Modern Physics
3rd Edition
ISBN: 9781111794378
Author: Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher: Cengage Learning
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Chapter 2, Problem 5P
To determine
The expression for the frequency of orbital motion of a charge particle.
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Modern Physics
Ch. 2 - A particle is moving at a speed of less than c/2....Ch. 2 - Give a physical argument showing that it is...Ch. 2 - Prob. 3QCh. 2 - Prob. 4QCh. 2 - Prob. 5QCh. 2 - Prob. 6QCh. 2 - Prob. 8QCh. 2 - Prob. 9QCh. 2 - Calculate the momentum of a proton moving with a...Ch. 2 - Prob. 2P
Ch. 2 - Consider the relativistic form of Newtons second...Ch. 2 - A charged particle moves along a straight line in...Ch. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - A proton moves at a speed of 0.95c. Calculate its...Ch. 2 - An electron has a kinetic energy 5 times greater...Ch. 2 - Find the speed of a particle whose total energy is...Ch. 2 - A proton in a high-energy accelerator is given a...Ch. 2 - An electron has a speed of 0.75c. Find the speed...Ch. 2 - Protons in an accelerator at the Fermi National...Ch. 2 - How long will the Sun shine, Nellie? The Sun...Ch. 2 - Electrons in projection television sets are...Ch. 2 - Prob. 16PCh. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - Prob. 19PCh. 2 - Prob. 20PCh. 2 - An electron having kinetic energy K = 1.000 MeV...Ch. 2 - The K0 meson is an uncharged member of the...Ch. 2 - An unstable particle having a mass of 3.34 1027...Ch. 2 - As measured by observers in a reference frame S, a...Ch. 2 - An object having mass of 900 kg and traveling at a...Ch. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 29PCh. 2 - Prob. 30PCh. 2 - A particle of mass m moving along the x-axis with...Ch. 2 - Prob. 32PCh. 2 - Energy reaches the upper atmosphere of the Earth...
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- As measured by observers in a reference frame S, a particle having charge q moves with velocity v in a magnetic field B and an electric field E. The resulting force on the particle is then measured to be F = q(E + v × B). Another observer moves along with the charged particle and measures its charge to be q also but measures the electric field to be E′. If both observers are to measure the same force, F, show that E′ = E + v × B.arrow_forwardA spacecraft is launched from the surface of the Earth with a velocity of 0.600c at an angle of 50.0° above the horizontal, positive x-axis. Another spacecraft is moving past with a velocity of 0.700c in the negative x direction. Determine the magnitude and direction of the velocity of the first spacecraft as measured by the pilot of the second spacecraft.arrow_forwardGive a physical argument showing that it is impossible to accelerate an object of mass m to the speed of light, even with a continuous force acting on it.arrow_forward
- Consider the relativistic form of Newtons second law. Show that when F is parallel to v, F=m(1v2c2)3/2dvdt where m is the mass of an object and v is its speed.arrow_forwardCalculate the momentum of a proton moving with a speed of (a) 0.010c, (b) 0.50c, (c) 0.90c. (d) Convert the answers of (a)(c) to MeV/c.arrow_forwardOwen and Dina are at rest in frame S. which is moving at 0.600c with respect to frame S. They play a game of catch while Ed. at rest in frame S, watches the action (Fig. P39.91). Owen throws the ball to Dina at 0.800c (according to Owen), and their separation (measured in S') is equal to 1.80 1012 m. (a) According to Dina, how fast is the ball moving? (b) According to Dina, what time interval is required for the ball to reach her? According to Ed, (c) how far apart are Owen and Dina, (d) how fast is the ball moving, and (e) what time interval is required for the ball to reach Dina?arrow_forward
- An enemy spacecraft moves away from the Earth at a speed of v = 0.800c (Fig. P9.19). A galactic patrol spacecraft pursues at a speed of u = 0.900c relative to the Earth. Observers on the Earth measure the patrol craft to be overtaking the enemy craft at a relative speed of 0.100c. With what speed is the patrol craft overtaking the enemy craft as measured by the patrol crafts crew? Figure. P9.19arrow_forwardSuppose the primed and laboratory observers want to measure the length of a rod that rests on the ground horizontally in the space between the helicopter and the tower (Fig. 39.8B). To derive the length transformation L = L (Eq. 39.5), we had to assume that the positions of the two ends were determined simultaneously. What happens to the length transformation equation if both observers measure the end below the helicopter at one time t1 and the other end at a later time t2?arrow_forwardTwo powerless rockets are on a collision course. The rockets are moving with speeds of 0.800c and 0.600c and are initially 2.52 × 1012 m apart as measured by Liz, an Earth observer, as shown in Figure P1.34. Both rockets are 50.0 m in length as measured by Liz. (a) What are their respective proper lengths? (b) What is the length of each rocket as measured by an observer in the other rocket? (c) According to Liz, how long before the rockets collide? (d) According to rocket 1, how long before they collide? (e) According to rocket 2, how long before they collide? (f) If both rocket crews are capable of total evacuation within 90 min (their own time), will there be any casualties? Figure P1.34arrow_forward
- A clock on a moving spacecraft runs 1 s slower per day relative to an identical clock on Earth. What is the relative speed of the spacecraft? (Hint: For v/c << 1, note that γ ≈ 1 + v2/2c2.)arrow_forwardYou measure the volume of a cube at rest to be V0. You then measure the volume of the same cube as it passes you in a direction parallel to one side of the cube. The speed of the cube is 0.980c, so 5. Is the volume you measure close to (a) V0/25, (b) V0/5, (c) V0, (d) 5V0, or (e) 25V0?arrow_forwardAn atomic clock is placed in a jet airplane. The clock measures a time interval of 3600 s when the jet moves with a speed of 400 m/s. How much longer or shorter a time interval does an identical clock held by an observer on the ground measure? (Hint: For , γ ≈ 1 + v2/2c2.)arrow_forward
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Length contraction: the real explanation; Author: Fermilab;https://www.youtube.com/watch?v=-Poz_95_0RA;License: Standard YouTube License, CC-BY