Concept explainers
Treatment of isobutene
that reacts with
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- Compound I (C11H14O2) is insoluble in water, aqueous acid, and aqueous NaHCO3, but dissolves readily in 10% Na2CO3 and 10% NaOH. When these alkaline solutions are acidified with 10% HCl, compound I is recovered unchanged. Given this information and its 1H-NMR spectrum, deduce the structure of compound I.arrow_forwardNitriles, R–=C≡N, undergo a hydrolysis reaction when heated with aqueous acid. What is the structure of the compound produced by hydrolysis of propanenitrile, CH3CH2C≡N, if it has IR absorptions from 2500–3100 cm-1 and at 1710 cm-1, and has M+=74?arrow_forwardReaction of (CH3)3CCHO with (C6H5)3P=C(CH3)OCH3, followed bytreatment with aqueous acid, affords R (C7H14O). R has a strong absorption in its IR spectrum at 1717 cm−1 and three singlets in its 1H NMR spectrum at 1.02 (9 H), 2.13 (3 H), and 2.33 (2 H) ppm. What is thestructure of R?arrow_forward
- Reaction of (CH3)3CCHO with (C6H5)3P=C(CH3)OCH3, followed by treatment with aqueous acid, affords R (C7H14O). R has a strong absorption in its IR spectrum at 1717 cm−1 and three singlets in its 1H NMR spectrum at 1.02 (9 H), 2.13 (3 H), and 2.33 (2 H) ppm. What is the structure of R? We will learn about this reaction in Chapter 18.arrow_forwardReaction of (CH3)2CO with LiCCH followed by H2O gives compound X, which has a molecular ion in the mass spectrum at 84. It also has prominent absorptions in the IR spectrum at 3600-3200, 3303, 2938, and 2120 cm-1. The proton NMR shows a singlet at 1.53 (6H), a singlet at 2.37 (1H) and a singlet at 2.43 (1H). What is the structure for compound X?arrow_forwardTreatment of 2-methylpropanenitrile [(CH3)2CHCN] with CH3CH2CH2MgBr, followed by aqueous acid, affords compound V, which has molecular formula C7H14O. V has a strong absorption in its IR spectrum at 1713 cm−1, and gives the following 1H NMR data: 0.91 (triplet, 3 H), 1.09 (doublet, 6 H), 1.6 (multiplet, 2 H), 2.43 (triplet, 2 H), and 2.60 (septet, 1 H) ppm. What is the structure of V? We will learn about this reaction in Chapter 20.arrow_forward
- As reaction of (CH3)2CO with LIC≡CH followed by H2O affords compound D, which has a molecular ion in its mass spectrum at 84 and prominent absorptions in its IR spectrum at 3600−3200, 3303, 2938, and 2120 cm−1. D shows the following 1H NMR spectral data: 1.53 (singlet, 6 H), 2.37 (singlet, 1 H), and 2.43 (singlet, 1 H) ppm. What is the structure of D?arrow_forwardTreatment of benzaldehyde (C6H5CHO) with Zn(Hg) in aqueous HCl forms a compound Z that has a molecular ion at 92 in its mass spectrum. Z shows absorptions at 3150–2950, 1605, and 1496 cm-1 in its IR spectrum. Give a possible structure for Z.arrow_forwardReaction of butanenitrile (CH3CH2CH2CN) with methylmagnesium bromide (CH3MgBr), followed by treatment with aqueous acid, forms compound G. G has a molecular ion in its mass spectrum at m/z = 86 and a base peak at m/z = 43. G exhibits a strong absorption in its IR spectrum at 1721 cm−1 and has the 1H NMR spectrum given below. What is the structure of G?arrow_forward
- Treatment of butan-2-one (CH3COCH2CH3) with strong base followed by CH3I forms a compound Q, which gives a molecular ion in its mass spectrum at 86. The IR (> 1500 cm−1 only) and 1H NMR spectra of Q are given below. What is the structure of Q?arrow_forwardTreatment of butan-2-one (CH3COCH2CH3) with strong base followed by CH3I forms a compound Q, which gives a molecular ion in its mass spectrum at 86. The IR (> 1500 cm−1 only) and 1H NMR spectrum of Q are given below. What is the structure of Q?arrow_forwardBenzonitrile (C6H5CN) is reduced to two different products depending on the reducing agent used. Treatment with lithium aluminum hydride followed by water forms K, which has a molecular ion in its mass spectrum at 107 and the following IR absorptions: 3373, 3290, 3062, 2920, and 1600 cm-1. Treatment with a milder reducing agent forms L, which has amolecular ion in its mass spectrum at 106 and the following IR absorptions: 3086, 2820, 2736, 1703, and 1600 cm-1. L shows fragments in its mass spectrum at m/z = 105 and 77. Propose structures for K and L and explain how you arrived at your conclusions.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning