
Concept explainers
a.
Obtain a sample of 10 pages from this textbook by using simple random sampling.
a.

Answer to Problem 69CE
The sample of 10 pages obtained from this textbook by using simple random sampling consists of the pages serial numbered as follows:
586 | 559 | 98 | 206 | 375 |
73 | 127 | 263 | 10 | 843 |
Explanation of Solution
Calculation:
Answers may vary. One of the possible answers is given below:
This textbook is considered as the population. The total number of pages in this textbook is 865 (from cover to cover).
Assign serial numbers 1 to 865 to the pages, starting with 1 for the first cover page and proceeding thereafter.
Simple random sampling:
Simple random sampling is defined as a method of sampling in which, a sample of size n is drawn from a population of size N by using a random method, such as a random number table or software such as EXCEL, MINITAB, etc. to ensure that each of the N population units has the same probability of being selected in each draw. The simple random sampling gives a sample that is representative of the population.
EXCEL Procedure:
Step by step procedure to obtain a simple random sample by using EXCEL is given below:
- Enter =RANDBETWEEN(1,865) in cells A1:A10 to obtain 10 random numbers lying between 1 and 865.
- Repeat the procedure till 10 unique random numbers are obtained.
Output using EXCEL is given below:
Hence, the sample of 10 pages obtained from this textbook by using simple random sampling consists of the pages serial numbered as follows:
586 | 559 | 98 | 206 | 375 |
73 | 127 | 263 | 10 | 843 |
b.
Obtain a sample of 10 pages from this textbook by using systematic sampling.
b.

Answer to Problem 69CE
The sample of 10 pages obtained from this textbook by using systematic sampling consists of the pages serial numbered as follows:
82 | 168 | 254 | 340 | 426 |
512 | 598 | 684 | 770 | 856 |
Explanation of Solution
Calculation:
Answers may vary. One of the possible answers is given below:
Systematic sampling:
Systematic sampling is defined as a method of sampling in which, at first, an entity is chosen from the first k entities in the list, followed by choosing every kth entity thereafter, till the desired
For a population size N and sample size n,
Here,
EXCEL Procedure:
Step by step procedure to obtain a systematic sample by using EXCEL is given below:
- Enter =RANDBETWEEN(1,86) in cell A1 to obtain 1 random number lying between 1 and 86.
Output using EXCEL is given below:
Denote
Here,
82 |
168 |
254 |
340 |
426 |
512 |
598 |
684 |
770 |
856 |
Hence, the sample of 10 pages obtained from this textbook by using systematic sampling consists of the pages serial numbered as follows:
82 | 168 | 254 | 340 | 426 |
512 | 598 | 684 | 770 | 856 |
c.
Obtain a sample of 10 pages from this textbook by using cluster sampling.
c.

Answer to Problem 69CE
The sample of 10 pages obtained from this textbook by using cluster sampling consists of the pages serial numbered as follows:
141 | 142 | 143 | 144 | 145 |
146 | 147 | 148 | 149 | 150 |
Explanation of Solution
Calculation:
Answers may vary. One of the possible answers is given below:
Cluster sampling:
Cluster sampling is defined as a method of sampling in which, at first, the entire population is divided into heterogeneous subgroups, especially by geographic areas called cluster, then desired number of clusters are selected from all the clusters, usually by simple random sampling. Each cluster is expected to be representative of the population.
Divide the book into clusters of 10 consecutive pages, starting from the first page. There are 865 pages. Thus, the total number of clusters would be as follows:
- 86 clusters of 10 pages each.
- 1 cluster of 5 pages.
Assign serial numbers 1 to 87 to the 87 clusters. Randomly select 1 cluster and consider all the pages in that cluster as the sample.
EXCEL Procedure:
Step by step procedure to obtain a cluster sample by using EXCEL is given below:
Step by step procedure to obtain a systematic sample by using EXCEL is given below:
- Enter =RANDBETWEEN(1,87) in cell A1 to obtain 1 random number lying between 1 and 87.
Output using EXCEL is given below:
Thus, the 15th cluster is selected.
Now,
The 1st cluster has page numbers 1 to 10.
The 2nd cluster has page numbers 11 to 20.
Proceeding in this manner,
The 86th cluster has page numbers 851 to 860.
The 87th cluster has page numbers 861 to 865.
The pattern above ensures that the ith cluster must have page numbers (10i – 9) to 10i for
For the 15th cluster,
Hence, the sample of 10 pages obtained from this textbook by using cluster sampling consists of the pages serial numbered as follows:
141 | 142 | 143 | 144 | 145 |
146 | 147 | 148 | 149 | 150 |
d.
Obtain a sample of 10 pages from this textbook by using judgment sampling.
d.

Answer to Problem 69CE
The sample of 10 pages obtained from this textbook by using judgment sampling consists of the pages serial numbered as follows:
29 | 49 | 83 | 195 | 277 |
361 | 463 | 571 | 675 | 720 |
Explanation of Solution
Calculation:
Answers may vary. One of the possible answers is given below:
Judgment sampling:
Judgment sampling is defined as a method of sampling that depends upon the expertise of the researcher to identify sample units that would represent the population, rather than on random sampling methods. It is a non-random sampling method.
It is considered to be a good judgment that in this particular case that the third page of each of chapters 1, 2, 3, 5, 7, 9, 11, 13, 15 and 17 would be a good representative of all the pages.
The chapters and the page number of their corresponding third pages are given below by a proper inspection of the table:
Chapter number | Third page number |
1 | 29 |
2 | 49 |
3 | 83 |
5 | 195 |
7 | 277 |
9 | 361 |
11 | 463 |
13 | 571 |
15 | 675 |
17 | 720 |
Note that the page numbers here are not the number marked at the top of the page, but the actual page number of the entire
Hence, the sample of 10 pages obtained from this textbook by using judgment sampling consists of the pages serial numbered as follows:
29 | 49 | 83 | 195 | 277 |
361 | 463 | 571 | 675 | 720 |
e.
Recommend a method to estimate the mean number of formulas per page.
e.

Answer to Problem 69CE
The method of simple random sampling may be recommended to estimate the mean number of formulas per page.
Explanation of Solution
Answers may vary. One of the possible answers is given below:
Simple random sampling provides a sample that is more-or-less representative of the population. In order to estimate the mean number of formulas per page, one would prefer that the sample represents the population well enough to ensure a reasonable estimate for the whole textbook.
Thus, the method of simple random sampling may be recommended to estimate the mean number of formulas per page.
In case of systematic sampling, there may be some periodicity observed based on the nature of the contents of each chapter, depending upon the random start. The same pattern of too few formulas or too many formulas may be observed in systematic sampling. Such a periodicity is not desirable. Thus, systematic sampling is not used in this case.
Cluster sampling can be useful when the population itself forms heterogeneous clusters naturally, especially in case of geographical regions. Here, although the population forms natural heterogeneous subgroups of chapters, each of those subgroups contains more than 10 pages. Now, in case of cluster sampling, the randomly selected cluster is considered entirely into the sample. In this case, it is not possible. Thus, cluster sampling is not used in this case.
Judgment sampling is non-random sampling methods. Now, it is known that a random sampling method is more likely to yield a well-representative sample than non-random sampling methods. As a result, the use of judgment sampling is usually avoided, unless it is absolutely impossible or unreasonable to use random sampling methods. Here, it is not impossible to use random sampling. Thus, judgment sampling is not used in this case.
Want to see more full solutions like this?
Chapter 2 Solutions
Applied Statistics in Business and Economics
- Client 1 Weight before diet (pounds) Weight after diet (pounds) 128 120 2 131 123 3 140 141 4 178 170 5 121 118 6 136 136 7 118 121 8 136 127 a) Determine the mean change in patient weight from before to after the diet (after – before). What is the 95% confidence interval of this mean difference?arrow_forwardIn order to find probability, you can use this formula in Microsoft Excel: The best way to understand and solve these problems is by first drawing a bell curve and marking key points such as x, the mean, and the areas of interest. Once marked on the bell curve, figure out what calculations are needed to find the area of interest. =NORM.DIST(x, Mean, Standard Dev., TRUE). When the question mentions “greater than” you may have to subtract your answer from 1. When the question mentions “between (two values)”, you need to do separate calculation for both values and then subtract their results to get the answer. 1. Compute the probability of a value between 44.0 and 55.0. (The question requires finding probability value between 44 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 44, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the…arrow_forwardIf a uniform distribution is defined over the interval from 6 to 10, then answer the followings: What is the mean of this uniform distribution? Show that the probability of any value between 6 and 10 is equal to 1.0 Find the probability of a value more than 7. Find the probability of a value between 7 and 9. The closing price of Schnur Sporting Goods Inc. common stock is uniformly distributed between $20 and $30 per share. What is the probability that the stock price will be: More than $27? Less than or equal to $24? The April rainfall in Flagstaff, Arizona, follows a uniform distribution between 0.5 and 3.00 inches. What is the mean amount of rainfall for the month? What is the probability of less than an inch of rain for the month? What is the probability of exactly 1.00 inch of rain? What is the probability of more than 1.50 inches of rain for the month? The best way to solve this problem is begin by creating a chart. Clearly mark the range, identifying the lower and upper…arrow_forward
- Problem 1: The mean hourly pay of an American Airlines flight attendant is normally distributed with a mean of 40 per hour and a standard deviation of 3.00 per hour. What is the probability that the hourly pay of a randomly selected flight attendant is: Between the mean and $45 per hour? More than $45 per hour? Less than $32 per hour? Problem 2: The mean of a normal probability distribution is 400 pounds. The standard deviation is 10 pounds. What is the area between 415 pounds and the mean of 400 pounds? What is the area between the mean and 395 pounds? What is the probability of randomly selecting a value less than 395 pounds? Problem 3: In New York State, the mean salary for high school teachers in 2022 was 81,410 with a standard deviation of 9,500. Only Alaska’s mean salary was higher. Assume New York’s state salaries follow a normal distribution. What percent of New York State high school teachers earn between 70,000 and 75,000? What percent of New York State high school…arrow_forwardPls help asaparrow_forwardSolve the following LP problem using the Extreme Point Theorem: Subject to: Maximize Z-6+4y 2+y≤8 2x + y ≤10 2,y20 Solve it using the graphical method. Guidelines for preparation for the teacher's questions: Understand the basics of Linear Programming (LP) 1. Know how to formulate an LP model. 2. Be able to identify decision variables, objective functions, and constraints. Be comfortable with graphical solutions 3. Know how to plot feasible regions and find extreme points. 4. Understand how constraints affect the solution space. Understand the Extreme Point Theorem 5. Know why solutions always occur at extreme points. 6. Be able to explain how optimization changes with different constraints. Think about real-world implications 7. Consider how removing or modifying constraints affects the solution. 8. Be prepared to explain why LP problems are used in business, economics, and operations research.arrow_forward
- ged the variance for group 1) Different groups of male stalk-eyed flies were raised on different diets: a high nutrient corn diet vs. a low nutrient cotton wool diet. Investigators wanted to see if diet quality influenced eye-stalk length. They obtained the following data: d Diet Sample Mean Eye-stalk Length Variance in Eye-stalk d size, n (mm) Length (mm²) Corn (group 1) 21 2.05 0.0558 Cotton (group 2) 24 1.54 0.0812 =205-1.54-05T a) Construct a 95% confidence interval for the difference in mean eye-stalk length between the two diets (e.g., use group 1 - group 2).arrow_forwardAn article in Business Week discussed the large spread between the federal funds rate and the average credit card rate. The table below is a frequency distribution of the credit card rate charged by the top 100 issuers. Credit Card Rates Credit Card Rate Frequency 18% -23% 19 17% -17.9% 16 16% -16.9% 31 15% -15.9% 26 14% -14.9% Copy Data 8 Step 1 of 2: Calculate the average credit card rate charged by the top 100 issuers based on the frequency distribution. Round your answer to two decimal places.arrow_forwardPlease could you check my answersarrow_forward
- Let Y₁, Y2,, Yy be random variables from an Exponential distribution with unknown mean 0. Let Ô be the maximum likelihood estimates for 0. The probability density function of y; is given by P(Yi; 0) = 0, yi≥ 0. The maximum likelihood estimate is given as follows: Select one: = n Σ19 1 Σ19 n-1 Σ19: n² Σ1arrow_forwardPlease could you help me answer parts d and e. Thanksarrow_forwardWhen fitting the model E[Y] = Bo+B1x1,i + B2x2; to a set of n = 25 observations, the following results were obtained using the general linear model notation: and 25 219 10232 551 XTX = 219 10232 3055 133899 133899 6725688, XTY 7361 337051 (XX)-- 0.1132 -0.0044 -0.00008 -0.0044 0.0027 -0.00004 -0.00008 -0.00004 0.00000129, Construct a multiple linear regression model Yin terms of the explanatory variables 1,i, x2,i- a) What is the value of the least squares estimate of the regression coefficient for 1,+? Give your answer correct to 3 decimal places. B1 b) Given that SSR = 5550, and SST=5784. Calculate the value of the MSg correct to 2 decimal places. c) What is the F statistics for this model correct to 2 decimal places?arrow_forward
- MATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th...StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C...StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage Learning
- Elementary Statistics: Picturing the World (7th E...StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. Freeman





