
General Chemistry
11th Edition
ISBN: 9781305859142
Author: Ebbing, Darrell D., Gammon, Steven D.
Publisher: Cengage Learning,
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Question
Chapter 20.4, Problem 20.7E
Interpretation Introduction
Interpretation:
The decay constant (inunit of /s) for given sample has to be determined.
Concept introduction:
The decay constant (k) is independent of the quantity of radioactive material however depends only on the character of the nuclide. Various nuclides have various decay constants. The degree of radioactive decay depends on the decay constant and number of radioactive nuclei at specific time (
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Chapter 20 Solutions
General Chemistry
Ch. 20.1 - Prob. 20.1ECh. 20.1 - Prob. 20.2ECh. 20.1 - Prob. 20.3ECh. 20.1 - Prob. 20.4ECh. 20.1 - Prob. 20.1CCCh. 20.2 - Prob. 20.5ECh. 20.2 - Prob. 20.6ECh. 20.3 - Prob. 20.2CCCh. 20.4 - Prob. 20.7ECh. 20.4 - Prob. 20.8E
Ch. 20.4 - Prob. 20.9ECh. 20.4 - Prob. 20.10ECh. 20.4 - Prob. 20.11ECh. 20.4 - Prob. 20.3CCCh. 20.6 - Prob. 20.12ECh. 20 - Prob. 20.1QPCh. 20 - Prob. 20.2QPCh. 20 - Prob. 20.3QPCh. 20 - Prob. 20.4QPCh. 20 - Prob. 20.5QPCh. 20 - Prob. 20.6QPCh. 20 - Prob. 20.7QPCh. 20 - Prob. 20.8QPCh. 20 - Prob. 20.9QPCh. 20 - Prob. 20.10QPCh. 20 - Prob. 20.11QPCh. 20 - Prob. 20.12QPCh. 20 - Prob. 20.13QPCh. 20 - Prob. 20.14QPCh. 20 - Prob. 20.15QPCh. 20 - Prob. 20.16QPCh. 20 - Prob. 20.17QPCh. 20 - Prob. 20.18QPCh. 20 - Prob. 20.19QPCh. 20 - Prob. 20.20QPCh. 20 - Prob. 20.21QPCh. 20 - Prob. 20.22QPCh. 20 - Prob. 20.23QPCh. 20 - Prob. 20.24QPCh. 20 - Prob. 20.25QPCh. 20 - Prob. 20.26QPCh. 20 - Prob. 20.27QPCh. 20 - Prob. 20.28QPCh. 20 - Prob. 20.29QPCh. 20 - Prob. 20.30QPCh. 20 - Prob. 20.31QPCh. 20 - Prob. 20.32QPCh. 20 - Prob. 20.33QPCh. 20 - Prob. 20.34QPCh. 20 - Prob. 20.35QPCh. 20 - Prob. 20.36QPCh. 20 - Prob. 20.37QPCh. 20 - Prob. 20.38QPCh. 20 - Prob. 20.39QPCh. 20 - Prob. 20.40QPCh. 20 - Prob. 20.41QPCh. 20 - Prob. 20.42QPCh. 20 - Prob. 20.43QPCh. 20 - Prob. 20.44QPCh. 20 - Prob. 20.45QPCh. 20 - Prob. 20.46QPCh. 20 - Prob. 20.47QPCh. 20 - Prob. 20.48QPCh. 20 - Prob. 20.49QPCh. 20 - Prob. 20.50QPCh. 20 - Prob. 20.51QPCh. 20 - Prob. 20.52QPCh. 20 - Fill in the missing parts of the following...Ch. 20 - Fill in the missing parts of the following...Ch. 20 - Prob. 20.55QPCh. 20 - Prob. 20.56QPCh. 20 - Prob. 20.57QPCh. 20 - Prob. 20.58QPCh. 20 - Prob. 20.59QPCh. 20 - Prob. 20.60QPCh. 20 - Prob. 20.61QPCh. 20 - Prob. 20.62QPCh. 20 - Prob. 20.63QPCh. 20 - Prob. 20.64QPCh. 20 - Prob. 20.65QPCh. 20 - Prob. 20.66QPCh. 20 - Prob. 20.67QPCh. 20 - Prob. 20.68QPCh. 20 - Prob. 20.69QPCh. 20 - Prob. 20.70QPCh. 20 - Prob. 20.71QPCh. 20 - Prob. 20.72QPCh. 20 - Prob. 20.73QPCh. 20 - Prob. 20.74QPCh. 20 - Prob. 20.75QPCh. 20 - Prob. 20.76QPCh. 20 - Prob. 20.77QPCh. 20 - Prob. 20.78QPCh. 20 - Find the change of mass (in grams) resulting from...Ch. 20 - Find the change of mass (in grams) resulting from...Ch. 20 - Prob. 20.81QPCh. 20 - Prob. 20.82QPCh. 20 - Prob. 20.83QPCh. 20 - Prob. 20.84QPCh. 20 - Prob. 20.85QPCh. 20 - Prob. 20.86QPCh. 20 - Prob. 20.87QPCh. 20 - Prob. 20.88QPCh. 20 - Prob. 20.89QPCh. 20 - Prob. 20.90QPCh. 20 - Prob. 20.91QPCh. 20 - Prob. 20.92QPCh. 20 - Prob. 20.93QPCh. 20 - Prob. 20.94QPCh. 20 - Prob. 20.95QPCh. 20 - Prob. 20.96QPCh. 20 - Prob. 20.97QPCh. 20 - Prob. 20.98QPCh. 20 - Prob. 20.99QPCh. 20 - Prob. 20.100QPCh. 20 - Prob. 20.101QPCh. 20 - Prob. 20.102QPCh. 20 - Prob. 20.103QPCh. 20 - Prob. 20.104QPCh. 20 - Prob. 20.105QPCh. 20 - Prob. 20.106QPCh. 20 - Prob. 20.107QPCh. 20 - Prob. 20.108QPCh. 20 - Prob. 20.109QPCh. 20 - Prob. 20.110QPCh. 20 - Prob. 20.111QPCh. 20 - Prob. 20.112QPCh. 20 - Prob. 20.113QPCh. 20 - Prob. 20.114QPCh. 20 - Prob. 20.115QPCh. 20 - Prob. 20.116QPCh. 20 - Prob. 20.117QPCh. 20 - Prob. 20.118QPCh. 20 - Prob. 20.119QPCh. 20 - Prob. 20.120QPCh. 20 - Prob. 20.121QPCh. 20 - Prob. 20.122QPCh. 20 - Prob. 20.123QPCh. 20 - Prob. 20.124QPCh. 20 - Prob. 20.125QPCh. 20 - Prob. 20.126QPCh. 20 - Prob. 20.127QPCh. 20 - Prob. 20.128QP
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- If the energy absorbed per mole of gas is 480 kJ mol-1, indicate the number of Einsteins per mole.arrow_forwardThe quantum yield of the photochemical decay of HI is 2. Calculating the moles of HI per kJ of radiant energy can be decayed knowing that the energy absorbed per mole of photons is 490 kJ.arrow_forwardThe quantum yield of the photochemical decay of HI is 2. Calculate the number of Einsteins absorbed per mole knowing that the energy absorbed per mole of photons is 490 kJ.arrow_forward
- The quantum yield of the photochemical decay of HI is 2. How many moles of HI per kJ of radiant energy can be decayed knowing that the energy absorbed per mole of photons is 490 kJ.arrow_forwardIf the energy absorbed per mole of photons is 450 kJ, the number of Einsteins absorbed per 1 mole.arrow_forwardWhen propionic aldehyde in vapor form at 200 mmHg and 30°C is irradiated with radiation of wavelength 302 nm, the quantum yield with respect to the formation of CO is 0.54. If the intensity of the incident radiation is 1.5x10-3 W, find the rate of formation of CO.arrow_forward
- If the dissociation energy of one mole of O2 is 5.17 eV, determine the wavelength that must be used to dissociate it with electromagnetic radiation. Indicate how many Einstein's of this radiation are needed to dissociate 1 liter of O2 at 25°C and 1 atm of pressure.Data: 1 eV = 96485 kJ mol-1; R = 0.082 atm L K-1; c = 2.998x108 m s-1; h = 6.626x10-34 J s; NA = 6.022x 1023 mol-1arrow_forwardIndicate the number of Einsteins that are equivalent to 550 kJ mol⁻¹ of absorbed energy (wavelength 475 nm).arrow_forwardIndicate the number of einsteins that are equivalent to 550 kJ mol⁻¹ of absorbed energy?arrow_forward
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