Concept explainers
Videos
Interpretation:
The systematic names of the given
Concept Introduction:
The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be
In order to give the name to the unsaturated hydrocarbon following steps are followed:
1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.
2. While writing the name of alkene, the suffix “ane” of the corresponding
3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.
4. Hyphen is used to connect the number to the name.
For number of carbons atoms in alkane chain, the prefix is given as:
Carbon-1 meth
Carbon-2 eth
Carbon-3 prop
Carbon-4 but
Carbon-5 pent
Carbon-6 hex
Carbon-7 hept
Carbon-8 oct
Carbon-9 non
Carbon-10 dec.
Interpretation:
The systematic names of the given unsaturated hydrocarbon should be determined.
Concept Introduction:
The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.
In order to give the name to the unsaturated hydrocarbon following steps are followed:
1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.
2. While writing the name of alkene, the suffix “ane” of the corresponding alkane is replaced by “ene”.
3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.
4. Hyphen is used to connect the number to the name.
For number of carbons atoms in alkane chain, the prefix is given as:
Carbon-1 meth
Carbon-2 eth
Carbon-3 prop
Carbon-4 but
Carbon-5 pent
Carbon-6 hex
Carbon-7 hept
Carbon-8 oct
Carbon-9 non
Carbon-10 dec.
Interpretation:
The systematic names of the given unsaturated hydrocarbon should be determined.
Concept Introduction:
The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.
In order to give the name to the unsaturated hydrocarbon following steps are followed:
1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.
2. While writing the name of alkene, the suffix “ane” of the corresponding alkane is replaced by “ene”.
3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.
4. Hyphen is used to connect the number to the name.
For number of carbons atoms in alkane chain, the prefix is given as:
Carbon-1 meth
Carbon-2 eth
Carbon-3 prop
Carbon-4 but
Carbon-5 pent
Carbon-6 hex
Carbon-7 hept
Carbon-8 oct
Carbon-9 non
Carbon-10 dec.
Interpretation:
The systematic names of the given unsaturated hydrocarbon should be determined.
Concept Introduction:
The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.
In order to give the name to the unsaturated hydrocarbon following steps are followed:
1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.
2. While writing the name of alkyne, the suffix “ane” of the corresponding alkane is replaced by “yne”.
3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.
4. Hyphen is used to connect the number to the name.
For number of carbons atoms in alkane chain, the prefix is given as:
Carbon-1 meth
Carbon-2 eth
Carbon-3 prop
Carbon-4 but
Carbon-5 pent
Carbon-6 hex
Carbon-7 hept
Carbon-8 oct
Carbon-9 non
Carbon-10 dec.
Want to see the full answer?
Check out a sample textbook solution
Chapter 20 Solutions
EBK INTRODUCTORY CHEMISTRY
- Convert the following structures into a chair representation. Then conduct a chair flip. Cl a. b. C\.... оarrow_forwardAktiv Learning App Cengage Digital Learning Part of Speech Table for Assign x o Mail-Karen Ento-Outlook * + app.aktiv.com Your Aktiv Learning trial expires on 02/06/25 at 01:15 PM Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. Problem 17 of 30 Drawing Arrows heat 4 O M B D 5x H H Und Settings H Done :0: H Jararrow_forwardConvert the following chairs into ring representations: a. Brz b.arrow_forward
- Drawing Arrows 1 I I 1 heat 1 51 MO + Drag To Und Settings Done 0 0 Jan 31 3:5arrow_forwardDon't used hand raitingarrow_forwardGramicidin A can adopt more than one structure; NMR spectroscopy has revealed an “end-to-end” dimer form, and x-ray crystallography has revealed an “anti-parallel double- helical” form. Briefly outline and describe an experimentalapproach/strategy to investigate WHICH configuration (“end-to-end dimer” vs “anti-paralleldouble helical”) gramicidin adopts in an actual lipid bilayer.arrow_forward
- Don't used hand raitingarrow_forwardCHEM2323 Problem 2-24 Tt O e: ל Predict the product(s) of the following acid/base reactions. Draw curved arrows to show the formation and breaking of bonds. If the bonds needed are not drawn out, you should redraw them. + BF3 (a) (b) HI + (c) OH -BF Problem 2-25 Use curved arrows and a proton (H+) to draw the protonated form of the following Lewis bases. Before starting, add all missing lone pairs. (a) (b) :0: (c) N 1 CHEM2323 PS CH02 Name:arrow_forwardCHEM2323 Problem 2-26 Tt O PS CH02 Name: Use the curved-arrow formalism to show how the electrons flow in the resonance form on the left to give the one on the right. (Draw all lone pairs first) (a) NH2 NH2 + (b) Problem 2-27 Double bonds can also act like Lewis bases, sharing their electrons with Lewis acids. Use curved arrows to show how each of the following double bonds will react with H-Cl and draw the resulting carbocation. (a) H2C=CH2 (b) (c) Problem 2-28 Identify the most electronegative element in each of the following molecules: (a) CH2FCI F Problem 2-29 (b) FCH2CH2CH2Br (c) HOCH2CH2NH2 (d) CH3OCH2Li F 0 0 Use the electronegativity table in Figure 2.3 to predict which bond in the following pairs is more polar and indicate the direction of bond polarity for each compound. (a) H3C-Cl or Cl-CI (b) H3C-H or H-CI (c) HO-CH3 or (CH3)3Si-CH3 (d) H3C-Li or Li-OHarrow_forward
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co
Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning
Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,
General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning