Chapter 2, Problem 80QRT

Interpretation Introduction

Interpretation:

The table given in the question statement has to be filled for $\text{1}\text{mol}\text{methanol,}{\text{CH}}_{\text{3}}\text{OH}$.

Explanation of Solution

Given the number of moles of methanol is $\text{1}$.

Number of moles of carbon $\text{=}\text{1}$ mole.

Number of moles of hydrogen $\text{=}4$ moles.

Number of moles of oxygen $\text{=}\text{1}$ mole.

Number of molecules $\text{=}$ $\text{Number}\text{of}\text{moles}\times \text{6}\text{.022}\text{×}{\text{10}}^{\text{23}}$.

Mass of carbon $\text{=}\text{12}\text{.0107}\text{g/mol}$.

Mass of hydrogen $\text{=}\text{1}\text{.0079}\text{g/mol}$.

Mass of oxygen $\text{=}15.9994\text{g/mol}$.

Molar mass of methanol $\text{=}\text{12}\text{.0107}\text{+}\text{(}\text{3}\text{×}\text{1}\text{.0079)}\text{+}\text{15}\text{.9994}\text{=}\text{32}\text{.0417}\text{g/mol}$.

Then the table will be:

$\begin{array}{l}{\text{CH}}_{\text{3}}\text{OH}\text{Carbon}\text{Hydrogen}\text{Oxygen}\\ \text{Amount}\text{of}\text{substance}\text{(mol)}\text{1}\text{mol}\text{1}\text{mol}\text{4}\text{mol}\text{1}\text{mol}\\ \text{Number}\text{of}\text{molecules}\text{or}\text{atoms}\text{6}{\text{.022×10}}^{\text{23}}\text{6}{\text{.022×10}}^{\text{23}}\text{2}{\text{.409×10}}^{\text{24}}\text{6}{\text{.022×10}}^{\text{23}}\\ \text{Molar}\text{mass}\text{32}\text{.0417}\text{g/mol}\text{12}\text{.0107g/mol}\text{4}\text{.0316g/mol}\text{15}\text{.9994}\text{g/mol}\end{array}$