EBK MANUFACTURING ENGINEERING & TECHNOL
7th Edition
ISBN: 8220100793431
Author: KALPAKJIAN
Publisher: PEARSON
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Chapter 20, Problem 10RQ
Which rapid-prototyping technologies do not require a laser?
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Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to find
Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of the
Procedure:
1- Cartesian system, 2D3D,
type of support
2- Free body diagram
3 - Find the support reactions
4- If you find a negative
number then flip the force
5- Find the internal force
3D
∑Fx=0
∑Fy=0
∑Fz=0
∑Mx=0
∑My=0
ΣMz=0
2D
ΣFx=0
ΣFy=0
ΣMz=0
5- Use method of section
and cut the element
where you want to find
the internal force and
keep either side of the
Chapter 20 Solutions
EBK MANUFACTURING ENGINEERING & TECHNOL
Ch. 20 - What is the basic difference between additive...Ch. 20 - What is stereolithography?Ch. 20 - What is virtual prototyping, and how does it...Ch. 20 - What is fused-deposition modeling?Ch. 20 - Prob. 5RQCh. 20 - Prob. 6RQCh. 20 - Explain what each of the following means: (a) 3DP,...Ch. 20 - What starting materials can be used in...Ch. 20 - What are the cleaning and finishing operations in...Ch. 20 - Which rapid-prototyping technologies do not...
Ch. 20 - What are the advantages of electron beam melting?Ch. 20 - What is the Keltool process?Ch. 20 - What is a self-replicating machine?Ch. 20 - Which rapid-prototyping operations can produce...Ch. 20 - Which rapid-prototyping operations can produce...Ch. 20 - How can a mold for sand casting be produced using...Ch. 20 - Examine a ceramic coffee cup and determine in...Ch. 20 - How would you rapidly manufacture tooling for...Ch. 20 - Explain the significance of rapid tooling in...Ch. 20 - List the processes described in this chapter that...Ch. 20 - Few parts in commercial products today are...Ch. 20 - Can rapid-prototyped parts be made of paper?...Ch. 20 - Careful analysis of a rapid-prototyped part...Ch. 20 - Why are the metal parts in three-dimensional...Ch. 20 - Make a list of the advantages and limitations of...Ch. 20 - In making a prototype of a toy automobile, list...Ch. 20 - Using an approximate cost of 400 per gallon for...Ch. 20 - The extruder head in a fused-deposition modeling...Ch. 20 - Using the data for Problem 20.28 and assuming that...Ch. 20 - Rapid-prototyping machines represent a large...Ch. 20 - One of the major advantages of stereolithography...Ch. 20 - A manufacturing technique is being proposed that...Ch. 20 - Identify the rapid-prototyping processes described...Ch. 20 - Design a machine that uses rapid-prototyping...Ch. 20 - Because of relief of residual stresses during...Ch. 20 - Prob. 37SDPCh. 20 - Prob. 39SDPCh. 20 - Prob. 40SDP
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- Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of thearrow_forwardProcedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forwardProcedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forward
- For each system below with transfer function G(s), plot the pole(s) on the s-plane. and indicate whether the system is: (a) "stable" (i.e., a bounded input will always result in a bounded output), (b) "marginally stable," or (c) "unstable" Sketch a rough graph of the time response to a step input. 8 a) G(s) = 5-5 8 b) G(s) = c) G(s) = = s+5 3s + 8 s² - 2s +2 3s +8 d) G(s): = s²+2s+2 3s+8 e) G(s): = s² +9 f) G(s): 8 00 == Sarrow_forwardPlease answer the following question. Include all work and plase explain. Graphs are provided below. "Consider the Mg (Magnesium) - Ni (Nickel) phase diagram shown below. This phase diagram contains two eutectic reactions and two intermediate phases (Mg2Ni and MgNi2). At a temperature of 505oC, determine what the composition of an alloy would need to be to contain a mass fraction of 0.20 Mg and 0.80 Mg2Ni."arrow_forwardThe triangular plate, having a 90∘∘ angle at AA, supports the load PP = 370 lblb as shown in (Figure 1).arrow_forward
- Design a 4-bar linkage to carry the body in Figure 1 through the two positions P1 and P2 at the angles shown in the figure. Use analytical synthesis with the free choice values z = 1.075, q= 210°, ß2 = −27° for left side and s = 1.24, y= 74°, ½ = − 40° for right side. φ 1.236 P2 147.5° 210° 2.138 P1 Figure 1 Xarrow_forwardDesign a 4-bar linkage to carry the body in Figure 1 through the two positions P1 and P2 at the angles shown in the figure. Use analytical synthesis with the free choice values z = 1.075, q= 210°, B₂ = −27° for left side and s = 1.24, y= 74°, ½ = − 40° for right side. 1.236 P2 147.5° 210° P1 Figure 1 2.138 Xarrow_forwardcan you explain how in a coordinate frame transformation: v = {v_n}^T {n-hat} and then it was found that {n-hat} = [C]^T {b-hat} so v_n = {v_n}^T [C]^T {b-hat}, how does that equation go from that to this --> v_n = [C]^T v_barrow_forward
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What is Rapid Prototyping?; Author: Formlabs;https://www.youtube.com/watch?v=-TDn25K-Jh4;License: Standard youtube license