Organic Chemistry
12th Edition
ISBN: 9781118875766
Author: T. W. Graham Solomons, Craig B. Fryhle, Scott A. Snyder
Publisher: WILEY
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Textbook Question
Chapter 2, Problem 45P
True or false: For a molecule to be polar, the presence of polar bonds is necessary, but it is not alone a sufficient requirement.
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Chapter 2 Solutions
Organic Chemistry
Ch. 2 - Practice Problem 2.1
Propose structures for two...Ch. 2 - Prob. 2PPCh. 2 - Prob. 3PPCh. 2 - Prob. 4PPCh. 2 - Prob. 5PPCh. 2 - Practice Problem 2.6
Using a three-dimensional...Ch. 2 - Practice Problem 2.7
Trichloromethane (, also...Ch. 2 - Prob. 8PPCh. 2 - Prob. 9PPCh. 2 - Practice Problem 2.10
Write bond-line structural...
Ch. 2 - Practice Problem 2.11 Although we shall discuss...Ch. 2 - Practice Problem 2.12 Write bond-line structural...Ch. 2 - Prob. 13PPCh. 2 - Practice Problem 2.14
One way of naming ethers is...Ch. 2 - Practice Problem 2.15 Eugenol is the main...Ch. 2 - Practice Problem 2.16
One way of naming amines is...Ch. 2 - Practice Problem 2.17 Which amines in Practice...Ch. 2 - Prob. 18PPCh. 2 - Prob. 19PPCh. 2 - Practice Problem 2.20
Write bond-line formulas for...Ch. 2 - Practice Problem 2.21
Write bond-line formulas for...Ch. 2 - Practice Problem 2.22
Write bond-line formulas for...Ch. 2 - Prob. 23PPCh. 2 - Practice Problem 2.24 Write another resonance...Ch. 2 - Prob. 25PPCh. 2 - Practice Problem 2.26
Which compound would you...Ch. 2 - Practice Problem 2.27 Arrange the following...Ch. 2 - Prob. 28PPCh. 2 - Prob. 29PCh. 2 - Identify all of the functional groups in each of...Ch. 2 - 2.31 There are four alkyl bromides with the...Ch. 2 - Prob. 32PCh. 2 - Classify the following alcohols as primary,...Ch. 2 - 2.34 Classify the following amines as primary,...Ch. 2 - Prob. 35PCh. 2 - Identify all of the functional groups in Crixivan,...Ch. 2 - 2.37 Identify all of the functional groups in...Ch. 2 - 2.38 (a) Indicate the hydrophobic and hydrophilic...Ch. 2 - Hydrogen fluoride has a dipole moment of 1.83 D;...Ch. 2 - 2.40 Why does one expect the cis isomer of an...Ch. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - 2.44 Consider each of the following molecules in...Ch. 2 - True or false: For a molecule to be polar, the...Ch. 2 - 2.46 Which compound in each of the following...Ch. 2 - Prob. 47PCh. 2 - The IR spectrum of propanoic acid (Fig. 2.16)...Ch. 2 - Prob. 49PCh. 2 - Write structural formulas for four compounds with...Ch. 2 - There are four amides with the formula C3H7NO. (a)...Ch. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 54PCh. 2 - Prob. 55PCh. 2 - 2.56 Compound C is asymmetric, has molecular...Ch. 2 - 2.57 Examine the diagram showing an -helical...Ch. 2 - Prob. 1LGPCh. 2 - Prob. 2LGPCh. 2 - Prob. 3LGPCh. 2 - Consider the molecular formula C4H8O2. Predict...Ch. 2 - Consider the molecular formula C4H8O2. If any of...Ch. 2 - Prob. 6LGPCh. 2 - Consider the molecular formula.
7. Pick five...Ch. 2 - Prob. 8LGP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Is it possible for a molecule with polar bonds to be non-polar? Why or why not?arrow_forwardThe concept of valence-shell electron-pair repulsion (VSEPR) is presented in introductory organic chemistry as a way to predict molecular geometries. The idea be- hind VSEPR is that areas of electron density repel each other so that the geometry of bonds and/or lone pairs of electrons around any one atom places these areas as far apart as possible. For four areas of electron density, a tetrahedral geometry is predicted. For three areas of electron density, a trigonal planar geometry is predicted. Two areas of electron density lead to a linear geometry. VSEPR is simply a predictive tool, but in some cases, it gives an incorrect prediction. In these instances, additional insights into bonding are necessary, such as resonance. Interestingly, several important situations are critical to biochemistry where VSEPR breaks down. Two examples are shown here. :O: CH3 H,N H3N CH3 H :0: :0: Histidine The circled nitrogen atoms are predicted by VSEPR to be tetrahedral in geometry because each…arrow_forwardPlease fill in the blank ! In part B, the difference is that the molecules have more than one atom with two or more attached neighbors. As molecules become larger and more complex, VSEPR theory does not attempt to create names for the overall geometries that result. Instead, we continue to consider the geometry about one central atom at a time. By giving the arrangement about each such atom in the larger structure, we can generate enough information to develop an overall picture. Thus, in your report for part B, you should determine which atoms have more than one bound neighbor, then repeat the procedure for part A. When deciding whether the molecules in part B are polar or nonpolar, focus on the molecule as a whole, not the geometry about a single atom. If the molecule is polar, draw a dipole arrow on your sketch indicating polarity.arrow_forward
- 12. Which of the following molecules is/are polar? For polar molecules, indicate direction of their dipole moment.arrow_forwardSelect ALL of the following that can be used to explain the polarities of NO2 and SeCl42- (these molecules are mentioned in earlier questions). NO2 has a permanent dipole moment or a net dipole moment greater than zero whereas SeCl42- has no net or zero dipole moment. Both molecules are symmetrical and hence nonpolar Due to their respective shapes, in NO2 the bond dipole moments reinforce each other whereas in SeCl42- they cancel out each other. NO2 has no net dipole moment and SeCl42- has a net dipole moment greater than zero. NO2 is an unsymmetrical molecule whereas SeCl42- is a symmetrical ion.arrow_forward(a) How does a polar molecule differ from a nonpolar one? (b) Atoms X and Y have different electronegativities. Will the diatomic molecule X—Y necessarily be polar? Explain. (c) What factors affect the size of the dipole moment of a diatomic molecule?arrow_forward
- A student who missed this class needs to know how to predict the bond angles and shape of amolecule from looking at its bond-line representation. Write a concise but complete explanationfor this student.arrow_forwardUse the VSEPR model to predict the bond angles around each central atom in the following Lewis structures (benzene rings are frequently pictured as hexagons, without the letter for the carbon atom at each vertex). Note that the drawings do not necessarily depict the bond angles correctly.arrow_forwardThe structural formula for vitamin C is Give a molecular-level explanation why vitamin C is a water-soluble rather than a fat-soluble vitamin.arrow_forward
- In each of the following molecules, a central atom is surrounded by a total of three atoms or unshared electron pairs: SnCl2, BCl3, SO2. In which of these molecules would you expect the bond angle to be less than 120? Explain your reasoning.arrow_forwardDescribe the bond angles to be found in each of the following molecular structures: (a) trigonal planar, (b) tetrahedral, (c) octahedral, (d) linear.arrow_forwardDraw the Lewis structures for the following molecules. For each molecule, determine its (a) electronic geometry, (b) number of nonbonding domains on the central atom, and (c) polarity of the molecule. Remember, that molecules that have zero nonbonding domains on the central atom AND have all of the outer atoms the same are NONPOLAR. Generally, molecules with different outer atoms or with more than one nonbonding domain are POLAR. However, these may be NONPOLAR ONLY IF the dipoles cancel each other due to a symmetrical arrangement. CIF3 (a) electronic geometry: -Select-- (b) number of nonbonding domains on central atom: -Select-v (c) molecule polarity: -Select- SO2 .(a) electronic geometry: --Select- (b) number of nonbonding domains on central atom: -Select---V (c) molecule polarity: --Select--v SF5 (a) electronic geometry: [-Select- (b) number of nonbonding domains on central atom: --Select--- ♥ (c) molecule polarity: --Select-- v IFS (a) electronic geometry: -Select-- (b) number of…arrow_forward
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