Chapter 2, Problem 4E

(a)

Summary Introduction

To calculate: The approximate mass of the E. coli cell that contains about $2.6\times \text{1}{0}^8$ ions.

Concept introduction: The mass of the molecule is denoted as the molecular mass. The molecular mass is calculated by the addition of atomic mass of atoms and by the division of number of atoms present in certain elements. It is known as the atomic mass unit (amu). The nucleic acids, lipids, carbohydrates and proteins are the major biochemical macromolecules. These are the building constituents of almost all living organisms.

(b)

Summary Introduction

To calculate: The approximate percentage of carbohydrate present in the E. coli cell mass.

Concept introduction: The mass of the molecule is denoted as the molecular mass. The molecular mass is calculated by the addition of atomic mass of atoms and by the division of number of atoms present in certain element. It is known as the atomic mass unit (amu). The nucleic acids, lipids, carbohydrates and proteins are the major biochemical macromolecules. These are the building constituents of almost all living organisms.

(c)

Summary Introduction

To calculate: The number of DNA molecule present in the E. coli cell.

Concept introduction: The mass of the molecule is denoted as the molecular mass. The molecular mass is calculated by the addition of atomic mass of atoms and by the division of number of atoms present in certain element. It is known as the atomic mass unit (amu). The nucleic acids, lipids, carbohydrates and proteins are the major biochemical macromolecules. These are the building constituents of almost all living organisms.