
(a)
Interpretation:
To write the chemical formula of methane.
Concept introduction:
Methane is first member of Alkane family that has only 1 carbon atom (‘meth’ prefix used for 1 carbon).
General molecular formula for
Where n represents the number of carbon atoms.

Answer to Problem 55QAP
Chemical formula of methane is CH4.
Explanation of Solution
Methane is a member of Alkane family that has only 1 carbon atom and general formula for molecular formula of Alkane is:
Where n represents the number of carbon atoms.
Therefore,
Molecular formula of methane:
(b)
Interpretation:
To write the chemical formula of carbon tetraiodide.
Concept introduction:
Naming format for covalent binary compounds:
Prefixes are used as mono, di, tri, tetra, penta, hexa and so on for the number of each element present in a molecule. Generally, we don’t use mono prefix while writing the name of covalent compoundsas by convection if no prefix is used, then it means we have 1 atom of that respective element.

Answer to Problem 55QAP
Formula of carbon tetraiodide is CI4.
Explanation of Solution
Here we have:
Chemical name of molecule = Carbon tetraiodide
In this chemical compound:
Least electronegative atom = Carbon and its symbol is C.
Most electronegative atom = Iodine and its symbol is I.
Prefix used for least electronegative atom = “none” that means only 1 carbon atom.
Prefix used for most electronegative atom = “tetra” that means only 4 Iodine atoms.
Thus,
Molecular formula for carbon tetraiodide = CI4
(c)
Interpretation:
To write the chemical formula of hydrogen peroxide.
Concept introduction:
Hydrogen peroxide is also known as dihydrogen dioxide.
Naming format for covalent binary compounds:
Prefixes are used as mono, di, tri, tetra, penta, hexa and so on for the number of each element present in a molecule. Generally, we don’t use mono prefix while writing the name of covalent compounds as by convection if no prefix is used, then it means we have 1 atom of that respective element.

Answer to Problem 55QAP
Formula of hydrogen peroxide is H2 O2.
Explanation of Solution
Here we have:
Chemical name of molecule = Hydrogen peroxide
Its other name is dihydrogen dioxide.
In this chemical compound:
Least electronegative atom = Hydrogen and its symbol is H.
Most electronegative atom = Oxygen and its symbol is O.
Prefix used for least electronegative atom = “di” that means only 2 atoms.
Prefix used for most electronegative atom = “di” that means only 2 atoms.
Thus,
Molecular formula for dihydrogen dioxide = H2 O2.
(d)
Interpretation:
To write the chemical formula of nitrogen oxide.
Concept introduction:
Naming format for covalent binary compounds:
Prefixes are used as mono, di, tri, tetra, penta, hexa and so on for the number of each element present in a molecule. Generally, we don’t use mono prefix while writing the name of covalent compounds as by convection if no prefix is used, then it means we have 1 atom of that respective element.

Answer to Problem 55QAP
Formula of nitrogen oxide is NO.
Explanation of Solution
Here we have:
Chemical name of molecule = Nitrogen oxide
In this chemical compound:
Least electronegative atom = Nitrogen and its symbol is N.
Most electronegative atom = Oxygen and its symbol is O.
Prefix used for least electronegative atom = “none” that means only 1 nitrogen atom.
Prefix used for most electronegative atom = “none” that means only 1 oxygen atom.
Thus,
Molecular formula for nitrogen oxide = NO
(e)
Interpretation:
To write the chemical formula of silicon dioxide.
Concept introduction:
Naming format for covalent binary compounds:
Prefixes are used as mono, di, tri, tetra, penta, hexa and so on for the number of each element present in a molecule. Generally, we don’t use mono prefix while writing the name of covalent compounds as by convection if no prefix is used, then it means we have 1 atom of that respective element.

Answer to Problem 55QAP
Formula of silicondioxide is SiO2.
Explanation of Solution
Here we have:
Chemical name of molecule = Silicon dioxide
In this chemical compound:
Least electronegative atom = Silicon and its symbol is Si.
Most electronegative atom = Oxygen and its symbol is O.
Prefix used for least electronegative atom = “none” that means only 1 silicon atom.
Prefix used for most electronegative atom = “di” that means 2 oxygen atoms.
Thus,
Molecular formula for silicon dioxide = SiO2
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Chapter 2 Solutions
CHEMISTRY:PRIN.+REACTIONS-OWLV2 ACCESS
- Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. + Drawing Arrows CH3ONA, CH3OH heat : Br:O Na → H H Br Na + H H H H H :0: .H + Undo Reset Done Q CH3 Drag To Pan +arrow_forwardWhat is the reaction mechanism for this?arrow_forward20.19 Predict the structure of the major 1,2-addition product formed by reaction of one mole of Cl₂ with 3-methylenecyclohexene. Also predict the structure of the 1,4-addition product formed under these conditions. 20.20 Which of the two molecules shown do you expect to be the major product formed by 1,2-addition of HCI to cyclopentadiene? Explain. Cyclopentadiene + HC 3-Chlorocyclopentene (racemic) or 4-Chlorocyclopentene (racemic)arrow_forward
- 20.35 Propose structural formulas for compounds A and B and specify the configuration of compound B. EtO₂C 250°C C14H2004 CO₂Et 1. Oso, then NaHSO3 2. HIO4 C14H2006 A Barrow_forward20.21 Predict the major product formed by 1,4-addition of HCI to cyclopentadiene. 20.22 Draw structural formulas for the two constitutional isomers with the molecular for- mula C₂H,Br, formed by adding one mole of Br, to cyclopentadiene.arrow_forwardAdd substituents to draw the conformer below (sighting down the indicated bond), then rotate the back carbon to provide the conformation that will be capable of an E2 elimination. R/S stereochemistry is graded. + I I H CH3 Ph Досн Br OCH 3 Drawing Q H Atoms, Bonds and Rings Charges Tap a node to see suggestions. H H H H H Undo Reset Remove Done Rotatearrow_forward
- 20.17 Predict the structure of the major product formed by 1,2-addition of HBr to 3-methylenecyclohexene. 3-Methylenecyclohexene 20.18 Predict the major product formed by 1,4-addition of HBr to 3-methylenecyclohexene.arrow_forward+ Draw a vicinal alkyl bromide that would produce the following alkene in an E2 elimination. Use a dash or wedge bond to indicate stereochemistry on asymmetric centers, where applicable. Ignore any inorganic byproducts. Br Drawing Strong Base H Q Atoms, Bonds Charges and Rings Draw or tap a new bond to see suggestions. Remove Done 語 Reset Undo + Drag To Panarrow_forwardDraw a vicinal alkyl bromide that would produce the following alkene in an E2 elimination. Use a dash or wedge bond to indicate stereochemistry on asymmetric centers, where applicable. Ignore any inorganic byproducts. + Drawing Į Strong Base H Br Q Atoms, Bonds and Rings Charges Draw or tap a new bond to see suggestions. Undo Reset 謂 Remove Done Drag To Pan +arrow_forward
- World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning
