Concept explainers
(a)
Interpretation:
The monosaccharides C and D needs to be classified by determining the type of carbonyl group and number of carbon atoms present in it.
Concept introduction:
Monosaccharide can be characterized according to the type of carbonyl group and the number of carbon atoms in their chain. In the classification of monosaccharide based on type of carbonyl group and number of carbons present in the chain, if the monosaccharide contains an
(b)
Interpretation:
The chiral center needs to be located in the given monosaccharides
Concept introduction:
Chiral carbon is an asymmetric carbon which contains four different types of groups or atoms.

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Chapter 20 Solutions
ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM
- A mixture of C7H12O2, C9H9OCl, biphenyl and acetone was put together in a gas chromatography tube. Please decide from the GC resutls which correspond to the peak for C7,C9 and biphenyl and explain the reasoning based on GC results. Eliminate unnecessary peaks from Gas Chromatography results.arrow_forwardIs the molecule chiral, meso, or achiral? CI .CH3 H₂C CIarrow_forwardPLEASE HELP ! URGENT!arrow_forward
- Identify priority of the substituents: CH3arrow_forwardHow many chiral carbons are in the molecule? OH F CI Brarrow_forwardA mixture of three compounds Phen-A, Acet-B and Rin-C was analyzed using TLC with 1:9 ethanol: hexane as the mobile phase. The TLC plate showed three spots of R, 0.1 and 0.2 and 0.3. Which of the three compounds (Phen-A; Acet-B or Rin-C) would have the highest (Blank 1), middle (Blank 2) and lowest (Blank 3) spot respectively? 0 CH: 0 CH, 0 H.C OH H.CN OH Acet-B Rin-C phen-A A A <arrow_forward
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