Chapter 20, Problem 41A

To determine

To write: - The Physics problem for which the given equation would be part of the solution.

Explanation of Solution

Introduction:

The given equation is based on the Coulomb’s force.

Where,

  $9\times {10}^9\frac{\text{N}{\text{.m}}^2}{{\text{C}}^2}=$ Coulomb’s constant.

The question can be framed as follow:

Two point charges having charge $\text{2 }\mu \text{C}$ and $\text{5 }\mu \text{C}$ are separated by a distance of $\text{70 cm}$ . A third charge of $3\mu \text{C}$ are placed between them. the location of third charge is $25\text{ cm}$ from the $\text{2 }\mu \text{C}$ charge. Find the net force acting on the third charge due to the presence of other two.

(use $\frac{1}{4\pi {\epsilon }_o}=9\times {10}^9\frac{\text{N}{\text{.m}}^2}{{\text{C}}^2}$ )

Conclusion:

Hence, the physics problem has been framed according to the given information.