Chapter 20, Problem 20.62SP

1. a)
2. b)

Interpretation Introduction

Interpretation:

The equilibrium constant is calculated and the reason for the $\text{Cu(I)}$ complex is insoluble to be interpreted.

Concept Introduction:

Equilibrium constant: The equilibrium constant of a chemical reaction is the value of its reaction quotient at chemical equilibrium.

$\text{K}\text{= }\frac{{\text{[product]}}_{\text{eq}}}{{\text{[reactant]}}_{\text{eq}}}$

Gibb’s free energy: The Gibb’s free energy also termed as the available energy; is the thermodynamic potential that is minimized when a system reaches chemical equilibrium at constant and temperature.

$\begin{array}{l}{\text{ΔG}}^{\text{o}}\text{=}{\text{-nFE}}^{\text{o}}\\ \text{where,}{\text{E}}^{\text{o}}\text{is}\text{standard}\text{reduction}\text{potential}\text{of}\text{the}\text{reaction}\text{.}\\ \text{F}\text{is}\text{Faraday}\text{constant}\text{.}\\ \text{n}\text{is}\text{number}\text{of}\text{electrons}\text{involved}\text{.}\end{array}$

To Identify: The equilibrium constant is calculated

Interpretation Introduction

Interpretation: The equilibrium constant is calculated and the reason for the $\text{Cu(I)}$ complex is insoluble to be interpreted.

Concept Introduction:

Equilibrium constant: The equilibrium constant of a chemical reaction is the value of its reaction quotient at chemical equilibrium.

$\text{K}\text{= }\frac{{\text{[product]}}_{\text{eq}}}{{\text{[reactant]}}_{\text{eq}}}$

Gibb’s free energy: The Gibb’s free energy also termed as the available energy; is the thermodynamic potential that is minimized when a system reaches chemical equilibrium at constant and temperature.

$\begin{array}{l}{\text{ΔG}}^{\text{o}}\text{=}{\text{-nFE}}^{\text{o}}\\ \text{where,}{\text{E}}^{\text{o}}\text{is}\text{standard}\text{reduction}\text{potential}\text{of}\text{the}\text{reaction}\text{.}\\ \text{F}\text{is}\text{Faraday}\text{constant}\text{.}\\ \text{n}\text{is}\text{number}\text{of}\text{electrons}\text{involved}\text{.}\end{array}$

To explain the reason for insoluble $\text{Cu(I)}$ complex