Concept explainers
(a)
Interpretation: The products formed by the treatment of
Concept introduction: Organometallic reagents like
Answer to Problem 20.36P
The products formed by the treatment of
Figure 1
Compound B do not react with
Explanation of Solution
The ball and stick model of compound A and B shows that black balls represent carbon atom, white balls represent hydrogen atom and red balls represent oxygen atom. Therefore, the structure of A and B is,
Figure 2
Ketones on reaction with
Figure 3
The products formed by the treatment of
(b)
Interpretation: The products formed by the treatment of
Concept introduction: Organometallic reagents like
Answer to Problem 20.36P
The products formed by the treatment of
Figure 4
Explanation of Solution
The structure of A and B is shown in Figure 2.
Ketones on reaction with
Figure 5
The products formed by the treatment of
(c)
Interpretation: The products formed by the treatment of
Concept introduction: Organometallic reagents like
Answer to Problem 20.36P
The products formed by the treatment of
Figure 6
Explanation of Solution
The structure of A and B is shown in Figure 2.
Ketones and esters on reaction with Grignard reagent form tertiary alcohol. Therefore, the products formed by the treatment of
Figure 7
The products formed by the treatment of
(d)
Interpretation: The products formed by the treatment of
Concept introduction: Organometallic reagents like
Answer to Problem 20.36P
The products formed by the treatment of
Figure 8
Explanation of Solution
The structure of A and B is shown in Figure 2.
Ketones and esters on reaction with organolithium reagent form tertiary alcohol. Therefore, the products formed by the treatment of
Figure 9
The products formed by the treatment of
(e)
Interpretation: The products formed by the treatment of
Concept introduction: Organometallic reagents like
Answer to Problem 20.36P
Compound A and B do not reaction with
Explanation of Solution
The structure of A and B is shown in Figure 2.
Ketones and esters do not undergo oxidation reaction with
Compound A and B do not reaction with
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Chapter 20 Solutions
ORGANIC CHEMISTRY
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- Draw the organic product(s) formed when CH3CH₂CH₂OH is treated with each reagent. a. H₂SO4 d. HBr g. TsCl, pyridine b. NaH h. [1] NaH; [2] CH₂CH₂Br e. SOCI₂, pyridine f. PBr3 c. HCI + ZnCl₂ Hint: NaH deprotonates the alcohol forming an alkoxidearrow_forwardDraw the products formed in each reaction.arrow_forwardDraw the product formed when phenylacetic acid (C6H5CH2COOH) is treated with each reagent. With some reagents, no reaction occurs. a. NaHCO3 b. NaOH c. SOCl2 d. NaCl e. NH3(1equiv) f. NH3, ∆ g. CH3OH, H2SO4 h. CH3OH, −OH i. [1] NaOH; [2] CH3COCl j. CH3NH2, DCC k. [1] SOCl2; [2] CH3CH2CH2NH2 (excess) l. [1] SOCl2; [2] (CH3)2; [2] (CHarrow_forward
- 4. Draw the products formed when 3-hexyne is treated with each reagent a. HBr(2 equivalents) b. Bra (2 equivalents) c. H₂ (2 equivalents) d. [1] 2Na [2]NH,(1)arrow_forwardDraw the organic products formed in each reaction.arrow_forwardDoes the equilibrium favor the reactants or products in each substitution reaction? a. CH;CH2-NH2 Br CH;CH2-Br + "NH2 b. "CN CN + I-arrow_forward
- Draw the products of each reaction.arrow_forwardDraw the products formed when each compound is treated with CH;CH,COCI, AICI3. CH(CH3)2 N(CH)2 Br CH3 CH(CH)2 a. b. C. d. е.arrow_forwardDraw the products formed when hex-1-yne is treated with each reagent. a. HCl (2 equiv) b. HBr (2 equiv) c. Cl2 (2 equiv) d.H2O + H2SO4 + HgSO4 e. [1] R2BH; [2] H2O2, HO− f. NaH g. [1] −NH2; [2] CH3CH2Brarrow_forward
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