 2.1 - A = r2 for r, Where r is a radiusCh. 2.1 - V = r2h for r, Where r is a radiusCh. 2.1 - R=kLd2 for d, where d is a diameterCh. 2.1 - V=13r2h for r, where r is a radiusCh. 2.1 - Solve each formula for the quantity given. 41....Ch. 2.1 - Solve each formula for the quantity given. 42....Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.2 - For each formula, (a) solve for the indicated...Ch. 2.3 - Find the volume of the box in Fig. 2.3. Figure 2.3Ch. 2.3 - Find the volume of a cylinder whose height is 7.50...Ch. 2.3 - Find the volume of a cone whose height is 9.30 cm...Ch. 2.3 - Find the volume of the cylinder. Figure 2.6Ch. 2.3 - Find the cross-sectional area of the cylinder....Ch. 2.3 - Find the lateral surface area of the cylinder....Ch. 2.3 - Find the total volume of the building shown in...Ch. 2.3 - Find the cross-sectional area of the concrete...Ch. 2.3 - Find the volume of a rectangular storage facility...Ch. 2.3 - Find the cross-sectional area of a piston head...Ch. 2.3 - Find the area of a right triangle that has legs of...Ch. 2.3 - Find the length of the hypotenuse of the right...Ch. 2.3 - Find the cross-sectional area of a pipe with outer...Ch. 2.3 - Find the volume of a spherical water tank with...Ch. 2.3 - The area of a rectangular parking lot is 900m2. If...Ch. 2.3 - The volume of a rectangular crate is 192 ft3. If...Ch. 2.3 - Find the volume of a brake cylinder whose diameter...Ch. 2.3 - Find the volume of a tractor engine cylinder whose...Ch. 2.3 - A cylindrical silo has a circumference of 29.5 m....Ch. 2.3 - If the silo in Problem 19 has a capacity of...Ch. 2.3 - A wheel 30.0 cm in diameter moving along level...Ch. 2.3 - The side of the silo in Problems 19 and 20 needs...Ch. 2.3 - You are asked to design a cylindrical water tank...Ch. 2.3 - If the height of the water tank in Problem 23 were...Ch. 2.3 - A ceiling is 12.0 ft by 15.0 ft. How many...Ch. 2.3 - Find the cross-sectional area of the dovetail...Ch. 2.3 - Find tile volume of the storage bin shown in Fig....Ch. 2.3 - The maximum cross-sectional area of a spherical...Ch. 2.3 - How many cubic yards of concrete are needed to...Ch. 2.3 - What length of sidewalk 4.00 in. thick and 4.00 ft...Ch. 2.3 - Find the volume of each figure.Ch. 2.3 - Inside diameter: 20.0 cm Outside diameter: 50.0 cmCh. 2 - A formula is a. the amount of each value needed....Ch. 2 - Subscripts are a. the same as exponents. b. used...Ch. 2 - A working equation a. is derived from the basic...Ch. 2 - Cite two examples in industry in which formulas...Ch. 2 - How are subscripts used in measurement?Ch. 2 - Why is reading the problem carefully the most...Ch. 2 - How can making a sketch help in problem solving?Ch. 2 - What do we call the relationship between data that...Ch. 2 - How is a working equation different from a basic...Ch. 2 - How can analysis of the units in a problem assist...Ch. 2 - How can making an estimate of your answer assist...Ch. 2 - Solve F = ma for (a) m and (b) a.Ch. 2 - Solve =2ghforh.Ch. 2 - Solve s=12(f+i)tforf.Ch. 2 - Prob. 4RPCh. 2 - Given P = a + b + c, with P = 36 ft, a = 12 ft,...Ch. 2 - Given A=(a+b2)h, with A=210m2, b = 16.0 m, and h =...Ch. 2 - Given A = r2, if A. = 15.0 m2, find r.Ch. 2 - Given A=12bh, if b = 12.2 cm and h = 20.0 cm, what...Ch. 2 - A cone has a volume of 314 cm3 and radius of 5.00...Ch. 2 - A right triangle has a side of 41.2 mm and a side...Ch. 2 - Given a cylinder with a radius of 7 .20 cm and a...Ch. 2 - A rectangle has a perimeter of 40.0 cm. One side...Ch. 2 - The formula for the volume of a cylinder is V =...Ch. 2 - The formula for the area of a triangle is A=12bh....Ch. 2 - Find the volume of the lead sleeve with the cored...Ch. 2 - A rectangular plot of land measure 40.0 m by...Ch. 2 - You run a landscaping business and know that you...Ch. 2 - A room that measures 10.0 ft wide, 32.0 ft long,...Ch. 2 - Instead of using a solid iron beam, structural...Ch. 2 - A shipping specialist at a craft store needs to...Ch. 2 - A crane needs to lift a spool of fine steel cable...
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