Horizons: Exploring the Universe - With MindTap
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Chapter 2, Problem 9RQ
Why do astronomers use the word on to describe angles on the sky rather than angles in the sky?
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8.114 CALC A Variable-Mass Raindrop. In a rocket-propul-
sion problem the mass is variable. Another such problem is a rain-
drop falling through a cloud of small water droplets. Some of these
small droplets adhere to the raindrop, thereby increasing its mass
as it falls. The force on the raindrop is
dp
dv
dm
Fext
=
+
dt
dt
dt
=
Suppose the mass of the raindrop depends on the distance x that it
has fallen. Then m kx, where k is a constant, and dm/dt = kv.
This gives, since Fext
=
mg,
dv
mg = m
+ v(kv)
dt
Or, dividing by k,
dv
xgx
+ v²
dt
This is a differential equation that has a solution of the form
v = at, where a is the acceleration and is constant. Take the initial
velocity of the raindrop to be zero. (a) Using the proposed solution
for v, find the acceleration a. (b) Find the distance the raindrop has
fallen in t = 3.00 s. (c) Given that k = 2.00 g/m, find the mass of
the raindrop at t = 3.00 s. (For many more intriguing aspects of
this problem, see K. S. Krane, American Journal of…
8.13 A 2.00-kg stone is sliding Figure E8.13
F (kN)
to the right on a frictionless hori-
zontal surface at 5.00 m/s when
it is suddenly struck by an object
that exerts a large horizontal
force on it for a short period of 2.50
time. The graph in Fig. E8.13
shows the magnitude of this force
as a function of time. (a) What
impulse does this force exert on
t (ms)
15.0
16.0
the stone? (b) Just after the force stops acting, find the magnitude
and direction of the stone's velocity if the force acts (i) to the right
or (ii) to the left.
Please calculate the expectation value for E and the uncertainty in E for this wavefunction trapped in a simple harmonic oscillator potential
Chapter 2 Solutions
Horizons: Exploring the Universe - With MindTap
Ch. 2 - Why have astronomers added modern constellations...Ch. 2 - What is the difference between asterism d a...Ch. 2 - What characteristic do starts in a constellation...Ch. 2 - Do people from other cultures on Earth see the...Ch. 2 - Prob. 5RQCh. 2 - Prob. 6RQCh. 2 - What does the word apparent mean in apparent...Ch. 2 - In what ways is the celestial sphere a scientific...Ch. 2 - Why do astronomers use the word on to describe...Ch. 2 - Earth did not rotate, could you define the...
Ch. 2 - Where would you go on Earth if you wanted to be...Ch. 2 - Prob. 12RQCh. 2 - Explain h to make a simple astronomical...Ch. 2 - 14. Why does the number of circumpolar...Ch. 2 - How could you detect Earths precession t examining...Ch. 2 - How Do We know? How can a scientific model be...Ch. 2 - Using stars from one or more of the “official”...Ch. 2 - Prob. 2DQCh. 2 - Prob. 1PCh. 2 - If two stars differ by 8.6 magnitudes, what is...Ch. 2 - Prob. 3PCh. 2 - By what factor is sunlight brighter than...Ch. 2 - If you are at a latitude of 35° north of Earths...Ch. 2 - Prob. 1LTLCh. 2 - Prob. 2LTL
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- Questions 68-70 Four hundred millilitres (mL) of a strong brine solution at room temperature was poured into a measuring cylinder (Figure 1). A piece of ice of mass 100 g was then gently placed in the brine solution and allowed to float freely (Figure 2). Changes in the surface level of the liquid in the cylinder were then observed until all the ice had melted. Assume that the densities of water, ice and the brine solution are 1000 kg m-3, 900 kg m3 and 1100 kg m3, respectively. 68 Figure 1 400 400 Figure 2 1m² = 1x10 mL After the ice was placed in the brine solution and before any of it had melted, the level of the brine solution was closest to 485 mL. B 490 mL. C 495 mL. Displaced volume by ice. D 500 mL. weight of ice 69 The level of the brine solution after all the ice had melted was A 490 mL B 495 mL D 1100kg/m² = 909 xious mis 70 Suppose water of the same volume and temperature had been used instead of the brine solution. In this case, by the time all the ice had melted, the…arrow_forwardPlease showarrow_forwardNo chatgpt plsarrow_forward
- A bowling ball encounters a 0.760-m vertical rise on the way back to the ball rack, as the drawing illustrates. Ignore frictional losses and assume that the mass of the ball is distributed uniformly. The translational speed of the ball is 8.62 m/s at the bottom of the rise. Find the translational speed at the top. Number i 7.70 Units m/s 0.760 marrow_forwardTwo converging lenses A and B, with focal lengths =20cm and = 25cm, are placed 80cm apart, as shown in the figure (1). An object is placed 60cm in front of the first lens as shown in figure (2). Determine (a) the position, and (b) the magnification, of the final image formed by the combination of the two lenses.arrow_forwardMajor sources of error in refractionnof light experiment.arrow_forward
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