CHEMISTRY:MOLECULAR NATURE (LL)W/ACCESS
CHEMISTRY:MOLECULAR NATURE (LL)W/ACCESS
7th Edition
ISBN: 9781119497325
Author: JESPERSEN
Publisher: WILEY
Question
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Chapter 20, Problem 54RQ
Interpretation Introduction

Interpretation:

The energy equivalent of a mass of 1.00 g in kJ is to be determined.

Concept Introduction:

When mass is converted to energy, relation between the change in energy and the change in rest mass is given by Einstein equation as follows:

ΔE=Δmc2

Here, ΔE is the change in energy, Δm is the change in rest mass and c is the velocity of light (3.00×108 ms1).

Conversion of kJ to J is done with the help of following relationship,

1 kJ = 1.00 ×103J

Conversion factor is

1.00 ×103J1 kJ

Conversion of J to kgm2s2 is done with the help of following relationship,

1 J = 1kgm2s2

Conversion factor is

1kgm2s21J

Conversion of g to kg is done with the help of following relationship,

1 kg = 103g

Conversion factor is

103g1 kg

Blurred answer

Chapter 20 Solutions

CHEMISTRY:MOLECULAR NATURE (LL)W/ACCESS

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