Chapter 20, Problem 83RQ

Interpretation Introduction

Interpretation:

The distance covered to reduce the exposure to $0.28$ units, if it is provided that a radiologist at a distance of $2.0\text{m}$ receives a radiation of $2.8$ units, is to be determined.

Concept Introduction:

The inverse square law states that the intensity of radiation is directly proportional to the inverse of the square of the distance. It is stated as:

$\frac{I_1}{I_2}=\frac{d_2{}^2}{d_1{}^2}$

Here, $I_1$ is intensity at distance $d_1$ and $I_2$ is intensity at distance $d_2$

The process in which a subatomic particle and a nucleus of an atom collide with each other in order to form one or more nuclides is known as a nuclear reaction.

These nuclides are different from the nuclides which are present initially.