Starting Out with C++ from Control Structures to Objects (8th Edition)
Starting Out with C++ from Control Structures to Objects (8th Edition)
8th Edition
ISBN: 9780133769395
Author: Tony Gaddis
Publisher: PEARSON
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Chapter 20, Problem 9RQE

A node without child is referred a “leaf node”.

Program Plan Intro

Binary tree:

A complete binary tree is a binary tree with the property that every node must have exactly two children, and at the last level the nodes should be from left to right.

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Computer Science lab3.h ------------- #include<stdio.h> #include<stdlib.h> #ifndef LAB3_H #define LAB3_H // A linked list node struct Node { int data; //Data struct Node *next; // Address to the next node }; //initialize: create an empty head node (whose "data" is intentionally missing); This head node will not be used to store any data; struct Node *init () { //create head node struct Node *head = (struct Node*)malloc(sizeof(struct Node)); } //Create a new node to store data and insert it to the end of current linked list; the head node will still be empty and data in the array in "main.c" are not stored in head node void insert(struct node *head, int data) { struct Node *newNode = (struct Node*)malloc(sizeof(struct Node));   new_node->data = data; new_node->next= head; } //print data for all nodes in the linked list except the head node (which is empty) void display (struct Node *head) { struct Node *current_node = head; while ( current_node != NULL) { printf("%d ",…
class Graph:    def __init__(self, num_nodes):        self.num_nodes = num_nodes        # Initialize a 2D matrix with zeros        self.adj_matrix = [[0] * num_nodes for _ in range(num_nodes)]     def add_edge(self, node1, node2):        # Add an undirected edge between node1 and node2        self.adj_matrix[node1][node2] = 1        self.adj_matrix[node2][node1] = 1     def remove_edge(self, node1, node2):        # Remove the edge between node1 and node2        self.adj_matrix[node1][node2] = 0        self.adj_matrix[node2][node1] = 0     def num_edges(self):        num_edges = 1        for i in range(self.num_nodes):            for j in range(i+1, self.num_nodes):                if self.adj_matrix[i][j] == 1:                    num_edges += 1        return num_edges     def num_edges_in_set(self, node, subset):        # count the number of edges joining the given node and nodes in subset.        # example input: 1, {0, 2}        num_edges = 0        for s in subset:            if…
typedef struct node{int data;struct node *left,*right;}BST;The node structure of BST is shown above. Please design an efficient algorithm to return the maximum keyword value in BST. Completion function: int findmax (BST *T)
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