Explanation Given, Natural abundance of 10 B = 19.91 % . The atomic weight of boron = 10.811 . The atomic mass of 10 B = 10.811 u/atom Sum of the percent must be 100% and for boron, only two isotopes occurs naturally. So, the natural abundance of other isotope is 100 - 19.91 = 80.09 % . These percentages tell us that every 1000 atoms of boron contain 1991 atoms of 10 B isotope and 8009 atoms of the other boron isotope. The atomic weight of boron = 10.811 . Let X be the atomic mass of other isotope of boron. Then, 1991 atoms 10 B 10000 B atoms × ( 10

Bundle: Chemistry: The Molecular Science, 5th, Loose-Leaf + OWLv2 with Quick Prep 24-Months Printed Access Card

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ISBN: 9781305367487

Author: John W. Moore, Conrad L. Stanitski

Publisher: Cengage Learning

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An atom is the smallest unit of an element that possesses all the properties of that particular element. Molecules are the smallest unit of a substance that possess all the properties of that particular substance.

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Chapter 2, Problem 23QRT

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The atomic weight of the other natural isotope of boron has to be calculated from the given information.

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Chapter 2, Problem 22QRT

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The atomic weight of the other natural isotope of boron has to be calculated from the given information.

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Chapter 2 Solutions

Interpretation:

The atomic weight of the other natural isotope of boron has to be calculated from the given information.