Welding: Principles and Applications (MindTap Course List)
8th Edition
ISBN: 9781305494695
Author: Larry Jeffus
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Videos
Textbook Question
Chapter 20, Problem 33R
When estimating weld cost, what weld joint design factors should be considered?
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
P₂
7+1
*
P₁
ART
2 P (P₁ - P₂- Zgp)
21 / Prove that :-
m²
a
cda
A₂
==
*
Cde
actual
mip
Solution
Q1/ Show that (actual
02/ A simple iet
==
Cda
Cdf
х
Af
2/Y
-
Y+1/Y
2P(P1-P2-zxgxpr)
5. Determine the transfer function of G(s) = 01(s)/T₁(s) and 02(s)/T₁ for the mechanical system
shown in Figure Q5. (Hints: assume zero initial condition)
T₁(t) 01(t)
102(1)
Ол
N1
D1
D2
No. 1790220000
N2
Figure Q5
K2
Chapter 20 Solutions
Welding: Principles and Applications (MindTap Course List)
Ch. 20 - What are two ways math is most commonly used in...Ch. 20 - What is the two-letter abbreviation for the metric...Ch. 20 - List factors that affect the cost of producing...Ch. 20 - List three examples of whole numbers.Ch. 20 - List three examples of decimal fractions.Ch. 20 - List three examples of a mixed unit.Ch. 20 - List three examples of fractions.Ch. 20 - Add the following angles: a. 3050+205 b. 2525+6245Ch. 20 - Subtract the following angles: a. 45481020 b....Ch. 20 - Using the Pythagorean theorem, find c if a=6 and...
Ch. 20 - Sketch a right triangle, equilateral triangle, and...Ch. 20 - Find the area of the following: a. Square that is...Ch. 20 - Find the volume of the following: a. 5 cube b. 10...Ch. 20 - What would the labor cost be if 20 hours were...Ch. 20 - What is the first step in the sequence of...Ch. 20 - If you need two pieces of pipe—one must be 15 ft...Ch. 20 - How many total feet of metal stock would you need...Ch. 20 - How many total feet of metal stock would you need...Ch. 20 - How many feet of scrap pipe will you have left...Ch. 20 - How much scrap pipe will you have once you cut out...Ch. 20 - When the denominators of two fractions to be added...Ch. 20 - How thick will the finished part be if two pieces...Ch. 20 - How much metal is left if 1/8 in. is ground off a...Ch. 20 - What is a dimensioning tolerance?Ch. 20 - What is the minimum and maximum length a part can...Ch. 20 - Give examples of welding applications where angles...Ch. 20 - Write the Pythagorean Theorem formula for a right...Ch. 20 - What is the name of a triangle where all three...Ch. 20 - Why is it important to know the perimeter...Ch. 20 - In what welding applications might you need to...Ch. 20 - List examples of fixed and variable costs that...Ch. 20 - List examples of overhead costs that a welding...Ch. 20 - When estimating weld cost, what weld joint design...Ch. 20 - When a weld is oversized, what joint failure...Ch. 20 - How does the bevel angle in a groove weld affect...Ch. 20 - What is the cross-sectional area of a V-groove...Ch. 20 - What is the cross-sectional area of a fillet weld...Ch. 20 - What two amounts must be multiplied to determine...Ch. 20 - How many pounds of steel electrode are required to...Ch. 20 - Not every pound of electrode filler metal used is...Ch. 20 - What does it mean if an electrode has a 50...Ch. 20 - What is the meaning of the term deposition rate?Ch. 20 - What factor is not included in the deposition...Ch. 20 - Why do flux cored wires have a higher deposition...Ch. 20 - If a welding project has a 45% operating factor,...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- A spring package with two springs and an external force, 200N. The short spring has a loin of 35 mm. Constantly looking for spring for short spring so that total compression is 35 mm (d). Known values: Long spring: Short spring:C=3.98 N/mm Lo=65mmLo=87.4mmF=c·fTotal compression is same for both spring. 200 = (3.98(c1) × 35) + (c₂ × 35) 200 = 139.3 + 35c₂ 200 - 139.3 = 35c₂ 60.7 = 35c₂ c₂ = 60.7/35 Short spring (c₂) = 1.73 N/mm According to my study book, the correct answer is 4.82N/mm What is wrong with the calculating?arrow_forwardWhat is the reason for this composition?arrow_forwardHomework: ANOVA Table for followed design B AB Dr -1 -1 1 (15.18,12) 1 -1 -1 (45.48.51) -1 1 -1 (25,28,19) 1 1 (75.75,81)arrow_forward
- 20. [Ans. 9; 71.8 mm] A semi-elliptical laminated spring is made of 50 mm wide and 3 mm thick plates. The length between the supports is 650 mm and the width of the band is 60 mm. The spring has two full length leaves and five graduated leaves. If the spring carries a central load of 1600 N, find: 1. Maximum stress in full length and graduated leaves for an initial condition of no stress in the leaves. 2. The maximum stress if the initial stress is provided to cause equal stress when loaded. [Ans. 590 MPa ; 390 MPa ; 450 MPa ; 54 mm] 3. The deflection in parts (1) and (2).arrow_forwardQ6/ A helical square section spring is set inside another, the outer spring having a free length of 35 mm greater than the inner spring. The dimensions of each spring are as follows: Mean diameter (mm) Side of square section (mm) Active turns Outer Inner Spring Spring 120 70 8 7 20 15 Determine the (1) Maximum deflection of the two springs and (2) Equivalent spring rate of the two springs after sufficient load has been applied to deflect the outer spring 60 mm. Use G = 83 GN/m².arrow_forwardQ2/ The bumper springs of a railway carriage are to be made of rectangular section wire. The ratio of the longer side of the wire to its shorter side is 1.5, and the ratio of mean diameter of spring to the longer side of wire is nearly equal to 6. Three such springs are required to bring to rest a carriage weighing 25 kN moving with a velocity of 75 m/min with a maximum deflection of 200 mm. Determine the sides of the rectangular section of the wire and the mean diameter of coils when the shorter side is parallel to the axis of the spring. The allowable shear stress is not to exceed 300 MPa and G = 84 kN/mm². Q6/ A belicalarrow_forward
- 11. A load of 2 kN is dropped axially on a close coiled helical spring, from a height of 250 mm. The spring has 20 effective turns, and it is made of 25 mm diameter wire. The spring index is 8. Find the maximum shear stress induced in the spring and the amount of compression produced. The modulus of rigidity for the material of the spring wire is 84 kN/mm². [Ans. 287 MPa; 290 mm]arrow_forwardWhat is the reason for this composition?arrow_forwardHomework: ANOVA Table for followed design B AB Dr -1 -1 1 (15.18,12) 1 -1 -1 (45.48.51) -1 1 -1 (25,28,19) 1 1 (75.75,81)arrow_forward
- S B Pin 6 mm Garrow_forwardMid-Term Exam 2024/2025 Post graduate/Applied Mechanics- Metallurgy Q1/ State the type of fault in the following case, and state the structure in which it will appear. АВСАВСВАСВАСАВСАВСarrow_forwardالثانية Babakt Momentum equation for Boundary Layer S SS -Txfriction dray Momentum equation for Boundary Layer What laws are important for resolving issues 2 How to draw. 3 What's Point about this.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Welding: Principles and Applications (MindTap Cou...Mechanical EngineeringISBN:9781305494695Author:Larry JeffusPublisher:Cengage Learning
Welding: Principles and Applications (MindTap Cou...
Mechanical Engineering
ISBN:9781305494695
Author:Larry Jeffus
Publisher:Cengage Learning
Differences between Temporary Joining and Permanent Joining.; Author: Academic Gain Tutorials;https://www.youtube.com/watch?v=PTr8QZhgXyg;License: Standard Youtube License