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(a)
Interpretation:
To write the molecular formula and condensed formula of given molecule:
Concept introduction:
Condensed formula: It is a way of writing the molecule where all the atoms are arranged in order as appear in structural formula but while writing condensed formula, bond lines are omitted. For example: Condensed formula of propane is CH3 CH2 CH3.
Molecular formula: It is the easiest way of representing the number of atoms of each element in a molecule.
While writing molecule formula,
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Answer to Problem 48QAP
Condensed formula: CH3 COOH
Molecular formula: C2 H4 O2
Explanation of Solution
Given structural formula-
In above structural formula, CH3 group is attached with acetic acid group through carbon atom. Hence, its condensed formula will be CH3 COOH.
In 1 molecule of CH3 COOH, there are 2 carbon atoms, 4 hydrogen atoms and 2 oxygen atoms. Therefore, its molecular formula is C2 H4 O2.
(b)
Interpretation:
To write the molecular formula and condensed formula of given molecule:
Concept introduction:
Condensed formula: It is a way of writing the molecule where all the atoms are arranged in order as appear in structural formula but while writing condensed formula, bond lines are omitted. For example: Condensed formula of propane is CH3 CH2 CH3.
Molecular formula: It is the easiest way of representing the number of atoms of each element in a molecule.
While writing molecule formula, symbol of each element is written with their respective number of atoms in a single molecule. And these numbers are written in subscript as:
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Answer to Problem 48QAP
Condensed formula: CH3 Cl
Molecular formula: CH3 Cl
Explanation of Solution
Given structural formula:
In above structural formula, CH3 group is attached with Chlorine group through carbon atom. Hence, its condensed formula will be CH3 Cl.
In 1 molecule of CH3 Cl, there are 1 carbon atom, 3 hydrogen atoms and 1 chlorine atom. Therefore, its molecular formula is CH3 Cl.
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Chapter 2 Solutions
CHEMISTRY:PRIN.+REACTIONS-OWLV2 ACCESS
- true or false The equilibrium constant for this reaction is 0.20. N2O4(g) ⇔ 2NO2(g) Based on the above, the equilibrium constant for the following reaction is 5. 4NO2(g) ⇔ 2N2O4(g)arrow_forwardtrue or false The equilibrium constant for this reaction is 0.20. N2O4(g) ⇔ 2NO2(g) Based on the above, the equilibrium constant for the following reaction is 0.4. 2N2O4(g) ⇔ 4NO2(g)arrow_forwardtrue or false Using the following equilibrium, if heat is added the equilibrium will shift toward the reactants. N2(g) + 3H2(g) ⇔ 2NH3(g) + heatarrow_forward
- True or False Using the following equilibrium, if heat is added the equilibrium will shift toward the products. N2O4(g) + heat ⇔ 2NO2(g)arrow_forwardtrue or false Using the following equilibrium, if solid carbon is added the equilibrium will shift toward the products. C(s) + CO2(g) ⇔ 2CO(g)arrow_forwardProvide the complete mechanism for the reaction below. You must include appropriate arrows,intermediates, and formal charges. Please also provide a reason to explain why the 1,4-adduct is preferred over the 1,3-adduct.arrow_forward
- Which of the following pairs are resonance structures of one another? I. III. || III IV + II. :0: n P !༠ IV. EN: Narrow_forwardPredict the major organic product(s) and byproducts (either organic or inorganic) for thefollowing reactions.arrow_forwardA 8.25 g sample of aluminum at 55°C released 2500 J of heat. The specific heat of aluminum is 0.900 J/g°C. The density of aluminum is 2.70 g/mL. Calculate the final temperature of the aluminum sample in °C.arrow_forward
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