(a) Interpretation: The glycosidic linkage in cellobiose should be located. Concept Introduction: Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Question

Want to see the full answer?

Answer 1

Question

Chapter 20.5, Problem 20.7PP

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Viscosity of a liquid related to the activation energy.

Vibrational contributions to internal energy and heat capacity1) are temperature independent2) are temperature dependent

The approximation of calculating the partition function by integration instead of the summation of all the energy terms can only be done if the separation of the energy levels is much smaller than the product kT. Explain why.

Answer 2

Question

Chapter 20.5, Problem 20.7PP

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 20.5, Problem 20.7PP

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 20.5, Problem 20.7PP

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 20.5, Problem 20.7PP

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

Answer 6

Chapter 20.5, Problem 20.7PP

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Answer 7

Chapter 20.5, Problem 20.7PP

Interpretation Introduction

(a)

Interpretation:

The glycosidic linkage in cellobiose should be located.

Concept Introduction:

Disaccharides are carbohydrate produced by the combination of two monosaccharides. Disaccharides are acetals. Monosaccharide contains hemiacetal. When a hemiacetal hydroxyl group is reacted with a hydroxyl group of another monosaccharide, a disaccharide is yielded.

Answer 8

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Answer 9

Interpretation Introduction

(b)

Interpretation:

Carbon atoms in both rings should be numbered.

Concept Introduction:

When numbering carbons in a cyclic carbohydrate, the numbering starts at acetal or hemiacetal carbon that means at the anomeric carbon, giving it the number 1. And the numbering continues clockwise. O atom in the ring is not given a number.

Answer 10

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

Answer 11

Interpretation Introduction

(c)

Interpretation:

The glycosidic linkage should be classified as a and β and the location of the linkage should be designated using the numbers.

Concept Introduction:

If the glycosidic linkage is oriented down or below the plane of the ring then it is an a glycoside. If the glycosidic linkage is oriented up, above the plane of the ring, then it is a β-glycoside.

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 15

Ch. 20.1 - Label the hemiacetal carbonthe carbon bonded to...Ch. 20.2 - Prob. 20.1PP Ch. 20.2 - Prob. 20.2P Ch. 20.2 - Prob. 20.3P Ch. 20.2 - Prob. 20.4P Ch. 20.2 - Prob. 20.5P Ch. 20.2 - Prob. 20.2PP Ch. 20.2 - Prob. 20.6P Ch. 20.2 - Prob. 20.7P Ch. 20.3 - Prob. 20.8P

Solution Summary: The author explains that the glycosidic linkage in cellobiose should be located.

Concept explainers

Want to see the full answer?

Chapter 20 Solutions