EBK GENERAL CHEMISTRY: THE ESSENTIAL CO
EBK GENERAL CHEMISTRY: THE ESSENTIAL CO
7th Edition
ISBN: 8220106637203
Author: Chang
Publisher: YUZU
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Chapter 20, Problem 20.26QP
Interpretation Introduction

Interpretation:

The factors that determines whether a given complex will be diamagnetic or paramagnetic has to be given.

Concept Introduction:

Diamagnetic:

The compounds in which all the electrons are paired in their orbitals are considered as diamagnetic compounds. Such compounds will be repelled by the magnetic field.

Paramagnetic:

If a compound consists of one or more unpaired electrons in their valence shell then it is known as paramagnetic compound. Such compounds will be attracted by the magnetic field.

Crystal field splitting:

When ligands approach the central metal atom then the field strength of the ligand splits the outermost valence d orbitals of the central metal atom into two set of orbitals such as t2g and eg orbitals. The energy gap between two set of t2g and eg orbitals will be more or less based on the extent of splitting which in turn is based on the strength of the ligands. This phenomenon is known as Crystal field splitting.

The following diagram shows the splitting in the octahedral complexes:

EBK GENERAL CHEMISTRY: THE ESSENTIAL CO, Chapter 20, Problem 20.26QP

Splitting energy is the energy between t2g and eg orbitals. The splitting energy distinguishes the energy of t2g and eg orbitals. t2g orbitals are the lower energy orbitals whereas eg orbitals are the higher energy orbitals. Splitting energy is represented as Δo .

Pairing energy is the energy required to pair up electrons in an orbital. It is represented as Π.

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6. Consider the following exothermic reaction below. 2Cu2+(aq) +41 (aq)2Cul(s) + 12(aq) a. If Cul is added, there will be a shift left/shift right/no shift (circle one). b. If Cu2+ is added, there will be a shift left/shift right/no shift (circle one). c. If a solution of AgNO3 is added, there will be a shift left/shift right/no shift (circle one). d. If the solvent hexane (C6H14) is added, there will be a shift left/shift right/no shift (circle one). Hint: one of the reaction species is more soluble in hexane than in water. e. If the reaction is cooled, there will be a shift left/shift right/no shift (circle one). f. Which of the changes above will change the equilibrium constant, K?
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Chapter 20 Solutions

EBK GENERAL CHEMISTRY: THE ESSENTIAL CO

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