Explanation Given Info: Volume of the insulated bottle is 1.00 L and temperature of tea is 90.0 °C The heat added or rejected for a substance is given as, Q = m C P Δ T = m C P ( T f − T i ) (1) Here, Q is the heat added or rejected m is the mass of the substance C P is the specific heat at constant pressure Δ T is the temperature difference T f is the final temperature of the substance T i is the initial temperature of the substance Consider 0.8 L of tea at 90.0 °C mixing with 0.2 L of air at 25.0 ° C As the whole system is in thermal equilibrium, the heat added to the air will be equal to the heat rejected by the air as shown below. Q t = Q a m t C t Δ T t = m a C a Δ T a m t C t ( T t − T ) = m a C a ( T a − T ) Here, Q t is the heat added by tea Q a is the heat added to air m t is the mass of the tea m a is the mass of the air C t is the specific heat for tea C a is the specific heat for air T is the equilibrium temperature between tea and air T t is the temperature of the tea T a is the temperature of the air Solve the above equation to get T , T = m t C t T t + m a C a T a m t C t + m a C a (2) The mass of any substance can be given as, m = ρ V Here, m is the mass of substance ρ is the density of substance V is the volume of the substance Therefore, mass of the tea will be, m t = ( 1000 kg / m 3 ) ( 0.8 L ) ( 1 m 3 1000 L ) = 0.8 kg And, the mass of the air will be, m a = ( 1

Bundle: Physics For Scientists And Engineers With Modern Physics, Loose-leaf Version, 10th + Webassign Printed Access Card For Serway/jewett's Physics For Scientists And Engineers, 10th, Single-term

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Chapter 20, Problem 13P

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Bundle: Physics For Scientists And Engineers With Modern Physics, Loose-leaf Version, 10th + Webassign Printed Access Card For Serway/jewett's Physics For Scientists And Engineers, 10th, Single-term

Ch. 20.1 - Two containers hold an ideal gas at the same...Ch. 20.2 - (i) How does the internal energy of an ideal gas...Ch. 20.3 - Prob. 20.3QQ Ch. 20.3 - Prob. 20.4QQ Ch. 20 - A spherical balloon of volume 4.00 103 cm3...Ch. 20 - A spherical balloon of volume V contains helium at...Ch. 20 - A 2.00-mol sample of oxygen gas is confined to a...Ch. 20 - Prob. 4P Ch. 20 - A 5.00-L vessel contains nitrogen gas at 27.0C and...Ch. 20 - Prob. 6P

Ch. 20 - In a period of 1.00 s, 5.00 1023 nitrogen...Ch. 20 - A 7.00-L vessel contains 3.50 moles of gas at a...Ch. 20 - Calculate the change in internal energy of 3.00...Ch. 20 - Prob. 10P Ch. 20 - In a constant-volume process, 209 J of energy is...Ch. 20 - A vertical cylinder with a heavy piston contains...Ch. 20 - Prob. 13P Ch. 20 - A certain molecule has f degrees of freedom. Show...Ch. 20 - Prob. 15P Ch. 20 - Why is the following situation impossible? A team...Ch. 20 - You and your younger brother are designing an air...Ch. 20 - During the compression stroke of a certain...Ch. 20 - Air in a thundercloud expands as it rises. If its...Ch. 20 - Prob. 20P Ch. 20 - Air (a diatomic ideal gas) at 27.0C and...Ch. 20 - Prob. 22P Ch. 20 - Prob. 23P Ch. 20 - Prob. 24P Ch. 20 - Prob. 25P Ch. 20 - Prob. 26P Ch. 20 - Prob. 27AP Ch. 20 - Prob. 28AP Ch. 20 - The dimensions of a classroom are 4.20 m 3.00 m ...Ch. 20 - Prob. 30AP Ch. 20 - The Earths atmosphere consists primarily of oxygen...Ch. 20 - Prob. 32AP Ch. 20 - Prob. 33AP Ch. 20 - In a cylinder, a sample of an ideal gas with...Ch. 20 - As a 1.00-mol sample of a monatomic ideal gas...Ch. 20 - Prob. 36AP Ch. 20 - Prob. 37AP Ch. 20 - Prob. 38AP Ch. 20 - Prob. 39AP Ch. 20 - Prob. 40AP Ch. 20 - Prob. 41AP Ch. 20 - On the PV diagram for an ideal gas, one isothermal...Ch. 20 - Prob. 43AP Ch. 20 - Prob. 44AP Ch. 20 - Prob. 45CP

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