Interpretation:
The structure for all the compounds with the molecular formula
Concept introduction:
Infrared spectroscopy is a simple, instrumental technique, which helps to determine the presence of various
It depends on the interactions of atoms or molecules with the
The molecules that have dipole moment are IR active and the molecules that do not have dipole moment are IR inactive.
The carbon–carbon double bond
The carbon–carbon triple bond
The alcohol or phenol
The ether
Degree of unsaturation is the calculation that determines the total number of rings and pi-bonds.
It is used in organic chemistry to draw chemical structures.
Mathematically, the degree of unsaturation is expressed as
Here,
Want to see the full answer?
Check out a sample textbook solutionChapter 2 Solutions
Organic Chemistry
- Draw the structures of the four primary (1°) amines with molecular formula C5H13N that contain a chain with 4 carbon atoms in the longest continuous carbon chain. You do not have to consider stereochemistry. You do not have to explicitly draw H atoms.arrow_forwardDraw the structure for a compound that meets this description (can be any structure that meets this description): C3H6O, with no IR absorption above 3000 cm^-1.arrow_forwardDraw the structure of the two tertiary (3°) amines with molecular formula C6H15N that contain a group with 3 carbon atoms in the largest group. You do not have to consider stereochemistry. You do not have to explicitly draw H atoms.arrow_forward
- a) which bond is present in alcohols but not alkanes? b) is this band strong or weak (in terms of spectra)? c) what is different about C=O and O-H bonds compared with C=C or C≡C bonds that show weaker signals?arrow_forwardIdentify whether the following pairs of structures are: (A) Same compound (B) Constitutional isomers (C) Cis-trans isomers (D) Not isomersarrow_forward10carrow_forward
- A compound, whose formula is C7H12, is known to have a six-membered ring. In its UV–vis spectrum, the longest-wavelength λmax appears at 191 nm. Draw four isomers that are consistent with these results.arrow_forwardDraw the structure of the one tertiary (3°) amine with molecular formula C5H13N that does not contain a 3-carbon chain. You do not have to consider stereochemistry. You do not have to explicitly draw H atomsarrow_forward1. An experimental technique called ¹3C-Nuclear Magnetic Resonance Spectroscopy allows chemists to tell how many different kinds of carbon there are in a molecule and whether carbons are primary (1°), secondary (2°), tertiary (3°), or quaternary (4°). Give dash (Kekule) structures (i.e., use lines for electron pair bonds) for the following compounds having a molecular formula C6H12. Also, on each structure, identify carbons as 1º, 2º, 3º, 4º; tell how many different kinds of C's there are; and designate which C's are equivalent. a) A compound having only single bonds and only secondary carbons. b) A compound having only single bonds and primary, secondary, and tertiary carbons. c) A compound having only single bonds and only primary, secondary, and quaternary carbons. d) A compound having only single bonds and primary, secondary, tertiary, and quaternary carbons.arrow_forward
- This is an isomer of C4H10O, and it’s not an alcohol. What could the structure be, and what are the degrees of unsaturation? Which peaks would correspond with which carbons?arrow_forwardIdentify whether the following pairs of structures are: (A) Same compound, (B) Constitutional isomers, (C) Cis-trans isomers or (D) Not isomersarrow_forwardNumbering the main chain of branched alkanes For each organic compound in the table below, enter the locant of the highlighted side chain. compound CH₁₂ CH3 - CH, | C - CH₁₂ | - CH2-CH- CH3 CH3 - locant of highlighted side chain ☐ CH3 | CH3 CH2 | CH₁₂ C-CH2-CH CH3 - CH - CH3 ㅁ CH₁₂ CH2 CH3 བos ད ་ CH3-CH2- - C CH3 - CH3 ☐ 00. Ararrow_forward
- Principles of Modern ChemistryChemistryISBN:9781305079113Author:David W. Oxtoby, H. Pat Gillis, Laurie J. ButlerPublisher:Cengage Learning