
(a)
Interpretation:
The total number of electrons, valence electrons, group number, period and number of valence shell for oxygen should be determined.
Concept Introduction:
An atom is composed of three main sub-atomic particles; electrons, neutrons and protons. The
The distribution of electrons in an atom can be shown with the help of electronic configuration. The electronic configuration of an element represents the number of electrons in different energy levels of an element. The energy levels must be arranged in increasing order of their energy and can only accommodate a certain number of electrons as given:
(b)
Interpretation:
The total number of electrons, valence electrons, group number, period and number of valence shell for sodium should be determined.
Concept Introduction:
An atom is composed of three main sub-atomic particles; electrons, neutrons and protons. The atomic number of the elements represents the number of protons or electrons in a neutral atom. All known elements are arranged in a tabular form in increasing order of their atomic number that is called the periodic table.
The distribution of electrons in an atom can be shown with the help of electronic configuration. The electronic configuration of an element represents the number of electrons in different energy levels of an element. The energy levels must be arranged in increasing order of their energy and can only accommodate a certain number of electrons as given:
(c)
Interpretation:
The total number of electrons, valence electrons, group number, period and number of valence shell for phosphorus should be determined.
Concept Introduction:
An atom is composed of three main sub-atomic particles; electrons, neutrons and protons. The atomic number of the elements represents the number of protons or electrons in a neutral atom. All known elements are arranged in a tabular form in increasing order of their atomic number that is called the periodic table.
The distribution of electrons in an atom can be shown with the help of electronic configuration. The electronic configuration of an element represents the number of electrons in different energy levels of an element. The energy levels must be arranged in increasing order of their energy and can only accommodate a certain number of electrons as given:

Want to see the full answer?
Check out a sample textbook solution
Chapter 2 Solutions
General, Organic, and Biological Chemistry - 4th edition
- true or false, given that a 20.00 mL sample of NaOH took 24.15 mL of 0.141 M HCI to reach the endpoint in a titration, the concentration of the NaOH is 1.17 M.arrow_forwardin the bromothymol blue experiment, pKa was measured. A closely related compound has a Ka of 2.10 x 10-5. What is the pKa?a) 7.1b) 4.7c) 2.0arrow_forwardcalculate the equilibrium concentration of H2 given that K= 0.017 at a constant temperature for this reaction. The inital concentration of HBr is 0.050 M.2HBr(g) ↔ H2(g) + Br2(g)a) 4.48 x 10-2 M b) 5.17 x 10-3 Mc) 1.03 x 10-2 Md) 1.70 x 10-2 Marrow_forward
- true or falsegiven these two equilibria with their equilibrium constants:H2(g) + CI2(l) ↔ 2HCI(g) K= 0.006 CI2(l) ↔ CI2(g) K= 0.30The equilibrium contstant for the following reaction is 1.8H2(g) + CI2 ↔ 2HCI(g)arrow_forwardI2(g) + CI2(g) ↔ 2ICIK for this reaction is 81.9. Find the equilibrium concentration of I2 if the inital concentration of I2 and CI2 are 0.010 Marrow_forwardtrue or false,the equilibrium constant for this reaction is 0.50.PCI5(g) ↔ PCI3(g) + CI2(g)Based on the above, the equilibrium constant for the following reaction is 0.25.2PCI5(g) ↔. 2PCI3(g) + 2CI2(g)arrow_forward
- true or false, using the following equilibrium, if carbon dioxide is added the equilibrium will shift toward the productsC(s) + CO2(g) ↔ 2CO(g)arrow_forward2S2O2/3- (aq) + I2 (aq) ---> S4O2/6- (aq) +2I- (aq) Experiment I2 (M) S2O3- (M) Initital Rate (M/s) 1 0.01 0.01 0.0004 2 0.01 0.02 0.0004 3 0.02 0.01 0.0008 Calculate the overall order for this reaction using the table data a) 3b) 0c) 2d) 1arrow_forwardthe decomposition of N2O5 is the first order with a half-life of 1.98 minutes. If the inital concentration of N2O5 is 0.200 M, what is the concentration after 6 minutes?a) 0.612 Mb) 0.035 Mc) 0.024 Md) 0.100 Marrow_forward
- 20.00 mL of 0.150 M HCI is titrated with 0.075 M NaOH. What volume of NaOH is needed?a) 50 mLb) 20 mLc) 40 mLd) 26.66 mLarrow_forward20.00 mL of 0.150 M NaOH is titrated with 37.75 mL of HCI. What is the molarity of the HCI?a) 0.150 Mb) 0.079 Mc) 0.025 Md) 0.050 Marrow_forwardin the following reaction, the OH- acts as which of these?NO2- (aq) + H2O (l) ⇌ OH- (aq) + HNO2 (aq)a) not a weak acidb) basec) acidarrow_forward
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781285199023Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
- Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningIntroduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning





