Sodium isotope is only occurring in nature which is does not radioactive. Mass defect of Sodium has to be calculated.

Question

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Answer 1

Question

Chapter 20, Problem 20.122QP

(a)

Interpretation Introduction

Interpretation:

Sodium isotope is only occurring in nature which is does not radioactive.

Mass defect of Sodium has to be calculated.

(a)

Expert Solution

Answer to Problem 20.122QP

Mass defect of Sodium is $0.2003297 amu$ .

Explanation of Solution

To calculate: Mass defect of Sodium

Atomic mass of $Na$ = $22.99 amu$

$Mass of eleven protons =11×1.00728 amu = 11.08008 amuMass oftwelveneutrons=12×1.008665 amu =12.10398 amuTotal mass of nucleons =(11.08008+12.10398) amu =22.98373029 amu$

$Nuclear mass of 1123Na = 22.98976929 amu - (11× 0.000549 amu) = 22.98373029 amu$

$Mass defect = total mass - nuclear mass =(23.18406-22.98373029)amu = 0.2003297amu$

(b)

Interpretation Introduction

Interpretation:

Sodium isotope is only occurring in nature which is does not radioactive.

The nuclear binding energy of Sodium nucleon in $MeV$ has to be calculated.

(b)

Expert Solution

Answer to Problem 20.122QP

The nuclear binding energy of Sodium nucleon is $186.64 MeV$ .

Explanation of Solution

To calculate: nuclear binding energy of Sodium nucleon

$ΔE = (Δm)c2 = 0.2003297amu ×1g6.022×1023×1amu×1kg103g ×(2.998×108m/s)2×1MeV1.602×10-13J =186.64 MeVBinding energy per nucleon =186.64 MeV23nucleons =8.115MeV/nucleon$

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Answer 2

Question

Chapter 20, Problem 20.122QP

(a)

Interpretation Introduction

Interpretation:

Sodium isotope is only occurring in nature which is does not radioactive.

Mass defect of Sodium has to be calculated.

(a)

Expert Solution

Answer to Problem 20.122QP

Mass defect of Sodium is $0.2003297 amu$ .

Explanation of Solution

To calculate: Mass defect of Sodium

Atomic mass of $Na$ = $22.99 amu$

$Mass of eleven protons =11×1.00728 amu = 11.08008 amuMass oftwelveneutrons=12×1.008665 amu =12.10398 amuTotal mass of nucleons =(11.08008+12.10398) amu =22.98373029 amu$

$Nuclear mass of 1123Na = 22.98976929 amu - (11× 0.000549 amu) = 22.98373029 amu$

$Mass defect = total mass - nuclear mass =(23.18406-22.98373029)amu = 0.2003297amu$

(b)

Interpretation Introduction

Interpretation:

Sodium isotope is only occurring in nature which is does not radioactive.

The nuclear binding energy of Sodium nucleon in $MeV$ has to be calculated.

(b)

Expert Solution

Answer to Problem 20.122QP

The nuclear binding energy of Sodium nucleon is $186.64 MeV$ .

Explanation of Solution

To calculate: nuclear binding energy of Sodium nucleon

$ΔE = (Δm)c2 = 0.2003297amu ×1g6.022×1023×1amu×1kg103g ×(2.998×108m/s)2×1MeV1.602×10-13J =186.64 MeVBinding energy per nucleon =186.64 MeV23nucleons =8.115MeV/nucleon$

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Answer 3

Question

Chapter 20, Problem 20.122QP

(a)

Interpretation Introduction

Interpretation:

Sodium isotope is only occurring in nature which is does not radioactive.

Mass defect of Sodium has to be calculated.

(a)

Expert Solution

Answer to Problem 20.122QP

Mass defect of Sodium is $0.2003297 amu$ .

Explanation of Solution

To calculate: Mass defect of Sodium

Atomic mass of $Na$ = $22.99 amu$

$Mass of eleven protons =11×1.00728 amu = 11.08008 amuMass oftwelveneutrons=12×1.008665 amu =12.10398 amuTotal mass of nucleons =(11.08008+12.10398) amu =22.98373029 amu$

$Nuclear mass of 1123Na = 22.98976929 amu - (11× 0.000549 amu) = 22.98373029 amu$

$Mass defect = total mass - nuclear mass =(23.18406-22.98373029)amu = 0.2003297amu$

(b)

Interpretation Introduction

Interpretation:

Sodium isotope is only occurring in nature which is does not radioactive.

The nuclear binding energy of Sodium nucleon in $MeV$ has to be calculated.

(b)

Expert Solution

Answer to Problem 20.122QP

The nuclear binding energy of Sodium nucleon is $186.64 MeV$ .

Explanation of Solution

To calculate: nuclear binding energy of Sodium nucleon

$ΔE = (Δm)c2 = 0.2003297amu ×1g6.022×1023×1amu×1kg103g ×(2.998×108m/s)2×1MeV1.602×10-13J =186.64 MeVBinding energy per nucleon =186.64 MeV23nucleons =8.115MeV/nucleon$

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Answer 4

Question

Chapter 20, Problem 20.122QP

(a)

Interpretation Introduction

Interpretation:

Sodium isotope is only occurring in nature which is does not radioactive.

Mass defect of Sodium has to be calculated.

(a)

Expert Solution

Answer to Problem 20.122QP

Mass defect of Sodium is $0.2003297 amu$ .

Explanation of Solution

To calculate: Mass defect of Sodium

Atomic mass of $Na$ = $22.99 amu$

$Mass of eleven protons =11×1.00728 amu = 11.08008 amuMass oftwelveneutrons=12×1.008665 amu =12.10398 amuTotal mass of nucleons =(11.08008+12.10398) amu =22.98373029 amu$

$Nuclear mass of 1123Na = 22.98976929 amu - (11× 0.000549 amu) = 22.98373029 amu$

$Mass defect = total mass - nuclear mass =(23.18406-22.98373029)amu = 0.2003297amu$

(b)

Interpretation Introduction

Interpretation:

Sodium isotope is only occurring in nature which is does not radioactive.

The nuclear binding energy of Sodium nucleon in $MeV$ has to be calculated.

(b)

Expert Solution

Answer to Problem 20.122QP

The nuclear binding energy of Sodium nucleon is $186.64 MeV$ .

Explanation of Solution

To calculate: nuclear binding energy of Sodium nucleon

$ΔE = (Δm)c2 = 0.2003297amu ×1g6.022×1023×1amu×1kg103g ×(2.998×108m/s)2×1MeV1.602×10-13J =186.64 MeVBinding energy per nucleon =186.64 MeV23nucleons =8.115MeV/nucleon$

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Answer 5

Chapter 20, Problem 20.122QP

(a)

Interpretation Introduction

Interpretation:

Sodium isotope is only occurring in nature which is does not radioactive.

Mass defect of Sodium has to be calculated.

(a)

Expert Solution

Answer to Problem 20.122QP

Mass defect of Sodium is $0.2003297 amu$ .

Explanation of Solution

To calculate: Mass defect of Sodium

Atomic mass of $Na$ = $22.99 amu$

$Mass of eleven protons =11×1.00728 amu = 11.08008 amuMass oftwelveneutrons=12×1.008665 amu =12.10398 amuTotal mass of nucleons =(11.08008+12.10398) amu =22.98373029 amu$

$Nuclear mass of 1123Na = 22.98976929 amu - (11× 0.000549 amu) = 22.98373029 amu$

$Mass defect = total mass - nuclear mass =(23.18406-22.98373029)amu = 0.2003297amu$

(b)

Interpretation Introduction

Interpretation:

Sodium isotope is only occurring in nature which is does not radioactive.

The nuclear binding energy of Sodium nucleon in $MeV$ has to be calculated.

(b)

Expert Solution

Answer to Problem 20.122QP

The nuclear binding energy of Sodium nucleon is $186.64 MeV$ .

Explanation of Solution

To calculate: nuclear binding energy of Sodium nucleon

$ΔE = (Δm)c2 = 0.2003297amu ×1g6.022×1023×1amu×1kg103g ×(2.998×108m/s)2×1MeV1.602×10-13J =186.64 MeVBinding energy per nucleon =186.64 MeV23nucleons =8.115MeV/nucleon$

Answer 6

Chapter 20, Problem 20.122QP

(a)

Interpretation Introduction

Interpretation:

Sodium isotope is only occurring in nature which is does not radioactive.

Mass defect of Sodium has to be calculated.

(a)

Expert Solution

Answer to Problem 20.122QP

Mass defect of Sodium is $0.2003297 amu$ .

Explanation of Solution

To calculate: Mass defect of Sodium

Atomic mass of $Na$ = $22.99 amu$

$Mass of eleven protons =11×1.00728 amu = 11.08008 amuMass oftwelveneutrons=12×1.008665 amu =12.10398 amuTotal mass of nucleons =(11.08008+12.10398) amu =22.98373029 amu$

$Nuclear mass of 1123Na = 22.98976929 amu - (11× 0.000549 amu) = 22.98373029 amu$

$Mass defect = total mass - nuclear mass =(23.18406-22.98373029)amu = 0.2003297amu$

Answer 7

Chapter 20, Problem 20.122QP

(a)

Interpretation Introduction

Interpretation:

Sodium isotope is only occurring in nature which is does not radioactive.

Mass defect of Sodium has to be calculated.

Answer 8

(a)

Expert Solution

Answer to Problem 20.122QP

Mass defect of Sodium is $0.2003297 amu$ .

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

To calculate: Mass defect of Sodium

Atomic mass of $Na$ = $22.99 amu$

$Mass of eleven protons =11×1.00728 amu = 11.08008 amuMass oftwelveneutrons=12×1.008665 amu =12.10398 amuTotal mass of nucleons =(11.08008+12.10398) amu =22.98373029 amu$

$Nuclear mass of 1123Na = 22.98976929 amu - (11× 0.000549 amu) = 22.98373029 amu$

$Mass defect = total mass - nuclear mass =(23.18406-22.98373029)amu = 0.2003297amu$

Answer 13

(b)

Interpretation Introduction

Interpretation:

Sodium isotope is only occurring in nature which is does not radioactive.

The nuclear binding energy of Sodium nucleon in $MeV$ has to be calculated.

(b)

Expert Solution

Answer to Problem 20.122QP

The nuclear binding energy of Sodium nucleon is $186.64 MeV$ .

Explanation of Solution

To calculate: nuclear binding energy of Sodium nucleon

$ΔE = (Δm)c2 = 0.2003297amu ×1g6.022×1023×1amu×1kg103g ×(2.998×108m/s)2×1MeV1.602×10-13J =186.64 MeVBinding energy per nucleon =186.64 MeV23nucleons =8.115MeV/nucleon$

Answer 14

(b)

Interpretation Introduction

Interpretation:

Sodium isotope is only occurring in nature which is does not radioactive.

The nuclear binding energy of Sodium nucleon in $MeV$ has to be calculated.

Answer 15

(b)

Expert Solution

Answer to Problem 20.122QP

The nuclear binding energy of Sodium nucleon is $186.64 MeV$ .

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

To calculate: nuclear binding energy of Sodium nucleon

$ΔE = (Δm)c2 = 0.2003297amu ×1g6.022×1023×1amu×1kg103g ×(2.998×108m/s)2×1MeV1.602×10-13J =186.64 MeVBinding energy per nucleon =186.64 MeV23nucleons =8.115MeV/nucleon$

Answer 20

Ch. 20.1 - Prob. 20.1E Ch. 20.1 - Prob. 20.2E Ch. 20.1 - Prob. 20.3E Ch. 20.1 - Prob. 20.4E Ch. 20.1 - Prob. 20.1CC Ch. 20.2 - Prob. 20.5E Ch. 20.2 - Prob. 20.6E Ch. 20.3 - Prob. 20.2CC Ch. 20.4 - Prob. 20.7E Ch. 20.4 - Prob. 20.8E

Sodium isotope is only occurring in nature which is does not radioactive. Mass defect of Sodium has to be calculated.

Concept explainers

Interpretation:

Sodium isotope is only occurring in nature which is does not radioactive.

Mass defect of Sodium has to be calculated.

Answer to Problem 20.122QP

Explanation of Solution

Interpretation:

Sodium isotope is only occurring in nature which is does not radioactive.

The nuclear binding energy of Sodium nucleon in $MeV$ has to be calculated.

Answer to Problem 20.122QP

Explanation of Solution

Want to see more full solutions like this?

Chapter 20 Solutions

Sodium isotope is only occurring in nature which is does not radioactive. Mass defect of Sodium has to be calculated.

Concept explainers

Interpretation: Sodium isotope is only occurring in nature which is does not radioactive. Mass defect of Sodium has to be calculated.

Answer to Problem 20.122QP

Explanation of Solution

Interpretation: Sodium isotope is only occurring in nature which is does not radioactive. The nuclear binding energy of Sodium nucleon in MeV<m:math><m:mrow><m:mtext>MeV</m:mtext></m:mrow> </m:math> has to be calculated.

Answer to Problem 20.122QP

Explanation of Solution

Want to see more full solutions like this?

Chapter 20 Solutions

Interpretation:

Sodium isotope is only occurring in nature which is does not radioactive.

Mass defect of Sodium has to be calculated.

Interpretation:

Sodium isotope is only occurring in nature which is does not radioactive.

The nuclear binding energy of Sodium nucleon in $MeV$ has to be calculated.