Starting Out with C++ from Control Structures to Objects (8th Edition)
Starting Out with C++ from Control Structures to Objects (8th Edition)
8th Edition
ISBN: 9780133769395
Author: Tony Gaddis
Publisher: PEARSON
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Chapter 20, Problem 9RQE

A node without child is referred a “leaf node”.

Program Plan Intro

Binary tree:

A complete binary tree is a binary tree with the property that every node must have exactly two children, and at the last level the nodes should be from left to right.

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Fill-in-the-Blank In a(n) __________ list, each node has a pointer to the one before it and the one after it.
#ifndef BT_NODE_H#define BT_NODE_H struct btNode{   int data;   btNode* left;   btNode* right;}; // pre:  bst_root is root pointer of a binary search tree (may be 0 for//       empty tree) and portArray has the base address of an array large//       enough to hold all the data items in the binary search tree// post: The binary search tree has been traversed in-order and the data//       values are written (as they are encountered) to portArray in//       increasing positional order starting from the first elementvoid portToArrayInOrder(btNode* bst_root, int* portArray);void portToArrayInOrderAux(btNode* bst_root, int* portArray, int& portIndex); // pre:  (none)// post: dynamic memory of all the nodes of the tree rooted at root has been//       freed up (returned back to heap/freestore) and the tree is now empty//       (root pointer contains the null address)void tree_clear(btNode*& root); // pre:  (none)// post: # of nodes contained in tree rooted at root is returnedint…
Assume the tree node structure is following........ struct node { int data; struct node* left; struct node* right; }; struct node *root = null; and there is a created new node function, called newnode(int new_data). Please filled the Blank of Insertion function. void insert(struct node *root, int key) { struct node *current; queue q; q.enque(root); while(!q.empty() } current = q.front(); q.deque(); if(current->left == NULL) { break; } else } q.enque( if(current->right == NULL) { break; else q.enque(_ = newnode(key); = newnode(key); _-));
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